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Equilibrium Partial Pressure of Substance A Formula

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Equilibrium Partial Pressure A is the partial pressure for both homogeneous and heterogeneous reactions involving gas A. Check FAQs

P A = {(\frac{({p C}^{c}) \cdot ({p D}^{d})}{K p \cdot ({p B}^{b})})}^{\frac{1}{a}}

P_A - Equilibrium Partial Pressure A?p_C - Equilibrium Partial Pressure C?c - No. of Moles of C?p_D - Equilibrium Partial Pressure D?d - No. of Moles of D?K_p - Equilibrium Constant for Partial Pressure?p_B - Equilibrium Partial Pressure B?b - No. of Moles of B?a - Number of Moles of A?

Equilibrium Partial Pressure of Substance A Example

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Here is how the Equilibrium Partial Pressure of Substance A equation looks like with Values.

Here is how the Equilibrium Partial Pressure of Substance A equation looks like with Units.

Here is how the Equilibrium Partial Pressure of Substance A equation looks like.

0.7699 = {(\frac{(80^{9}) \cdot (40^{7})}{150 \cdot (50^{3})})}^{\frac{1}{17}}

0.7699Bar = {(\frac{({80Bar}^{9}) \cdot ({40Bar}^{7})}{150mol/L \cdot ({50Bar}^{3})})}^{\frac{1}{17}}

0.7699 = {(\frac{(80^{9}) \cdot (40^{7})}{150 \cdot (50^{3})})}^{\frac{1}{17}}

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Equilibrium Partial Pressure of Substance A Solution

Follow our step by step solution on how to calculate Equilibrium Partial Pressure of Substance A?

FIRST Step Consider the formula

P A = {(\frac{({p C}^{c}) \cdot ({p D}^{d})}{K p \cdot ({p B}^{b})})}^{\frac{1}{a}}

Next Step Substitute values of Variables

∴

P A = {(\frac{({80Bar}^{9}) \cdot ({40Bar}^{7})}{150mol/L \cdot ({50Bar}^{3})})}^{\frac{1}{17}}

Next Step Convert Units

∴

P A = {(\frac{({8E+6Pa}^{9}) \cdot ({4E+6Pa}^{7})}{150000mol/m³ \cdot ({5E+6Pa}^{3})})}^{\frac{1}{17}}

Next Step Prepare to Evaluate

∴

P A = {(\frac{({8E+6}^{9}) \cdot ({4E+6}^{7})}{150000 \cdot ({5E+6}^{3})})}^{\frac{1}{17}}

Next Step Evaluate

∴

P A = 76988.384891225Pa

Next Step Convert to Output's Unit

∴

P A = 0.76988384891225Bar

LAST Step Rounding Answer

∴

P A = 0.7699Bar

Equilibrium Partial Pressure of Substance A Formula Elements

Variables

Equilibrium Partial Pressure A

Equilibrium Partial Pressure A is the partial pressure for both homogeneous and heterogeneous reactions involving gas A.

Symbol: P_A

Measurement: PressureUnit: Bar

Note: Value can be positive or negative.

Formulas to find Equilibrium Partial Pressure A

Equilibrium Partial Pressure C

Equilibrium Partial Pressure C is the partial pressure for both homogeneous and heterogeneous reactions involving gas C.

Symbol: p_C

Measurement: PressureUnit: Bar

Note: Value can be positive or negative.

Formulas to find Equilibrium Partial Pressure C

No. of Moles of C

No. of Moles of C is the no. of moles of product C present in the equilibrium mixture.

Symbol: c

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find No. of Moles of C

Equilibrium Partial Pressure D

Equilibrium Partial Pressure D is the partial pressure for both homogeneous and heterogeneous reactions involving gas D.

Symbol: p_D

Measurement: PressureUnit: Bar

Note: Value can be positive or negative.

Formulas to find Equilibrium Partial Pressure D

No. of Moles of D

No. of Moles of D is the no. of moles of product D present in the equilibrium mixture.

Symbol: d

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find No. of Moles of D

Equilibrium Constant for Partial Pressure

Equilibrium constant for partial pressure is the value of its reaction quotient at chemical equilibrium with respect to partial pressure.

Symbol: K_p

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Equilibrium Constant for Partial Pressure

Equilibrium Partial Pressure B

Equilibrium Partial Pressure B is the partial pressure for both homogeneous and heterogeneous reactions involving gas B.

