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Enthalpy of evaporation to nucleate pool boiling Formula

GoEnthalpy of evaporation given critical heat flux Formula

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Change in Enthalpy of Vaporization is the amount of energy (enthalpy) that must be added to a liquid substance to transform a quantity of that substance into a gas. Check FAQs

∆H = {((\frac{1}{Q}) \cdot μ f \cdot {(\frac{[g] \cdot (ρ l - ρ v)}{Y})}^{0.5} \cdot {(\frac{C l \cdot ΔT}{C s \cdot {(Pr)}^{1.7}})}^{3})}^{0.5}

∆H - Change in Enthalpy of Vaporization?Q - Heat Flux?μ_f - Dynamic Viscosity of Fluid?ρ_l - Density of Liquid?ρ_v - Density of Vapour?Y - Surface Tension?C_l - Specific Heat of Liquid?ΔT - Excess Temperature?C_s - Constant in Nucleate Boiling?Pr - Prandtl Number?[g] - Gravitational acceleration on Earth?

Enthalpy of evaporation to nucleate pool boiling Example

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Here is how the Enthalpy of evaporation to nucleate pool boiling equation looks like with Values.

Here is how the Enthalpy of evaporation to nucleate pool boiling equation looks like with Units.

Here is how the Enthalpy of evaporation to nucleate pool boiling equation looks like.

500 = {((\frac{1}{69.4281}) \cdot 8 \cdot {(\frac{9.8066 \cdot (4 - 0.5)}{21.8})}^{0.5} \cdot {(\frac{3 \cdot 12}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

500J/mol = {((\frac{1}{69.4281W/m²}) \cdot 8Pa*s \cdot {(\frac{9.8066m/s² \cdot (4kg/m³ - 0.5kg/m³)}{21.8N/m})}^{0.5} \cdot {(\frac{3J/(kg*K) \cdot 12K}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

500 = {((\frac{1}{69.4281}) \cdot 8 \cdot {(\frac{9.8066 \cdot (4 - 0.5)}{21.8})}^{0.5} \cdot {(\frac{3 \cdot 12}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

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Enthalpy of evaporation to nucleate pool boiling Solution

Follow our step by step solution on how to calculate Enthalpy of evaporation to nucleate pool boiling?

FIRST Step Consider the formula

∆H = {((\frac{1}{Q}) \cdot μ f \cdot {(\frac{[g] \cdot (ρ l - ρ v)}{Y})}^{0.5} \cdot {(\frac{C l \cdot ΔT}{C s \cdot {(Pr)}^{1.7}})}^{3})}^{0.5}

Next Step Substitute values of Variables

∴

∆H = {((\frac{1}{69.4281W/m²}) \cdot 8Pa*s \cdot {(\frac{[g] \cdot (4kg/m³ - 0.5kg/m³)}{21.8N/m})}^{0.5} \cdot {(\frac{3J/(kg*K) \cdot 12K}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

Next Step Substitute values of Constants

∴

∆H = {((\frac{1}{69.4281W/m²}) \cdot 8Pa*s \cdot {(\frac{9.8066m/s² \cdot (4kg/m³ - 0.5kg/m³)}{21.8N/m})}^{0.5} \cdot {(\frac{3J/(kg*K) \cdot 12K}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

Next Step Prepare to Evaluate

∴

∆H = {((\frac{1}{69.4281}) \cdot 8 \cdot {(\frac{9.8066 \cdot (4 - 0.5)}{21.8})}^{0.5} \cdot {(\frac{3 \cdot 12}{0.55 \cdot {(0.7)}^{1.7}})}^{3})}^{0.5}

LAST Step Evaluate

∴

∆H = 500J/mol

Enthalpy of evaporation to nucleate pool boiling Formula Elements

Variables

Constants

Change in Enthalpy of Vaporization

Change in Enthalpy of Vaporization is the amount of energy (enthalpy) that must be added to a liquid substance to transform a quantity of that substance into a gas.

