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Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Formula

GoNet Energy Leaving given Radiosity and Irradiation Formula

GoHeat Transfer between Concentric Spheres Formula

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Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second). Check FAQs

q = \frac{([Stefan-BoltZ] \cdot A 1 \cdot (({T 1}^{4}) - ({T 2}^{4})))}{(\frac{1}{ε 1}) + ((\frac{A 1}{A 2}) \cdot ((\frac{1}{ε 2}) - 1))}

q - Heat Transfer?A₁ - Surface Area of Body 1?T₁ - Temperature of Surface 1?T₂ - Temperature of Surface 2?ε₁ - Emissivity of Body 1?A₂ - Surface Area of Body 2?ε₂ - Emissivity of Body 2?[Stefan-BoltZ] - Stefan-Boltzmann Constant?

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Example

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Here is how the Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces equation looks like with Values.

Here is how the Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces equation looks like with Units.

Here is how the Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces equation looks like.

547.3353 = \frac{(5.7E-8 \cdot 34.74 \cdot ((202^{4}) - (151^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74}{50}) \cdot ((\frac{1}{0.3}) - 1))}

547.3353W = \frac{(5.7E-8 \cdot 34.74m² \cdot (({202K}^{4}) - ({151K}^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74m²}{50m²}) \cdot ((\frac{1}{0.3}) - 1))}

547.3353 = \frac{(5.7E-8 \cdot 34.74 \cdot ((202^{4}) - (151^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74}{50}) \cdot ((\frac{1}{0.3}) - 1))}

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Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Solution

Follow our step by step solution on how to calculate Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

FIRST Step Consider the formula

q = \frac{([Stefan-BoltZ] \cdot A 1 \cdot (({T 1}^{4}) - ({T 2}^{4})))}{(\frac{1}{ε 1}) + ((\frac{A 1}{A 2}) \cdot ((\frac{1}{ε 2}) - 1))}

Next Step Substitute values of Variables

∴

q = \frac{([Stefan-BoltZ] \cdot 34.74m² \cdot (({202K}^{4}) - ({151K}^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74m²}{50m²}) \cdot ((\frac{1}{0.3}) - 1))}

Next Step Substitute values of Constants

∴

q = \frac{(5.7E-8 \cdot 34.74m² \cdot (({202K}^{4}) - ({151K}^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74m²}{50m²}) \cdot ((\frac{1}{0.3}) - 1))}

Next Step Prepare to Evaluate

∴

q = \frac{(5.7E-8 \cdot 34.74 \cdot ((202^{4}) - (151^{4})))}{(\frac{1}{0.4}) + ((\frac{34.74}{50}) \cdot ((\frac{1}{0.3}) - 1))}

Next Step Evaluate

∴

q = 547.335263755058W

LAST Step Rounding Answer

∴

q = 547.3353W

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Formula Elements

Variables

Constants

Heat Transfer

Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second).

Symbol: q

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Heat Transfer

Surface Area of Body 1

The Surface Area of Body 1 is the area of body 1 through which the radiation takes place.

Symbol: A₁

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Surface Area of Body 1

Temperature of Surface 1

Temperature of Surface 1 is the temperature of the 1st surface.

Symbol: T₁

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Temperature of Surface 1

Temperature of Surface 2

Temperature of Surface 2 is the temperature of the 2nd surface.

Symbol: T₂

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Surface 2

Emissivity of Body 1

The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.

Symbol: ε₁

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Emissivity of Body 1

Surface Area of Body 2

The Surface Area of Body 2 is the area of body 2 upon which the radiation takes place.

Symbol: A₂

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Surface Area of Body 2

Emissivity of Body 2

The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.

Symbol: ε₂

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Emissivity of Body 2

Stefan-Boltzmann Constant

Stefan-Boltzmann Constant relates the total energy radiated by a perfect black body to its temperature and is fundamental in understanding blackbody radiation and astrophysics.

Symbol: [Stefan-BoltZ]

Value: 5.670367E-8

Other Formulas to find Heat Transfer

Go Net Energy Leaving given Radiosity and Irradiation

q = A \cdot (J - G)

Go Heat Transfer between Concentric Spheres

q = \frac{A 1 \cdot [Stefan-BoltZ] \cdot (({T 1}^{4}) - ({T 2}^{4}))}{(\frac{1}{ε 1}) + (((\frac{1}{ε 2}) - 1) \cdot ({(\frac{r 1}{r 2})}^{2}))}

Other formulas in Radiation Heat Transfer category

Go Absorptivity given Reflectivity and Transmissivity

α = 1 - ρ - 𝜏

Go Area of Surface 1 given Area 2 and Radiation Shape Factor for Both Surfaces

A 1 = A 2 \cdot (\frac{F 21}{F 12})

How to Evaluate Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces evaluator uses Heat Transfer = (([Stefan-BoltZ]*Surface Area of Body 1*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))))/((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1))) to evaluate the Heat Transfer, The Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces formula is a function of emissivity and temperature of both surface, area of heat transfer. Heat Transfer is denoted by q symbol.

How to evaluate Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces using this online evaluator? To use this online evaluator for Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces, enter Surface Area of Body 1 (A₁), Temperature of Surface 1 (T₁), Temperature of Surface 2 (T₂), Emissivity of Body 1 (ε₁), Surface Area of Body 2 (A₂) & Emissivity of Body 2 (ε₂) and hit the calculate button.

FAQs on Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces

What is the formula to find Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

The formula of Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces is expressed as Heat Transfer = (([Stefan-BoltZ]*Surface Area of Body 1*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))))/((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1))). Here is an example- 547.3353 = (([Stefan-BoltZ]*34.74*((202^4)-(151^4))))/((1/0.4)+((34.74/50)*((1/0.3)-1))).

How to calculate Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

With Surface Area of Body 1 (A₁), Temperature of Surface 1 (T₁), Temperature of Surface 2 (T₂), Emissivity of Body 1 (ε₁), Surface Area of Body 2 (A₂) & Emissivity of Body 2 (ε₂) we can find Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces using the formula - Heat Transfer = (([Stefan-BoltZ]*Surface Area of Body 1*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))))/((1/Emissivity of Body 1)+((Surface Area of Body 1/Surface Area of Body 2)*((1/Emissivity of Body 2)-1))). This formula also uses Stefan-Boltzmann Constant .

What are the other ways to Calculate Heat Transfer?

Here are the different ways to Calculate Heat Transfer-

Heat Transfer=Area*(Radiosity-Irradiation)
Heat Transfer=(Surface Area of Body 1*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(((1/Emissivity of Body 2)-1)*((Radius of Smaller Sphere/Radius of Larger Sphere)^2)))
Heat Transfer=Surface Area of Body 1*Emissivity of Body 1*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))

Can the Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces be negative?

Yes, the Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces, measured in Power can be negative.

Which unit is used to measure Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces can be measured.

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Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Formula

​GoNet Energy Leaving given Radiosity and Irradiation Formula

​GoHeat Transfer between Concentric Spheres Formula

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Example

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Solution

Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces Formula Elements

Other Formulas to find Heat Transfer

Other formulas in Radiation Heat Transfer category

How to Evaluate Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces?

FAQs on Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces

Variable Name

GoNet Energy Leaving given Radiosity and Irradiation Formula

GoHeat Transfer between Concentric Spheres Formula