FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Entropy Change for Isochoric Process given Pressures Formula

GoEntropy Change for Isochoric Process given Temperature Formula

Fx Copy

LaTeX Copy

Entropy change constant volume is the measure of a system’s thermal energy per unit temperature that is unavailable for doing useful work. Check FAQs

δs vol = m gas \cdot C vs \cdot \ln (\frac{P f}{P i})

δs_vol - Entropy Change Constant Volume?m_gas - Mass of Gas?C_vs - Specific Molar Heat Capacity at Constant Volume?P_f - Final Pressure of System?P_i - Initial Pressure of System?

Entropy Change for Isochoric Process given Pressures Example

With values

With units

Only example

Here is how the Entropy Change for Isochoric Process given Pressures equation looks like with Values.

Here is how the Entropy Change for Isochoric Process given Pressures equation looks like with Units.

Here is how the Entropy Change for Isochoric Process given Pressures equation looks like.

130.1023 = 2 \cdot 530 \cdot \ln (\frac{96100}{85000})

130.1023J/kg*K = 2kg \cdot 530J/K*mol \cdot \ln (\frac{96100Pa}{85000Pa})

130.1023 = 2 \cdot 530 \cdot \ln (\frac{96100}{85000})

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Mechanical » Category

Thermodynamics » fx Entropy Change for Isochoric Process given Pressures

Entropy Change for Isochoric Process given Pressures Solution

Follow our step by step solution on how to calculate Entropy Change for Isochoric Process given Pressures?

FIRST Step Consider the formula

δs vol = m gas \cdot C vs \cdot \ln (\frac{P f}{P i})

Next Step Substitute values of Variables

∴

δs vol = 2kg \cdot 530J/K*mol \cdot \ln (\frac{96100Pa}{85000Pa})

Next Step Prepare to Evaluate

∴

δs vol = 2 \cdot 530 \cdot \ln (\frac{96100}{85000})

Next Step Evaluate

∴

δs vol = 130.102343055086J/kg*K

LAST Step Rounding Answer

∴

δs vol = 130.1023J/kg*K

Entropy Change for Isochoric Process given Pressures Formula Elements

Variables

Functions

Entropy Change Constant Volume

Entropy change constant volume is the measure of a system’s thermal energy per unit temperature that is unavailable for doing useful work.

Symbol: δs_vol

Measurement: Specific EntropyUnit: J/kg*K

Note: Value can be positive or negative.

Formulas to find Entropy Change Constant Volume

Mass of Gas

Mass of Gas is the mass on or by which the work is done.

Symbol: m_gas

Measurement: WeightUnit: kg

Note: Value should be greater than 0.

Formulas to find Mass of Gas

Specific Molar Heat Capacity at Constant Volume

Specific Molar Heat Capacity at Constant Volume, (of a gas) is the amount of heat required to raise the temperature of 1 mol of the gas by 1 °C at the constant volume.

Symbol: C_vs

Measurement: Molar Specific Heat Capacity at Constant VolumeUnit: J/K*mol

Note: Value should be greater than 0.

Formulas to find Specific Molar Heat Capacity at Constant Volume

Final Pressure of System

Final Pressure of System is the total final pressure exerted by the molecules inside the system.

Symbol: P_f

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Final Pressure of System

Initial Pressure of System

Initial Pressure of System is the total initial pressure exerted by the molecules inside the system.

Symbol: P_i

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Initial Pressure of System

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other Formulas to find Entropy Change Constant Volume

Go Entropy Change for Isochoric Process given Temperature

δs vol = m gas \cdot C vs \cdot \ln (\frac{T f}{T i})

Other formulas in Entropy Generation category

Go Specific Heat Capacity at Constant Pressure using Adiabatic Index

C p = \frac{γ \cdot [R]}{γ - 1}

Go Entropy Change in Isobaric Process given Temperature

δs pres = m gas \cdot C pm \cdot \ln (\frac{T f}{T i})

Go Entropy Change in Isobaric Processin Terms of Volume

δs pres = m gas \cdot C pm \cdot \ln (\frac{V f}{V i})

Go Entropy Change for Isothermal Process given Volumes

ΔS = m gas \cdot [R] \cdot \ln (\frac{V f}{V i})

How to Evaluate Entropy Change for Isochoric Process given Pressures?

Entropy Change for Isochoric Process given Pressures evaluator uses Entropy Change Constant Volume = Mass of Gas*Specific Molar Heat Capacity at Constant Volume*ln(Final Pressure of System/Initial Pressure of System) to evaluate the Entropy Change Constant Volume, Entropy Change for Isochoric Process given Pressures formula is defined as a measure of the change in entropy during an isochoric process, reflecting how pressure variations affect the thermal state of a gas while maintaining constant volume. Entropy Change Constant Volume is denoted by δs_vol symbol.

How to evaluate Entropy Change for Isochoric Process given Pressures using this online evaluator? To use this online evaluator for Entropy Change for Isochoric Process given Pressures, enter Mass of Gas (m_gas), Specific Molar Heat Capacity at Constant Volume (C_vs), Final Pressure of System (P_f) & Initial Pressure of System (P_i) and hit the calculate button.

FAQs on Entropy Change for Isochoric Process given Pressures

What is the formula to find Entropy Change for Isochoric Process given Pressures?

The formula of Entropy Change for Isochoric Process given Pressures is expressed as Entropy Change Constant Volume = Mass of Gas*Specific Molar Heat Capacity at Constant Volume*ln(Final Pressure of System/Initial Pressure of System). Here is an example- 130.1023 = 2*530*ln(96100/85000).

How to calculate Entropy Change for Isochoric Process given Pressures?

With Mass of Gas (m_gas), Specific Molar Heat Capacity at Constant Volume (C_vs), Final Pressure of System (P_f) & Initial Pressure of System (P_i) we can find Entropy Change for Isochoric Process given Pressures using the formula - Entropy Change Constant Volume = Mass of Gas*Specific Molar Heat Capacity at Constant Volume*ln(Final Pressure of System/Initial Pressure of System). This formula also uses Natural Logarithm (ln) function(s).

What are the other ways to Calculate Entropy Change Constant Volume?

Here are the different ways to Calculate Entropy Change Constant Volume-

Entropy Change Constant Volume=Mass of Gas*Specific Molar Heat Capacity at Constant Volume*ln(Final Temperature/Initial Temperature)

Can the Entropy Change for Isochoric Process given Pressures be negative?

Yes, the Entropy Change for Isochoric Process given Pressures, measured in Specific Entropy can be negative.

Which unit is used to measure Entropy Change for Isochoric Process given Pressures?

Entropy Change for Isochoric Process given Pressures is usually measured using the Joule per Kilogram K[J/kg*K] for Specific Entropy. Calorie per Gram per Celcius[J/kg*K], Joule per Kilogram per Celcius[J/kg*K], Kilojoule per Kilogram per Celcius[J/kg*K] are the few other units in which Entropy Change for Isochoric Process given Pressures can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Entropy Change for Isochoric Process given Pressures Formula

​GoEntropy Change for Isochoric Process given Temperature Formula

Entropy Change for Isochoric Process given Pressures Example

Entropy Change for Isochoric Process given Pressures Solution

Entropy Change for Isochoric Process given Pressures Formula Elements

Other Formulas to find Entropy Change Constant Volume

Other formulas in Entropy Generation category

How to Evaluate Entropy Change for Isochoric Process given Pressures?

FAQs on Entropy Change for Isochoric Process given Pressures

Variable Name

GoEntropy Change for Isochoric Process given Temperature Formula