Symbol: ∆H

Measurement: Energy Per MoleUnit: J/mol

Note: Value can be positive or negative.

Formulas to find Change in Enthalpy of Vaporization

Heat Flux

Heat Flux is the heat transfer rate per unit area normal to the direction of heat flow. It is denoted by the letter "Q".

Symbol: Q

Measurement: Heat Flux DensityUnit: W/m²

Note: Value can be positive or negative.

Formulas to find Heat Flux

Dynamic Viscosity of Fluid

Dynamic Viscosity of Fluid is the resistance to movement of one layer of a fluid over another.

Symbol: μ_f

Measurement: Dynamic ViscosityUnit: Pa*s

Note: Value can be positive or negative.

Formulas to find Dynamic Viscosity of Fluid

Density of Liquid

Density of Liquid is mass of a unit volume of a material substance.

Symbol: ρ_l

Measurement: DensityUnit: kg/m³

Note: Value should be greater than 0.

Formulas to find Density of Liquid

Density of Vapour

The Density of Vapour is the mass of a unit volume of a material substance.

Symbol: ρ_v

Measurement: DensityUnit: kg/m³

Note: Value should be greater than 0.

Formulas to find Density of Vapour

Surface Tension

Surface Tension is the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Symbol: Y

Measurement: Surface TensionUnit: N/m

Note: Value should be greater than 0.

Formulas to find Surface Tension

Specific Heat of Liquid

Specific Heat of Liquid is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

Symbol: C_l

Measurement: Specific Heat CapacityUnit: J/(kg*K)

Note: Value can be positive or negative.

Formulas to find Specific Heat of Liquid

Excess Temperature

Excess Temperature is defined as the temperature difference between heat source and saturation temperature of the fluid.

Symbol: ΔT

Measurement: Temperature DifferenceUnit: K

Note: Value can be positive or negative.

Formulas to find Excess Temperature

Constant in Nucleate Boiling

Constant in Nucleate Boiling is a constant term used in the nucleate pool boiling equation.

Symbol: C_s

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant in Nucleate Boiling

Prandtl Number

Prandtl Number (Pr) or Prandtl group is a dimensionless number, named after the German physicist Ludwig Prandtl, defined as the ratio of momentum diffusivity to thermal diffusivity.

Symbol: Pr

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Prandtl Number

Gravitational acceleration on Earth

Gravitational acceleration on Earth means that the velocity of an object in free fall will increase by 9.8 m/s2 every second.

Symbol: [g]

Value: 9.80665 m/s²

Other Formulas to find Change in Enthalpy of Vaporization

Go Enthalpy of evaporation given critical heat flux

∆H = \frac{Q c}{0.18 \cdot ρ v \cdot {(\frac{Y \cdot [g] \cdot (ρ l - ρ v)}{{ρ v}^{2}})}^{0.25}}

Other formulas in Boiling category

Go Heat flux to nucleate pool boiling

Q = μ f \cdot ∆H \cdot {(\frac{[g] \cdot (ρ l - ρ v)}{Y})}^{0.5} \cdot {(\frac{C l \cdot ΔT}{C s \cdot ∆H \cdot {(Pr)}^{1.7}})}^{3.0}

Go Critical heat flux to nucleate pool boiling

Q c = 0.18 \cdot ∆H \cdot ρ v \cdot {(\frac{Y \cdot [g] \cdot (ρ l - ρ v)}{{ρ v}^{2}})}^{0.25}

How to Evaluate Enthalpy of evaporation to nucleate pool boiling?

Enthalpy of evaporation to nucleate pool boiling evaluator uses Change in Enthalpy of Vaporization = ((1/Heat Flux)*Dynamic Viscosity of Fluid*(([g]*(Density of Liquid-Density of Vapour))/(Surface Tension))^0.5*((Specific Heat of Liquid*Excess Temperature)/(Constant in Nucleate Boiling*(Prandtl Number)^1.7))^3)^0.5 to evaluate the Change in Enthalpy of Vaporization, Enthalpy of evaporation to nucleate pool boiling formula is defined as amount of energy (enthalpy) that must be added to a liquid substance, to transform a quantity of that substance into a gas. Change in Enthalpy of Vaporization is denoted by ∆H symbol.

