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Equation for drawdown across one log cycle Formula

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The Drawdown Across Log Cycle is referred as change in water level (or hydraulic head) in an aquifer due to pumping from a well. Check FAQs

Δs D = \frac{2.3 \cdot q}{τ \cdot 4 \cdot π}

Δs_D - Drawdown Across Log Cycle?q - Pumping Rate?τ - Transmissivity?π - Archimedes' constant?

Equation for drawdown across one log cycle Example

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Here is how the Equation for drawdown across one log cycle equation looks like with Values.

Here is how the Equation for drawdown across one log cycle equation looks like with Units.

Here is how the Equation for drawdown across one log cycle equation looks like.

0.9151 = \frac{2.3 \cdot 7}{1.4 \cdot 4 \cdot 3.1416}

0.9151 = \frac{2.3 \cdot 7m³/s}{1.4m²/s \cdot 4 \cdot 3.1416}

0.9151 = \frac{2.3 \cdot 7}{1.4 \cdot 4 \cdot 3.1416}

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Equation for drawdown across one log cycle Solution

Follow our step by step solution on how to calculate Equation for drawdown across one log cycle?

FIRST Step Consider the formula

Δs D = \frac{2.3 \cdot q}{τ \cdot 4 \cdot π}

Next Step Substitute values of Variables

∴

Δs D = \frac{2.3 \cdot 7m³/s}{1.4m²/s \cdot 4 \cdot π}

Next Step Substitute values of Constants

∴

Δs D = \frac{2.3 \cdot 7m³/s}{1.4m²/s \cdot 4 \cdot 3.1416}

Next Step Prepare to Evaluate

∴

Δs D = \frac{2.3 \cdot 7}{1.4 \cdot 4 \cdot 3.1416}

Next Step Evaluate

∴

Δs D = 0.915140922778398

LAST Step Rounding Answer

∴

Δs D = 0.9151

Equation for drawdown across one log cycle Formula Elements

Variables

Constants

Drawdown Across Log Cycle

The Drawdown Across Log Cycle is referred as change in water level (or hydraulic head) in an aquifer due to pumping from a well.

Symbol: Δs_D

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Drawdown Across Log Cycle

Pumping Rate

The Pumping Rate is referred as volume of water (or other fluid) that is pumped per unit of time. It’s typically measured in units like liters per second (L/s) or cubic meters per hour (m³/h).

Symbol: q

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Pumping Rate

Transmissivity

The Transmissivity refers to the measure of how much water can be transmitted horizontally through an aquifer is the product of the hydraulic conductivity of the aquifer and its saturated thickness.

Symbol: τ

Measurement: Kinematic ViscosityUnit: m²/s

Note: Value should be greater than 0.

Formulas to find Transmissivity

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other formulas in Time Drawdown Analysis category

Go Time at which Steady Shape Conditions Develop

t c = \frac{7200 \cdot r^{2} \cdot S}{τ}

Go Storage Coefficient given time at which Steady Shape conditions develops

S = τ \cdot \frac{t c}{7200} \cdot r^{2}

Go Transmissivity derived from time drawdown graphs

τ = \frac{2.3 \cdot q}{4 \cdot π \cdot Δs}

Go Equation for pumping rate of transmissivity from time drawdown graphs

q = \frac{τ \cdot 4 \cdot π \cdot Δs D}{2.3}

How to Evaluate Equation for drawdown across one log cycle?

Equation for drawdown across one log cycle evaluator uses Drawdown Across Log Cycle = (2.3*Pumping Rate)/(Transmissivity*4*pi) to evaluate the Drawdown Across Log Cycle, The Equation for drawdown across one log cycle when transmissivity is given as the reduction in hydraulic head observed at a well in an aquifer. Drawdown Across Log Cycle is denoted by Δs_D symbol.

How to evaluate Equation for drawdown across one log cycle using this online evaluator? To use this online evaluator for Equation for drawdown across one log cycle, enter Pumping Rate (q) & Transmissivity (τ) and hit the calculate button.

FAQs on Equation for drawdown across one log cycle

What is the formula to find Equation for drawdown across one log cycle?

The formula of Equation for drawdown across one log cycle is expressed as Drawdown Across Log Cycle = (2.3*Pumping Rate)/(Transmissivity*4*pi). Here is an example- 0.915141 = (2.3*7)/(1.4*4*pi).

How to calculate Equation for drawdown across one log cycle?

With Pumping Rate (q) & Transmissivity (τ) we can find Equation for drawdown across one log cycle using the formula - Drawdown Across Log Cycle = (2.3*Pumping Rate)/(Transmissivity*4*pi). This formula also uses Archimedes' constant .

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