FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Entropy for Pumps using Volume Expansivity for Pump Formula

Fx Copy

LaTeX Copy

Change in entropy is the thermodynamic quantity equivalent to the total difference between the entropy of a system. Check FAQs

ΔS = (c \cdot \ln (\frac{T 2}{T 1})) - (β \cdot V T \cdot ΔP)

ΔS - Change in Entropy?c - Specific Heat Capacity?T₂ - Temperature of Surface 2?T₁ - Temperature of Surface 1?β - Volume Expansivity?V_T - Volume?ΔP - Difference in Pressure?

Entropy for Pumps using Volume Expansivity for Pump Example

With values

With units

Only example

Here is how the Entropy for Pumps using Volume Expansivity for Pump equation looks like with Values.

Here is how the Entropy for Pumps using Volume Expansivity for Pump equation looks like with Units.

Here is how the Entropy for Pumps using Volume Expansivity for Pump equation looks like.

-61.3174 = (4.184 \cdot \ln (\frac{151}{101})) - (0.1 \cdot 63 \cdot 10)

-61.3174J/kg*K = (4.184J/(kg*K) \cdot \ln (\frac{151K}{101K})) - (0.1°C⁻¹ \cdot 63m³ \cdot 10Pa)

-61.3174 = (4.184 \cdot \ln (\frac{151}{101})) - (0.1 \cdot 63 \cdot 10)

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Chemical Engineering » Category

Thermodynamics » fx Entropy for Pumps using Volume Expansivity for Pump

Entropy for Pumps using Volume Expansivity for Pump Solution

Follow our step by step solution on how to calculate Entropy for Pumps using Volume Expansivity for Pump?

FIRST Step Consider the formula

ΔS = (c \cdot \ln (\frac{T 2}{T 1})) - (β \cdot V T \cdot ΔP)

Next Step Substitute values of Variables

∴

ΔS = (4.184J/(kg*K) \cdot \ln (\frac{151K}{101K})) - (0.1°C⁻¹ \cdot 63m³ \cdot 10Pa)

Next Step Convert Units

∴

ΔS = (4.184J/(kg*K) \cdot \ln (\frac{151K}{101K})) - (0.11/K \cdot 63m³ \cdot 10Pa)

Next Step Prepare to Evaluate

∴

ΔS = (4.184 \cdot \ln (\frac{151}{101})) - (0.1 \cdot 63 \cdot 10)

Next Step Evaluate

∴

ΔS = -61.3173654052302J/kg*K

LAST Step Rounding Answer

∴

ΔS = -61.3174J/kg*K

Entropy for Pumps using Volume Expansivity for Pump Formula Elements

Variables

Functions

Change in Entropy

Change in entropy is the thermodynamic quantity equivalent to the total difference between the entropy of a system.

Symbol: ΔS

Measurement: Specific EntropyUnit: J/kg*K

Note: Value can be positive or negative.

Formulas to find Change in Entropy

Specific Heat Capacity

Specific Heat Capacity is the heat required to raise the temperature of the unit mass of a given substance by a given amount.

Symbol: c

Measurement: Specific Heat CapacityUnit: J/(kg*K)

Note: Value can be positive or negative.

Formulas to find Specific Heat Capacity

Temperature of Surface 2

Temperature of Surface 2 is the temperature of the 2nd surface.

Symbol: T₂

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Surface 2

Temperature of Surface 1

Temperature of Surface 1 is the temperature of the 1st surface.

Symbol: T₁

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Surface 1

Volume Expansivity

Volume Expansivity is the fractional increase in the volume of a solid, liquid, or gas per unit rise in temperature.

Symbol: β

Measurement: Temperature Coefficient of ResistanceUnit: °C⁻¹

Note: Value can be positive or negative.

Formulas to find Volume Expansivity

Volume

Volume is the amount of space that a substance or object occupies or that is enclosed within a container.

Symbol: V_T

Measurement: VolumeUnit: m³

Note: Value should be greater than 0.

