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Equivalent Stiffness of Two Springs in Series Formula

GoEquivalent Stiffness of Two Springs in Parallel Formula

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Equivalent Stiffness of Springs is the combined stiffness of multiple springs in a mechanical system, affecting the vibration response and natural frequency. Check FAQs

K eq = \frac{K 1 \cdot K 2}{K 1 + K 2}

K_eq - Equivalent Stiffness of Springs?K₁ - Stiffness of Spring 1?K₂ - Stiffness of Spring 2?

Equivalent Stiffness of Two Springs in Series Example

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Here is how the Equivalent Stiffness of Two Springs in Series equation looks like with Values.

Here is how the Equivalent Stiffness of Two Springs in Series equation looks like with Units.

Here is how the Equivalent Stiffness of Two Springs in Series equation looks like.

24.99 = \frac{49 \cdot 51}{49 + 51}

24.99N/mm = \frac{49N/mm \cdot 51N/mm}{49N/mm + 51N/mm}

24.99 = \frac{49 \cdot 51}{49 + 51}

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Equivalent Stiffness of Two Springs in Series Solution

Follow our step by step solution on how to calculate Equivalent Stiffness of Two Springs in Series?

FIRST Step Consider the formula

K eq = \frac{K 1 \cdot K 2}{K 1 + K 2}

Next Step Substitute values of Variables

∴

K eq = \frac{49N/mm \cdot 51N/mm}{49N/mm + 51N/mm}

Next Step Convert Units

∴

K eq = \frac{49000N/m \cdot 51000N/m}{49000N/m + 51000N/m}

Next Step Prepare to Evaluate

∴

K eq = \frac{49000 \cdot 51000}{49000 + 51000}

Next Step Evaluate

∴

K eq = 24990N/m

LAST Step Convert to Output's Unit

∴

K eq = 24.99N/mm

Equivalent Stiffness of Two Springs in Series Formula Elements

Variables

Equivalent Stiffness of Springs

Equivalent Stiffness of Springs is the combined stiffness of multiple springs in a mechanical system, affecting the vibration response and natural frequency.

Symbol: K_eq

Measurement: Stiffness ConstantUnit: N/mm

Note: Value should be greater than 0.

Formulas to find Equivalent Stiffness of Springs

Stiffness of Spring 1

Stiffness of Spring 1 is a measure of the force required to deform a spring by a unit distance in a mechanical vibration system.

Symbol: K₁

Measurement: Stiffness ConstantUnit: N/mm

Note: Value should be greater than 0.

Formulas to find Stiffness of Spring 1

Stiffness of Spring 2

Stiffness of Spring 2 is a measure of the force required to deform a spring by a unit distance in mechanical vibration systems.

Symbol: K₂

Measurement: Stiffness ConstantUnit: N/mm

Note: Value should be greater than 0.

Formulas to find Stiffness of Spring 2

Other Formulas to find Equivalent Stiffness of Springs

Go Equivalent Stiffness of Two Springs in Parallel

K eq = K 1 + K 2

Other formulas in Undamped Free Vibration category

Go Frequency of Vibration

v vib = \frac{1}{2 \cdot π} \cdot \sqrt{\frac{k 1}{m}}

Go Natural Frequency of Torsional Vibration System

ω' = \sqrt{\frac{s}{I disc}}

How to Evaluate Equivalent Stiffness of Two Springs in Series?

Equivalent Stiffness of Two Springs in Series evaluator uses Equivalent Stiffness of Springs = (Stiffness of Spring 1*Stiffness of Spring 2)/(Stiffness of Spring 1+Stiffness of Spring 2) to evaluate the Equivalent Stiffness of Springs, Equivalent Stiffness of Two Springs in Series formula is defined as the total stiffness of two springs connected in series, which determines the overall stiffness of the system, taking into account the individual stiffness of each spring, and is a critical parameter in mechanical vibration analysis. Equivalent Stiffness of Springs is denoted by K_eq symbol.

How to evaluate Equivalent Stiffness of Two Springs in Series using this online evaluator? To use this online evaluator for Equivalent Stiffness of Two Springs in Series, enter Stiffness of Spring 1 (K₁) & Stiffness of Spring 2 (K₂) and hit the calculate button.

FAQs on Equivalent Stiffness of Two Springs in Series

What is the formula to find Equivalent Stiffness of Two Springs in Series?

The formula of Equivalent Stiffness of Two Springs in Series is expressed as Equivalent Stiffness of Springs = (Stiffness of Spring 1*Stiffness of Spring 2)/(Stiffness of Spring 1+Stiffness of Spring 2). Here is an example- 0.02499 = (49000*51000)/(49000+51000).

How to calculate Equivalent Stiffness of Two Springs in Series?

With Stiffness of Spring 1 (K₁) & Stiffness of Spring 2 (K₂) we can find Equivalent Stiffness of Two Springs in Series using the formula - Equivalent Stiffness of Springs = (Stiffness of Spring 1*Stiffness of Spring 2)/(Stiffness of Spring 1+Stiffness of Spring 2).

What are the other ways to Calculate Equivalent Stiffness of Springs?

Here are the different ways to Calculate Equivalent Stiffness of Springs-

Equivalent Stiffness of Springs=Stiffness of Spring 1+Stiffness of Spring 2

Can the Equivalent Stiffness of Two Springs in Series be negative?

No, the Equivalent Stiffness of Two Springs in Series, measured in Stiffness Constant cannot be negative.

Which unit is used to measure Equivalent Stiffness of Two Springs in Series?

Equivalent Stiffness of Two Springs in Series is usually measured using the Newton per Millimeter[N/mm] for Stiffness Constant. Newton per Meter[N/mm], Kilonewton per Millimeter[N/mm] are the few other units in which Equivalent Stiffness of Two Springs in Series can be measured.

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Equivalent Stiffness of Two Springs in Series Formula

​GoEquivalent Stiffness of Two Springs in Parallel Formula

Equivalent Stiffness of Two Springs in Series Example

Equivalent Stiffness of Two Springs in Series Solution

Equivalent Stiffness of Two Springs in Series Formula Elements

Other Formulas to find Equivalent Stiffness of Springs

Other formulas in Undamped Free Vibration category

How to Evaluate Equivalent Stiffness of Two Springs in Series?

FAQs on Equivalent Stiffness of Two Springs in Series

Variable Name

GoEquivalent Stiffness of Two Springs in Parallel Formula