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Force Required to Lower Load by Screw Jack given Weight of Load Formula

GoForce Required to Lower Load by Screw Jack given weight of load and Limiting angle Formula

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Force Required is any interaction that, when unopposed, will change the motion of an object. In other words, a force can cause an object with mass to change its velocity. Check FAQs

F = W l \cdot \frac{μ f \cdot \cos (ψ) - \sin (ψ)}{\cos (ψ) + μ f \cdot \sin (ψ)}

F - Force Required?W_l - Load?μ_f - Coefficient of Friction?ψ - Helix Angle?

Force Required to Lower Load by Screw Jack given Weight of Load Example

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Here is how the Force Required to Lower Load by Screw Jack given Weight of Load equation looks like with Values.

Here is how the Force Required to Lower Load by Screw Jack given Weight of Load equation looks like with Units.

Here is how the Force Required to Lower Load by Screw Jack given Weight of Load equation looks like.

-2.9619 = 53 \cdot \frac{0.4 \cdot \cos (25) - \sin (25)}{\cos (25) + 0.4 \cdot \sin (25)}

-2.9619N = 53N \cdot \frac{0.4 \cdot \cos (25°) - \sin (25°)}{\cos (25°) + 0.4 \cdot \sin (25°)}

-2.9619 = 53 \cdot \frac{0.4 \cdot \cos (25) - \sin (25)}{\cos (25) + 0.4 \cdot \sin (25)}

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Force Required to Lower Load by Screw Jack given Weight of Load Solution

Follow our step by step solution on how to calculate Force Required to Lower Load by Screw Jack given Weight of Load?

FIRST Step Consider the formula

F = W l \cdot \frac{μ f \cdot \cos (ψ) - \sin (ψ)}{\cos (ψ) + μ f \cdot \sin (ψ)}

Next Step Substitute values of Variables

∴

F = 53N \cdot \frac{0.4 \cdot \cos (25°) - \sin (25°)}{\cos (25°) + 0.4 \cdot \sin (25°)}

Next Step Convert Units

∴

F = 53N \cdot \frac{0.4 \cdot \cos (0.4363rad) - \sin (0.4363rad)}{\cos (0.4363rad) + 0.4 \cdot \sin (0.4363rad)}

Next Step Prepare to Evaluate

∴

F = 53 \cdot \frac{0.4 \cdot \cos (0.4363) - \sin (0.4363)}{\cos (0.4363) + 0.4 \cdot \sin (0.4363)}

Next Step Evaluate

∴

F = -2.96185214685012N

LAST Step Rounding Answer

∴

F = -2.9619N

Force Required to Lower Load by Screw Jack given Weight of Load Formula Elements

Variables

Functions

Force Required

Force Required is any interaction that, when unopposed, will change the motion of an object. In other words, a force can cause an object with mass to change its velocity.

Symbol: F

Measurement: ForceUnit: N

Note: Value can be positive or negative.

Formulas to find Force Required

Load

Load is the weight of body lifted by screw jack.

Symbol: W_l

Measurement: ForceUnit: N

Note: Value should be greater than 0.

Formulas to find Load

Coefficient of Friction

Coefficient of Friction(μ) is the ratio defining the force that resists the motion of one body in relation to another body in contact with it.

Symbol: μ_f

Measurement: NAUnit: Unitless

Note: Value should be less than 1.

Formulas to find Coefficient of Friction

Helix Angle

Helix Angle is the angle between any helix and an axial line on its right, circular cylinder, or cone.

Symbol: ψ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Helix Angle

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

Other Formulas to find Force Required

Go Force Required to Lower Load by Screw Jack given weight of load and Limiting angle

F = W l \cdot \tan (Φ - ψ)

Other formulas in Screw Jack category

Go Efficiency of Screw Jack when Screw Friction as well as Collar Friction Considered

η = \frac{W \cdot \tan (ψ) \cdot d}{W l \cdot \tan (ψ + Φ) \cdot d + μ c \cdot W l \cdot R c}

Go Efficiency of Screw Jack when only Screw Friction is Considered

η = \frac{\tan (ψ)}{\tan (ψ + Φ)}

Go Ideal Effort to Raise Load by Screw Jack

P o = W l \cdot \tan (ψ)

Go Maximum Efficiency of Screw Jack

η = \frac{1 - \sin (Φ)}{1 + \sin (Φ)}

How to Evaluate Force Required to Lower Load by Screw Jack given Weight of Load?

Force Required to Lower Load by Screw Jack given Weight of Load evaluator uses Force Required = Load*(Coefficient of Friction*cos(Helix Angle)-sin(Helix Angle))/(cos(Helix Angle)+Coefficient of Friction*sin(Helix Angle)) to evaluate the Force Required, Force required to Lower Load by Screw Jack given Weight of Load is any interaction that, when unopposed, will change the motion of an object. Force Required is denoted by F symbol.

How to evaluate Force Required to Lower Load by Screw Jack given Weight of Load using this online evaluator? To use this online evaluator for Force Required to Lower Load by Screw Jack given Weight of Load, enter Load (W_l), Coefficient of Friction (μ_f) & Helix Angle (ψ) and hit the calculate button.

FAQs on Force Required to Lower Load by Screw Jack given Weight of Load

What is the formula to find Force Required to Lower Load by Screw Jack given Weight of Load?

The formula of Force Required to Lower Load by Screw Jack given Weight of Load is expressed as Force Required = Load*(Coefficient of Friction*cos(Helix Angle)-sin(Helix Angle))/(cos(Helix Angle)+Coefficient of Friction*sin(Helix Angle)). Here is an example- -2.961852 = 53*(0.4*cos(0.4363323129985)-sin(0.4363323129985))/(cos(0.4363323129985)+0.4*sin(0.4363323129985)).

How to calculate Force Required to Lower Load by Screw Jack given Weight of Load?

With Load (W_l), Coefficient of Friction (μ_f) & Helix Angle (ψ) we can find Force Required to Lower Load by Screw Jack given Weight of Load using the formula - Force Required = Load*(Coefficient of Friction*cos(Helix Angle)-sin(Helix Angle))/(cos(Helix Angle)+Coefficient of Friction*sin(Helix Angle)). This formula also uses Sine (sin), Cosine (cos) function(s).

What are the other ways to Calculate Force Required?

Here are the different ways to Calculate Force Required-

Force Required=Load*tan(Limiting Angle of Friction-Helix Angle)

Can the Force Required to Lower Load by Screw Jack given Weight of Load be negative?

Yes, the Force Required to Lower Load by Screw Jack given Weight of Load, measured in Force can be negative.

Which unit is used to measure Force Required to Lower Load by Screw Jack given Weight of Load?

Force Required to Lower Load by Screw Jack given Weight of Load is usually measured using the Newton[N] for Force. Exanewton[N], Meganewton[N], Kilonewton[N] are the few other units in which Force Required to Lower Load by Screw Jack given Weight of Load can be measured.

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