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Fault Impedance using A-Phase Voltage(LGF) Formula

GoFault Impedance given Sequence Voltages(LGF) Formula

GoFault Impedance given A-Phase EMF and Sequence Impedances(LGF) Formula

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Fault Impedance LG is a measure of the resistance and reactance in an electrical circuit that is used to calculate the fault current that flows through the circuit in the event of a fault. Check FAQs

Z f(lg) = \frac{V a(lg)}{I a(lg)}

Z_f(lg) - Fault Impedance LG?V_a(lg) - A Phase Voltage LG?I_a(lg) - A-Phase Current LG?

Fault Impedance using A-Phase Voltage(LGF) Example

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Here is how the Fault Impedance using A-Phase Voltage(LGF) equation looks like with Values.

Here is how the Fault Impedance using A-Phase Voltage(LGF) equation looks like with Units.

Here is how the Fault Impedance using A-Phase Voltage(LGF) equation looks like.

5.6103 = \frac{11.95}{2.13}

5.6103Ω = \frac{11.95V}{2.13A}

5.6103 = \frac{11.95}{2.13}

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Fault Impedance using A-Phase Voltage(LGF) Solution

Follow our step by step solution on how to calculate Fault Impedance using A-Phase Voltage(LGF)?

FIRST Step Consider the formula

Z f(lg) = \frac{V a(lg)}{I a(lg)}

Next Step Substitute values of Variables

∴

Z f(lg) = \frac{11.95V}{2.13A}

Next Step Prepare to Evaluate

∴

Z f(lg) = \frac{11.95}{2.13}

Next Step Evaluate

∴

Z f(lg) = 5.61032863849765Ω

LAST Step Rounding Answer

∴

Z f(lg) = 5.6103Ω

Fault Impedance using A-Phase Voltage(LGF) Formula Elements

Variables

Fault Impedance LG

Fault Impedance LG is a measure of the resistance and reactance in an electrical circuit that is used to calculate the fault current that flows through the circuit in the event of a fault.

Symbol: Z_f(lg)

Measurement: Electric ResistanceUnit: Ω

Note: Value should be greater than 0.

Formulas to find Fault Impedance LG

A Phase Voltage LG

A phase voltage LG is the voltage of a-phase in open conductor fault.

Symbol: V_a(lg)

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find A Phase Voltage LG

A-Phase Current LG

A-phase Current LG is the current that flows into the a-phase in open conductor fault.

Symbol: I_a(lg)

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find A-Phase Current LG

Other Formulas to find Fault Impedance LG

Go Fault Impedance given Sequence Voltages(LGF)

Z f(lg) = \frac{V 0(lg) + V 1(lg) + V 2(lg)}{3 \cdot I 1(lg)}

Go Fault Impedance given A-Phase EMF and Sequence Impedances(LGF)

Z f(lg) = \frac{1}{3} \cdot ((\frac{E a(lg)}{I 1(lg)}) - (Z 0(lg) + Z 1(lg) + Z 2(lg)))

Go Fault Impedance using Fault Voltage and A-Phase Current(LGF)

Z f(lg) = \frac{V f(lg)}{I a(lg)} - (\frac{1}{3} \cdot (Z 0(lg) + Z 1(lg) + Z 2(lg)))

Other formulas in Impedance category

Go Zero Sequence Impedance for L-G-F

Z 0(lg) = (- 1) \cdot \frac{V 0(lg)}{I 0(lg)}

Go Positive Sequence Impedance for L-G-F

Z 1(lg) = \frac{E 1(lg) - V 1(lg)}{I 1(lg)}

Go Positive Sequence Impedance using A-Phase EMF (LGF)

Z 1(lg) = (\frac{E 1(lg)}{I 1(lg)}) - (3 \cdot Z f(lg)) - Z 0(lg) - Z 2(lg)

Go Zero Sequence Impedance using A-Phase EMF (LGF)

Z 0(lg) = (\frac{E 1(lg)}{I 0(lg)}) - (3 \cdot Z f(lg)) - Z 1(lg) - Z 2(lg)

How to Evaluate Fault Impedance using A-Phase Voltage(LGF)?

Fault Impedance using A-Phase Voltage(LGF) evaluator uses Fault Impedance LG = A Phase Voltage LG/A-Phase Current LG to evaluate the Fault Impedance LG, The Fault Impedance using a-phase voltage(LGF) formula is defined as the impedance which is connected to the earth. Fault Impedance LG is denoted by Z_f(lg) symbol.

How to evaluate Fault Impedance using A-Phase Voltage(LGF) using this online evaluator? To use this online evaluator for Fault Impedance using A-Phase Voltage(LGF), enter A Phase Voltage LG (V_a(lg)) & A-Phase Current LG (I_a(lg)) and hit the calculate button.

FAQs on Fault Impedance using A-Phase Voltage(LGF)

What is the formula to find Fault Impedance using A-Phase Voltage(LGF)?

The formula of Fault Impedance using A-Phase Voltage(LGF) is expressed as Fault Impedance LG = A Phase Voltage LG/A-Phase Current LG. Here is an example- 5.610329 = 11.95/2.13.

How to calculate Fault Impedance using A-Phase Voltage(LGF)?

With A Phase Voltage LG (V_a(lg)) & A-Phase Current LG (I_a(lg)) we can find Fault Impedance using A-Phase Voltage(LGF) using the formula - Fault Impedance LG = A Phase Voltage LG/A-Phase Current LG.

What are the other ways to Calculate Fault Impedance LG?

Here are the different ways to Calculate Fault Impedance LG-

Fault Impedance LG=(Zero Sequence Voltage LG+Positive Sequence Voltage LG+Negative Sequence Voltage LG)/(3*Positive Sequence Current LG)
Fault Impedance LG=1/3*((A Phase EMF LG/Positive Sequence Current LG)-(Zero Sequence Impedance LG+Positive Sequence Impedance LG+Negative Sequence Impedance LG))
Fault Impedance LG=Fault Voltage LG/A-Phase Current LG-(1/3*(Zero Sequence Impedance LG+Positive Sequence Impedance LG+Negative Sequence Impedance LG))

Can the Fault Impedance using A-Phase Voltage(LGF) be negative?

No, the Fault Impedance using A-Phase Voltage(LGF), measured in Electric Resistance cannot be negative.

Which unit is used to measure Fault Impedance using A-Phase Voltage(LGF)?

Fault Impedance using A-Phase Voltage(LGF) is usually measured using the Ohm[Ω] for Electric Resistance. Megohm[Ω], Microhm[Ω], Volt per Ampere[Ω] are the few other units in which Fault Impedance using A-Phase Voltage(LGF) can be measured.

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