Symbol: p_B

Measurement: PressureUnit: Bar

Note: Value can be positive or negative.

Formulas to find Equilibrium Partial Pressure B

No. of Moles of B

No. of Moles of B is the no. of moles of reactant B present in the equilibrium mixture.

Symbol: b

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find No. of Moles of B

Number of Moles of A

Number of Moles of A is the no. of moles of reactant A present in the equilibrium mixture.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Number of Moles of A

Other formulas in Properties of Equilibrium Constant category

Go Equilibrium Constant for Reaction when Multiplied with Integer

K'' c = ({K c}^{n})

Go Equilibrium Constant for Reverse Reaction

K' c = \frac{({Eq conc A}^{a}) \cdot ({Eq conc B}^{b})}{({Eq conc C}^{c}) \cdot ({Eq conc D}^{d})}

How to Evaluate Equilibrium Partial Pressure of Substance A?

Equilibrium Partial Pressure of Substance A evaluator uses Equilibrium Partial Pressure A = (((Equilibrium Partial Pressure C^No. of Moles of C)*(Equilibrium Partial Pressure D^No. of Moles of D))/(Equilibrium Constant for Partial Pressure*(Equilibrium Partial Pressure B^No. of Moles of B)))^(1/Number of Moles of A) to evaluate the Equilibrium Partial Pressure A, The Equilibrium partial pressure of substance A formula is defined as the partial pressure for both homogeneous and heterogeneous reactions involving gas A. Equilibrium Partial Pressure A is denoted by P_A symbol.

How to evaluate Equilibrium Partial Pressure of Substance A using this online evaluator? To use this online evaluator for Equilibrium Partial Pressure of Substance A, enter Equilibrium Partial Pressure C (p_C), No. of Moles of C (c), Equilibrium Partial Pressure D (p_D), No. of Moles of D (d), Equilibrium Constant for Partial Pressure (K_p), Equilibrium Partial Pressure B (p_B), No. of Moles of B (b) & Number of Moles of A (a) and hit the calculate button.

FAQs on Equilibrium Partial Pressure of Substance A

What is the formula to find Equilibrium Partial Pressure of Substance A?

The formula of Equilibrium Partial Pressure of Substance A is expressed as Equilibrium Partial Pressure A = (((Equilibrium Partial Pressure C^No. of Moles of C)*(Equilibrium Partial Pressure D^No. of Moles of D))/(Equilibrium Constant for Partial Pressure*(Equilibrium Partial Pressure B^No. of Moles of B)))^(1/Number of Moles of A). Here is an example- 7.7E-6 = (((8000000^9)*(4000000^7))/(150000*(5000000^3)))^(1/17).

How to calculate Equilibrium Partial Pressure of Substance A?

With Equilibrium Partial Pressure C (p_C), No. of Moles of C (c), Equilibrium Partial Pressure D (p_D), No. of Moles of D (d), Equilibrium Constant for Partial Pressure (K_p), Equilibrium Partial Pressure B (p_B), No. of Moles of B (b) & Number of Moles of A (a) we can find Equilibrium Partial Pressure of Substance A using the formula - Equilibrium Partial Pressure A = (((Equilibrium Partial Pressure C^No. of Moles of C)*(Equilibrium Partial Pressure D^No. of Moles of D))/(Equilibrium Constant for Partial Pressure*(Equilibrium Partial Pressure B^No. of Moles of B)))^(1/Number of Moles of A).

Can the Equilibrium Partial Pressure of Substance A be negative?

Yes, the Equilibrium Partial Pressure of Substance A, measured in Pressure can be negative.

Which unit is used to measure Equilibrium Partial Pressure of Substance A?

Equilibrium Partial Pressure of Substance A is usually measured using the Bar[Bar] for Pressure. Pascal[Bar], Kilopascal[Bar], Pound Per Square Inch[Bar] are the few other units in which Equilibrium Partial Pressure of Substance A can be measured.

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Equilibrium Partial Pressure of Substance A Formula

Equilibrium Partial Pressure of Substance A Example

Equilibrium Partial Pressure of Substance A Solution

Equilibrium Partial Pressure of Substance A Formula Elements

Other formulas in Properties of Equilibrium Constant category

How to Evaluate Equilibrium Partial Pressure of Substance A?

FAQs on Equilibrium Partial Pressure of Substance A

Variable Name