Head over Jet Hole given Force exerted on Tank due to Jet Formula

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Impulse height is the distance between the lowest and highest points of a person/ shape/ object standing upright. Check FAQs
h=0.5F(Cv2)γfAJet
h - Impulse Height?F - Force of Fluid?Cv - Coefficient of Velocity?γf - Specific Weight of Liquid?AJet - Cross Sectional Area of Jet?

Head over Jet Hole given Force exerted on Tank due to Jet Example

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Here is how the Head over Jet Hole given Force exerted on Tank due to Jet equation looks like with Values.

Here is how the Head over Jet Hole given Force exerted on Tank due to Jet equation looks like with Units.

Here is how the Head over Jet Hole given Force exerted on Tank due to Jet equation looks like.

12.0436Edit=0.5240Edit(0.92Edit2)9.81Edit1.2Edit
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Head over Jet Hole given Force exerted on Tank due to Jet Solution

Follow our step by step solution on how to calculate Head over Jet Hole given Force exerted on Tank due to Jet?

FIRST Step Consider the formula
h=0.5F(Cv2)γfAJet
Next Step Substitute values of Variables
h=0.5240N(0.922)9.81kN/m³1.2
Next Step Prepare to Evaluate
h=0.5240(0.922)9.811.2
Next Step Evaluate
h=12.0435726824794m
LAST Step Rounding Answer
h=12.0436m

Head over Jet Hole given Force exerted on Tank due to Jet Formula Elements

Variables
Impulse Height
Impulse height is the distance between the lowest and highest points of a person/ shape/ object standing upright.
Symbol: h
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Force of Fluid
Force of Fluid is the force resulting from liquid pressure acting over an area.
Symbol: F
Measurement: ForceUnit: N
Note: Value should be greater than 0.
Coefficient of Velocity
The Coefficient of Velocity is the ratio of actual velocity to theoretical velocity.
Symbol: Cv
Measurement: NAUnit: Unitless
Note: Value should be greater than 0.
Specific Weight of Liquid
The Specific Weight of Liquid refers to the weight per unit volume of that substance.
Symbol: γf
Measurement: Specific WeightUnit: kN/m³
Note: Value should be greater than 0.
Cross Sectional Area of Jet
Cross Sectional Area of Jet is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.
Symbol: AJet
Measurement: AreaUnit:
Note: Value should be greater than 0.

Other formulas in Jet Propulsion of Orifice Tank category

​Go Force exerted on Tank due to Jet
F=γfAJetv2[g]
​Go Area of Jet given Force exerted on Tank due to Jet
AJet=Fγfv2[g]
​Go Actual Velocity given Force exerted on Tank due to Jet
v=F[g]γfAJet
​Go Specific Weight of Liquid given Force exerted on Tank due to Jet
γf=(F[g]AJet(v)2)

How to Evaluate Head over Jet Hole given Force exerted on Tank due to Jet?

Head over Jet Hole given Force exerted on Tank due to Jet evaluator uses Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet) to evaluate the Impulse Height, The Head over Jet Hole given Force exerted on Tank due to Jet is defined as the force exerted on the tank due to the jet, typically measured as the difference in fluid level between the tank and the jet hole. Impulse Height is denoted by h symbol.

How to evaluate Head over Jet Hole given Force exerted on Tank due to Jet using this online evaluator? To use this online evaluator for Head over Jet Hole given Force exerted on Tank due to Jet, enter Force of Fluid (F), Coefficient of Velocity (Cv), Specific Weight of Liquid f) & Cross Sectional Area of Jet (AJet) and hit the calculate button.

FAQs on Head over Jet Hole given Force exerted on Tank due to Jet

What is the formula to find Head over Jet Hole given Force exerted on Tank due to Jet?
The formula of Head over Jet Hole given Force exerted on Tank due to Jet is expressed as Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet). Here is an example- 12.04357 = (0.5*240)/((0.92^2)*9810*1.2).
How to calculate Head over Jet Hole given Force exerted on Tank due to Jet?
With Force of Fluid (F), Coefficient of Velocity (Cv), Specific Weight of Liquid f) & Cross Sectional Area of Jet (AJet) we can find Head over Jet Hole given Force exerted on Tank due to Jet using the formula - Impulse Height = (0.5*Force of Fluid)/((Coefficient of Velocity^2)*Specific Weight of Liquid*Cross Sectional Area of Jet).
Can the Head over Jet Hole given Force exerted on Tank due to Jet be negative?
No, the Head over Jet Hole given Force exerted on Tank due to Jet, measured in Length cannot be negative.
Which unit is used to measure Head over Jet Hole given Force exerted on Tank due to Jet?
Head over Jet Hole given Force exerted on Tank due to Jet is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Head over Jet Hole given Force exerted on Tank due to Jet can be measured.
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