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Final Temperature using Integrated Form of Clausius-Clapeyron Equation Formula

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The Final temperature is the temperature at which measurements are made in final state. Check FAQs

T f = \frac{1}{(- \frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T i})}

T_f - Final Temperature?P_f - Final Pressure of System?P_i - Initial Pressure of System?LH - Latent Heat?T_i - Initial Temperature?[R] - Universal gas constant?

Final Temperature using Integrated Form of Clausius-Clapeyron Equation Example

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Here is how the Final Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like with Values.

Here is how the Final Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like with Units.

Here is how the Final Temperature using Integrated Form of Clausius-Clapeyron Equation equation looks like.

699.9981 = \frac{1}{(- \frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{600})}

699.9981K = \frac{1}{(- \frac{\ln (\frac{133.07Pa}{65Pa}) \cdot 8.3145}{25020.7J}) + (\frac{1}{600K})}

699.9981 = \frac{1}{(- \frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{600})}

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Final Temperature using Integrated Form of Clausius-Clapeyron Equation Solution

Follow our step by step solution on how to calculate Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

FIRST Step Consider the formula

T f = \frac{1}{(- \frac{\ln (\frac{P f}{P i}) \cdot [R]}{LH}) + (\frac{1}{T i})}

Next Step Substitute values of Variables

∴

T f = \frac{1}{(- \frac{\ln (\frac{133.07Pa}{65Pa}) \cdot [R]}{25020.7J}) + (\frac{1}{600K})}

Next Step Substitute values of Constants

∴

T f = \frac{1}{(- \frac{\ln (\frac{133.07Pa}{65Pa}) \cdot 8.3145}{25020.7J}) + (\frac{1}{600K})}

Next Step Prepare to Evaluate

∴

T f = \frac{1}{(- \frac{\ln (\frac{133.07}{65}) \cdot 8.3145}{25020.7}) + (\frac{1}{600})}

Next Step Evaluate

∴

T f = 699.998109485234K

LAST Step Rounding Answer

∴

T f = 699.9981K

Final Temperature using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Variables

Constants

Functions

Final Temperature

The Final temperature is the temperature at which measurements are made in final state.

Symbol: T_f

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Final Temperature

Final Pressure of System

Final Pressure of System is the total final pressure exerted by the molecules inside the system.

Symbol: P_f

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Final Pressure of System

Initial Pressure of System

Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.

Symbol: P_i

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Initial Pressure of System

Latent Heat

Latent Heat is the heat that increases the specific humidity without a change in temperature.

Symbol: LH

Measurement: EnergyUnit: J

Note: Value can be positive or negative.

Formulas to find Latent Heat

Initial Temperature

The Initial temperature is defined as the measure of heat under initial state or conditions.

Symbol: T_i

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Initial Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Clausius Clapeyron Equation category

Go August Roche Magnus Formula

e s = 6.1094 \cdot \exp (\frac{17.625 \cdot T}{T + 243.04})

Go Boiling Point given Enthalpy using Trouton's Rule

bp = \frac{H}{10.5 \cdot [R]}

Go Boiling Point using Trouton's Rule given Latent Heat

bp = \frac{LH}{10.5 \cdot [R]}

Go Boiling Point using Trouton's Rule given Specific Latent Heat

bp = \frac{L \cdot MW}{10.5 \cdot [R]}

How to Evaluate Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

Final Temperature using Integrated Form of Clausius-Clapeyron Equation evaluator uses Final Temperature = 1/((-(ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Initial Temperature)) to evaluate the Final Temperature, The Final Temperature using integrated form of Clausius-Clapeyron Equation is the final state temperature of the system. Final Temperature is denoted by T_f symbol.

How to evaluate Final Temperature using Integrated Form of Clausius-Clapeyron Equation using this online evaluator? To use this online evaluator for Final Temperature using Integrated Form of Clausius-Clapeyron Equation, enter Final Pressure of System (P_f), Initial Pressure of System (P_i), Latent Heat (LH) & Initial Temperature (T_i) and hit the calculate button.

FAQs on Final Temperature using Integrated Form of Clausius-Clapeyron Equation

What is the formula to find Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

The formula of Final Temperature using Integrated Form of Clausius-Clapeyron Equation is expressed as Final Temperature = 1/((-(ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Initial Temperature)). Here is an example- 479.5003 = 1/((-(ln(133.07/65)*[R])/25020.7)+(1/600)).

How to calculate Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

With Final Pressure of System (P_f), Initial Pressure of System (P_i), Latent Heat (LH) & Initial Temperature (T_i) we can find Final Temperature using Integrated Form of Clausius-Clapeyron Equation using the formula - Final Temperature = 1/((-(ln(Final Pressure of System/Initial Pressure of System)*[R])/Latent Heat)+(1/Initial Temperature)). This formula also uses Universal gas constant and Natural Logarithm (ln) function(s).

Can the Final Temperature using Integrated Form of Clausius-Clapeyron Equation be negative?

No, the Final Temperature using Integrated Form of Clausius-Clapeyron Equation, measured in Temperature cannot be negative.

Which unit is used to measure Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

Final Temperature using Integrated Form of Clausius-Clapeyron Equation is usually measured using the Kelvin[K] for Temperature. Celsius[K], Fahrenheit[K], Rankine[K] are the few other units in which Final Temperature using Integrated Form of Clausius-Clapeyron Equation can be measured.

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Final Temperature using Integrated Form of Clausius-Clapeyron Equation Formula

Final Temperature using Integrated Form of Clausius-Clapeyron Equation Example

Final Temperature using Integrated Form of Clausius-Clapeyron Equation Solution

Final Temperature using Integrated Form of Clausius-Clapeyron Equation Formula Elements

Other formulas in Clausius Clapeyron Equation category

How to Evaluate Final Temperature using Integrated Form of Clausius-Clapeyron Equation?

FAQs on Final Temperature using Integrated Form of Clausius-Clapeyron Equation

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