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Energy per Unit Material Removal given Efficiency of Motor Drive System Formula

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Energy Required for Unit Volume Removal is the electrical energy required to remove specified unit volume of material from workpiece. This parameter plays a vital role in cost-effectiveness. Check FAQs

P s = P e \cdot \frac{η m}{Z w}

P_s - Energy Required for Unit Volume Removal?P_e - Electrical Power Consumed in Machining?η_m - Overall Efficiency of Machine Tool?Z_w - Metal Removal Rate?

Energy per Unit Material Removal given Efficiency of Motor Drive System Example

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Here is how the Energy per Unit Material Removal given Efficiency of Motor Drive System equation looks like with Values.

Here is how the Energy per Unit Material Removal given Efficiency of Motor Drive System equation looks like with Units.

Here is how the Energy per Unit Material Removal given Efficiency of Motor Drive System equation looks like.

74.375 = 14 \cdot \frac{0.85}{0.16}

74.375kW = 14kW \cdot \frac{0.85}{0.16m³/s}

74.375 = 14 \cdot \frac{0.85}{0.16}

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Energy per Unit Material Removal given Efficiency of Motor Drive System Solution

Follow our step by step solution on how to calculate Energy per Unit Material Removal given Efficiency of Motor Drive System?

FIRST Step Consider the formula

P s = P e \cdot \frac{η m}{Z w}

Next Step Substitute values of Variables

∴

P s = 14kW \cdot \frac{0.85}{0.16m³/s}

Next Step Convert Units

∴

P s = 14000W \cdot \frac{0.85}{0.16m³/s}

Next Step Prepare to Evaluate

∴

P s = 14000 \cdot \frac{0.85}{0.16}

Next Step Evaluate

∴

P s = 74375W

LAST Step Convert to Output's Unit

∴

P s = 74.375kW

Energy per Unit Material Removal given Efficiency of Motor Drive System Formula Elements

Variables

Energy Required for Unit Volume Removal

Energy Required for Unit Volume Removal is the electrical energy required to remove specified unit volume of material from workpiece. This parameter plays a vital role in cost-effectiveness.

Symbol: P_s

Measurement: PowerUnit: kW

Note: Value should be greater than 0.

Formulas to find Energy Required for Unit Volume Removal

Electrical Power Consumed in Machining

Electrical power consumed in machining is the amount of electrical energy a machine tool uses to perform machining operations. This parameter plays a vital role in cost-effectiveness.

Symbol: P_e

Measurement: PowerUnit: kW

Note: Value should be greater than 0.

Formulas to find Electrical Power Consumed in Machining

Overall Efficiency of Machine Tool

Overall Efficiency of Machine Tool is a parameter which signifies how effectively a machine tool can perform under different machining operational conditions.

Symbol: η_m

Measurement: NAUnit: Unitless

Note: Value should be less than 1.

Formulas to find Overall Efficiency of Machine Tool

Metal Removal Rate

Metal removal rate (MRR) is the volume of material can be removed per unit time from workpiece during machining operations.

Symbol: Z_w

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value should be greater than 0.

Formulas to find Metal Removal Rate

Other formulas in Cutting Operation category

Go Cutting Speed Angle using Resultant Cutting Speed

η = a \cos (\frac{v}{v e})

Go Cross sectional Area of Uncut Chip

A c = F \cdot D c

Go Mean Cutting Speed

V t = n \cdot π \cdot \frac{d w + d m}{2}

Go Average Material Removal Rate using Uncut Chip Cross-Section Area

Z t = A cs \cdot V

How to Evaluate Energy per Unit Material Removal given Efficiency of Motor Drive System?

Energy per Unit Material Removal given Efficiency of Motor Drive System evaluator uses Energy Required for Unit Volume Removal = Electrical Power Consumed in Machining*Overall Efficiency of Machine Tool/Metal Removal Rate to evaluate the Energy Required for Unit Volume Removal, The Energy per Unit Material Removal given Efficiency of Motor Drive System is a method to determine the average energy required to remove a unit volume of material from the workpiece, When the overall efficiency of machine tool is known. Energy Required for Unit Volume Removal is denoted by P_s symbol.

How to evaluate Energy per Unit Material Removal given Efficiency of Motor Drive System using this online evaluator? To use this online evaluator for Energy per Unit Material Removal given Efficiency of Motor Drive System, enter Electrical Power Consumed in Machining (P_e), Overall Efficiency of Machine Tool (η_m) & Metal Removal Rate (Z_w) and hit the calculate button.

FAQs on Energy per Unit Material Removal given Efficiency of Motor Drive System

What is the formula to find Energy per Unit Material Removal given Efficiency of Motor Drive System?

The formula of Energy per Unit Material Removal given Efficiency of Motor Drive System is expressed as Energy Required for Unit Volume Removal = Electrical Power Consumed in Machining*Overall Efficiency of Machine Tool/Metal Removal Rate. Here is an example- 0.074375 = 14000*0.85/0.16.

How to calculate Energy per Unit Material Removal given Efficiency of Motor Drive System?

With Electrical Power Consumed in Machining (P_e), Overall Efficiency of Machine Tool (η_m) & Metal Removal Rate (Z_w) we can find Energy per Unit Material Removal given Efficiency of Motor Drive System using the formula - Energy Required for Unit Volume Removal = Electrical Power Consumed in Machining*Overall Efficiency of Machine Tool/Metal Removal Rate.

Can the Energy per Unit Material Removal given Efficiency of Motor Drive System be negative?

No, the Energy per Unit Material Removal given Efficiency of Motor Drive System, measured in Power cannot be negative.

Which unit is used to measure Energy per Unit Material Removal given Efficiency of Motor Drive System?

Energy per Unit Material Removal given Efficiency of Motor Drive System is usually measured using the Kilowatt[kW] for Power. Watt[kW], Milliwatt[kW], Microwatt[kW] are the few other units in which Energy per Unit Material Removal given Efficiency of Motor Drive System can be measured.

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Energy per Unit Material Removal given Efficiency of Motor Drive System Formula

Energy per Unit Material Removal given Efficiency of Motor Drive System Example

Energy per Unit Material Removal given Efficiency of Motor Drive System Solution

Energy per Unit Material Removal given Efficiency of Motor Drive System Formula Elements

Other formulas in Cutting Operation category

How to Evaluate Energy per Unit Material Removal given Efficiency of Motor Drive System?

FAQs on Energy per Unit Material Removal given Efficiency of Motor Drive System

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