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Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second). Check FAQs
q=A[Stefan-BoltZ]((T14)-(T24))(1ε1)+(1ε2)-1
q - Heat Transfer?A - Area?T1 - Temperature of Surface 1?T2 - Temperature of Surface 2?ε1 - Emissivity of Body 1?ε2 - Emissivity of Body 2?[Stefan-BoltZ] - Stefan-Boltzmann Constant?

Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces Example

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Here is how the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces equation looks like with Values.

Here is how the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces equation looks like with Units.

Here is how the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces equation looks like.

675.7228Edit=50.3Edit5.7E-8((202Edit4)-(151Edit4))(10.4Edit)+(10.3Edit)-1
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Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces Solution

Follow our step by step solution on how to calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?

FIRST Step Consider the formula
q=A[Stefan-BoltZ]((T14)-(T24))(1ε1)+(1ε2)-1
Next Step Substitute values of Variables
q=50.3[Stefan-BoltZ]((202K4)-(151K4))(10.4)+(10.3)-1
Next Step Substitute values of Constants
q=50.35.7E-8((202K4)-(151K4))(10.4)+(10.3)-1
Next Step Prepare to Evaluate
q=50.35.7E-8((2024)-(1514))(10.4)+(10.3)-1
Next Step Evaluate
q=675.722755500347W
LAST Step Rounding Answer
q=675.7228W

Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces Formula Elements

Variables
Constants
Heat Transfer
Heat Transfer is the amount of heat that is transferred per unit of time in some material, usually measured in watts (joules per second).
Symbol: q
Measurement: PowerUnit: W
Note: Value can be positive or negative.
Area
The area is the amount of two-dimensional space taken up by an object.
Symbol: A
Measurement: AreaUnit:
Note: Value should be greater than 0.
Temperature of Surface 1
Temperature of Surface 1 is the temperature of the 1st surface.
Symbol: T1
Measurement: TemperatureUnit: K
Note: Value should be greater than 0.
Temperature of Surface 2
Temperature of Surface 2 is the temperature of the 2nd surface.
Symbol: T2
Measurement: TemperatureUnit: K
Note: Value can be positive or negative.
Emissivity of Body 1
The Emissivity of Body 1 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Symbol: ε1
Measurement: NAUnit: Unitless
Note: Value should be between 0 to 1.
Emissivity of Body 2
The Emissivity of Body 2 is the ratio of the energy radiated from a body's surface to that radiated from a perfect emitter.
Symbol: ε2
Measurement: NAUnit: Unitless
Note: Value should be between 0 to 1.
Stefan-Boltzmann Constant
Stefan-Boltzmann Constant relates the total energy radiated by a perfect black body to its temperature and is fundamental in understanding blackbody radiation and astrophysics.
Symbol: [Stefan-BoltZ]
Value: 5.670367E-8

Other Formulas to find Heat Transfer

​Go Net Energy Leaving given Radiosity and Irradiation
q=A(J-G)
​Go Heat Transfer between Concentric Spheres
q=A1[Stefan-BoltZ]((T14)-(T24))(1ε1)+(((1ε2)-1)((r1r2)2))
​Go Heat Transfer between Small Convex Object in Large Enclosure
q=A1ε1[Stefan-BoltZ]((T14)-(T24))
​Go Heat Transfer between Two Long Concentric Cylinder given Temp, Emissivity and Area of Both Surfaces
q=([Stefan-BoltZ]A1((T14)-(T24)))(1ε1)+((A1A2)((1ε2)-1))

Other formulas in Radiation Heat Transfer category

​Go Absorptivity given Reflectivity and Transmissivity
α=1-ρ-𝜏
​Go Area of Surface 1 given Area 2 and Radiation Shape Factor for Both Surfaces
A1=A2(F21F12)
​Go Area of Surface 2 given Area 1 and Radiation Shape Factor for Both Surfaces
A2=A1(F12F21)
​Go Emissive Power of Blackbody
Eb=[Stefan-BoltZ](T4)

How to Evaluate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?

Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces evaluator uses Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1) to evaluate the Heat Transfer, The Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces formula is defined as the function of area of heat transfer, temperature of both the bodies, emissivity of both the bodies. Heat Transfer is denoted by q symbol.

How to evaluate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces using this online evaluator? To use this online evaluator for Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces, enter Area (A), Temperature of Surface 1 (T1), Temperature of Surface 2 (T2), Emissivity of Body 1 1) & Emissivity of Body 2 2) and hit the calculate button.

FAQs on Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces

What is the formula to find Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?
The formula of Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces is expressed as Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1). Here is an example- 675.7228 = (50.3*[Stefan-BoltZ]*((202^4)-(151^4)))/((1/0.4)+(1/0.3)-1).
How to calculate Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?
With Area (A), Temperature of Surface 1 (T1), Temperature of Surface 2 (T2), Emissivity of Body 1 1) & Emissivity of Body 2 2) we can find Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces using the formula - Heat Transfer = (Area*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(1/Emissivity of Body 2)-1). This formula also uses Stefan-Boltzmann Constant .
What are the other ways to Calculate Heat Transfer?
Here are the different ways to Calculate Heat Transfer-
  • Heat Transfer=Area*(Radiosity-Irradiation)OpenImg
  • Heat Transfer=(Surface Area of Body 1*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4)))/((1/Emissivity of Body 1)+(((1/Emissivity of Body 2)-1)*((Radius of Smaller Sphere/Radius of Larger Sphere)^2)))OpenImg
  • Heat Transfer=Surface Area of Body 1*Emissivity of Body 1*[Stefan-BoltZ]*((Temperature of Surface 1^4)-(Temperature of Surface 2^4))OpenImg
Can the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces be negative?
Yes, the Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces, measured in Power can be negative.
Which unit is used to measure Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces?
Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Heat Transfer between Two Infinite Parallel Planes given Temp and Emissivity of Both Surfaces can be measured.
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