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Energy of Photochemical Reaction terms of Wavelength Formula

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Energy in photochemical reaction is the energy absorbed by one mole of a substance which is undergoing a photochemical reaction. Check FAQs

E = \frac{[Avaga-no] \cdot [hP] \cdot [c]}{λ}

E - Energy in Photochemical Reaction?λ - Wavelength?[Avaga-no] - Avogadro’s number?[hP] - Planck constant?[c] - Light speed in vacuum?

Energy of Photochemical Reaction terms of Wavelength Example

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Here is how the Energy of Photochemical Reaction terms of Wavelength equation looks like with Values.

Here is how the Energy of Photochemical Reaction terms of Wavelength equation looks like with Units.

Here is how the Energy of Photochemical Reaction terms of Wavelength equation looks like.

5.7E+7 = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8}{2.1}

5.7E+7J = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8m/s}{2.1nm}

5.7E+7 = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8}{2.1}

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Stark Einstein law » fx Energy of Photochemical Reaction terms of Wavelength

Energy of Photochemical Reaction terms of Wavelength Solution

Follow our step by step solution on how to calculate Energy of Photochemical Reaction terms of Wavelength?

FIRST Step Consider the formula

E = \frac{[Avaga-no] \cdot [hP] \cdot [c]}{λ}

Next Step Substitute values of Variables

∴

E = \frac{[Avaga-no] \cdot [hP] \cdot [c]}{2.1nm}

Next Step Substitute values of Constants

∴

E = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8m/s}{2.1nm}

Next Step Convert Units

∴

E = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8m/s}{2.1E-9m}

Next Step Prepare to Evaluate

∴

E = \frac{6E+23 \cdot 6.6E-34 \cdot 3E+8}{2.1E-9}

Next Step Evaluate

∴

E = 56965030.3108407J

LAST Step Rounding Answer

∴

E = 5.7E+7J

Energy of Photochemical Reaction terms of Wavelength Formula Elements

Variables

Constants

Energy in Photochemical Reaction

Energy in photochemical reaction is the energy absorbed by one mole of a substance which is undergoing a photochemical reaction.

Symbol: E

Measurement: EnergyUnit: J

Note: Value can be positive or negative.

Formulas to find Energy in Photochemical Reaction

Wavelength

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

Symbol: λ

Measurement: WavelengthUnit: nm

Note: Value can be positive or negative.

Formulas to find Wavelength

Avogadro’s number

Avogadro’s number represents the number of entities (atoms, molecules, ions, etc.) in one mole of a substance.

Symbol: [Avaga-no]

Value: 6.02214076E+23

Planck constant

Planck constant is a fundamental universal constant that defines the quantum nature of energy and relates the energy of a photon to its frequency.

Symbol: [hP]

Value: 6.626070040E-34

Light speed in vacuum

Light speed in vacuum is a fundamental physical constant representing the speed at which light propagates through a vacuum.

Symbol: [c]

Value: 299792458.0 m/s

Other Formulas to find Energy in Photochemical Reaction

Go Energy of Photochemical Reaction

E = [Avaga-no] \cdot [hP] \cdot f

Other formulas in Stark Einstein law category

Go Quantum Efficiency for Formation of Product

Φ p = \frac{dN P dt}{I quanta}

Go Number of Molecules of Product formed in 1 second

dN P dt = Φ p \cdot I quanta

Go Number of Quanta absorbed in 1 second using Quantum Efficiency of Products

I quanta = \frac{dN P dt}{Φ p}

Go Quantum Efficiency for Disappearance of Reactant

Φ r = \frac{R mol}{I quanta}

How to Evaluate Energy of Photochemical Reaction terms of Wavelength?

Energy of Photochemical Reaction terms of Wavelength evaluator uses Energy in Photochemical Reaction = ([Avaga-no]*[hP]*[c])/Wavelength to evaluate the Energy in Photochemical Reaction, The Energy of photochemical reaction terms of wavelength formula is defined as the energy absorbed by one mole of a substance which is undergoing a photochemical reaction. Energy in Photochemical Reaction is denoted by E symbol.

How to evaluate Energy of Photochemical Reaction terms of Wavelength using this online evaluator? To use this online evaluator for Energy of Photochemical Reaction terms of Wavelength, enter Wavelength (λ) and hit the calculate button.

FAQs on Energy of Photochemical Reaction terms of Wavelength

What is the formula to find Energy of Photochemical Reaction terms of Wavelength?

The formula of Energy of Photochemical Reaction terms of Wavelength is expressed as Energy in Photochemical Reaction = ([Avaga-no]*[hP]*[c])/Wavelength. Here is an example- 5.7E+7 = ([Avaga-no]*[hP]*[c])/2.1E-09.

How to calculate Energy of Photochemical Reaction terms of Wavelength?

With Wavelength (λ) we can find Energy of Photochemical Reaction terms of Wavelength using the formula - Energy in Photochemical Reaction = ([Avaga-no]*[hP]*[c])/Wavelength. This formula also uses Avogadro’s number, Planck constant, Light speed in vacuum constant(s).

What are the other ways to Calculate Energy in Photochemical Reaction?

Here are the different ways to Calculate Energy in Photochemical Reaction-

Energy in Photochemical Reaction=[Avaga-no]*[hP]*Frequency

Can the Energy of Photochemical Reaction terms of Wavelength be negative?

Yes, the Energy of Photochemical Reaction terms of Wavelength, measured in Energy can be negative.

Which unit is used to measure Energy of Photochemical Reaction terms of Wavelength?

Energy of Photochemical Reaction terms of Wavelength is usually measured using the Joule[J] for Energy. Kilojoule[J], Gigajoule[J], Megajoule[J] are the few other units in which Energy of Photochemical Reaction terms of Wavelength can be measured.

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