Formulas to find Volume

Difference in Pressure

Difference in Pressure is the difference between the pressures.

Symbol: ΔP

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Difference in Pressure

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Application of Thermodynamics to Flow Processes category

Go Isentropic Work done rate for Adiabatic Compression Process using Cp

W s isentropic = c \cdot T 1 \cdot ({(\frac{P 2}{P 1})}^{\frac{[R]}{c}} - 1)

Go Isentropic Work Done Rate for Adiabatic Compression Process using Gamma

W s isentropic = [R] \cdot (\frac{T 1}{\frac{γ - 1}{γ}}) \cdot ({(\frac{P 2}{P 1})}^{\frac{γ - 1}{γ}} - 1)

How to Evaluate Entropy for Pumps using Volume Expansivity for Pump?

Entropy for Pumps using Volume Expansivity for Pump evaluator uses Change in Entropy = (Specific Heat Capacity*ln(Temperature of Surface 2/Temperature of Surface 1))-(Volume Expansivity*Volume*Difference in Pressure) to evaluate the Change in Entropy, The Entropy for Pumps using Volume Expansivity for Pump formula is defined as the function of specific heat capacity, temperature 1 & 2, volume, volume expansivity, and the difference in pressure for a pump. Change in Entropy is denoted by ΔS symbol.

How to evaluate Entropy for Pumps using Volume Expansivity for Pump using this online evaluator? To use this online evaluator for Entropy for Pumps using Volume Expansivity for Pump, enter Specific Heat Capacity (c), Temperature of Surface 2 (T₂), Temperature of Surface 1 (T₁), Volume Expansivity (β), Volume (V_T) & Difference in Pressure (ΔP) and hit the calculate button.

FAQs on Entropy for Pumps using Volume Expansivity for Pump

What is the formula to find Entropy for Pumps using Volume Expansivity for Pump?

The formula of Entropy for Pumps using Volume Expansivity for Pump is expressed as Change in Entropy = (Specific Heat Capacity*ln(Temperature of Surface 2/Temperature of Surface 1))-(Volume Expansivity*Volume*Difference in Pressure). Here is an example- -61.317365 = (4.184*ln(151/101))-(0.1*63*10).

How to calculate Entropy for Pumps using Volume Expansivity for Pump?

With Specific Heat Capacity (c), Temperature of Surface 2 (T₂), Temperature of Surface 1 (T₁), Volume Expansivity (β), Volume (V_T) & Difference in Pressure (ΔP) we can find Entropy for Pumps using Volume Expansivity for Pump using the formula - Change in Entropy = (Specific Heat Capacity*ln(Temperature of Surface 2/Temperature of Surface 1))-(Volume Expansivity*Volume*Difference in Pressure). This formula also uses Natural Logarithm (ln) function(s).

Can the Entropy for Pumps using Volume Expansivity for Pump be negative?

Yes, the Entropy for Pumps using Volume Expansivity for Pump, measured in Specific Entropy can be negative.

Which unit is used to measure Entropy for Pumps using Volume Expansivity for Pump?

Entropy for Pumps using Volume Expansivity for Pump is usually measured using the Joule per Kilogram K[J/kg*K] for Specific Entropy. Calorie per Gram per Celcius[J/kg*K], Joule per Kilogram per Celcius[J/kg*K], Kilojoule per Kilogram per Celcius[J/kg*K] are the few other units in which Entropy for Pumps using Volume Expansivity for Pump can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Entropy for Pumps using Volume Expansivity for Pump Formula

Entropy for Pumps using Volume Expansivity for Pump Example

Entropy for Pumps using Volume Expansivity for Pump Solution

Entropy for Pumps using Volume Expansivity for Pump Formula Elements

Other formulas in Application of Thermodynamics to Flow Processes category

How to Evaluate Entropy for Pumps using Volume Expansivity for Pump?

FAQs on Entropy for Pumps using Volume Expansivity for Pump

Variable Name