How to evaluate Enthalpy of evaporation to nucleate pool boiling using this online evaluator? To use this online evaluator for Enthalpy of evaporation to nucleate pool boiling, enter Heat Flux (Q), Dynamic Viscosity of Fluid (μ_f), Density of Liquid (ρ_l), Density of Vapour (ρ_v), Surface Tension (Y), Specific Heat of Liquid (C_l), Excess Temperature (ΔT), Constant in Nucleate Boiling (C_s) & Prandtl Number (Pr) and hit the calculate button.

FAQs on Enthalpy of evaporation to nucleate pool boiling

What is the formula to find Enthalpy of evaporation to nucleate pool boiling?

The formula of Enthalpy of evaporation to nucleate pool boiling is expressed as Change in Enthalpy of Vaporization = ((1/Heat Flux)*Dynamic Viscosity of Fluid*(([g]*(Density of Liquid-Density of Vapour))/(Surface Tension))^0.5*((Specific Heat of Liquid*Excess Temperature)/(Constant in Nucleate Boiling*(Prandtl Number)^1.7))^3)^0.5. Here is an example- 500 = ((1/69.4281385117412)*8*(([g]*(4-0.5))/(21.8))^0.5*((3*12)/(0.55*(0.7)^1.7))^3)^0.5.

How to calculate Enthalpy of evaporation to nucleate pool boiling?

With Heat Flux (Q), Dynamic Viscosity of Fluid (μ_f), Density of Liquid (ρ_l), Density of Vapour (ρ_v), Surface Tension (Y), Specific Heat of Liquid (C_l), Excess Temperature (ΔT), Constant in Nucleate Boiling (C_s) & Prandtl Number (Pr) we can find Enthalpy of evaporation to nucleate pool boiling using the formula - Change in Enthalpy of Vaporization = ((1/Heat Flux)*Dynamic Viscosity of Fluid*(([g]*(Density of Liquid-Density of Vapour))/(Surface Tension))^0.5*((Specific Heat of Liquid*Excess Temperature)/(Constant in Nucleate Boiling*(Prandtl Number)^1.7))^3)^0.5. This formula also uses Gravitational acceleration on Earth constant(s).

What are the other ways to Calculate Change in Enthalpy of Vaporization?

Here are the different ways to Calculate Change in Enthalpy of Vaporization-

Change in Enthalpy of Vaporization=Critical Heat Flux/(0.18*Density of Vapour*((Surface Tension*[g]*(Density of Liquid-Density of Vapour))/(Density of Vapour^2))^0.25)

Can the Enthalpy of evaporation to nucleate pool boiling be negative?

Yes, the Enthalpy of evaporation to nucleate pool boiling, measured in Energy Per Mole can be negative.

Which unit is used to measure Enthalpy of evaporation to nucleate pool boiling?

Enthalpy of evaporation to nucleate pool boiling is usually measured using the Joule Per Mole[J/mol] for Energy Per Mole. KiloJoule Per Mole[J/mol], Kilocalorie Per Mole[J/mol] are the few other units in which Enthalpy of evaporation to nucleate pool boiling can be measured.

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Enthalpy of evaporation to nucleate pool boiling Formula

​GoEnthalpy of evaporation given critical heat flux Formula

Enthalpy of evaporation to nucleate pool boiling Example

Enthalpy of evaporation to nucleate pool boiling Solution

Enthalpy of evaporation to nucleate pool boiling Formula Elements

Other Formulas to find Change in Enthalpy of Vaporization

Other formulas in Boiling category

How to Evaluate Enthalpy of evaporation to nucleate pool boiling?

FAQs on Enthalpy of evaporation to nucleate pool boiling

Variable Name

GoEnthalpy of evaporation given critical heat flux Formula