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Enantiomeric Excess Formula

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Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer. Check FAQs

ee = | F R - F S |

ee - Enantiomeric Excess?F_R - Mole Fraction of R?F_S - Mole Fraction of S?

Enantiomeric Excess Example

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With units

Only example

Here is how the Enantiomeric Excess equation looks like with Values.

Here is how the Enantiomeric Excess equation looks like with Units.

Here is how the Enantiomeric Excess equation looks like.

0.4 = | 0.7 - 0.3 |

0.4 = | 0.7 - 0.3 |

0.4 = | 0.7 - 0.3 |

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Enantiomeric Excess Solution

Follow our step by step solution on how to calculate Enantiomeric Excess?

FIRST Step Consider the formula

ee = | F R - F S |

Next Step Substitute values of Variables

∴

ee = | 0.7 - 0.3 |

Next Step Prepare to Evaluate

∴

ee = | 0.7 - 0.3 |

LAST Step Evaluate

∴

ee = 0.4

Enantiomeric Excess Formula Elements

Variables

Functions

Enantiomeric Excess

Enantiomeric excess is defined as the absolute difference between the mole fraction of each enantiomer.

Symbol: ee

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Enantiomeric Excess

Mole Fraction of R

Mole Fraction of R is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

Symbol: F_R

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Mole Fraction of R

Mole Fraction of S

Mole Fraction of S is a quantity defined as the ratio between the amount of a constituent substance and the total amount of all constituents in a mixture.

Symbol: F_S

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Mole Fraction of S

abs

The absolute value of a number is its distance from zero on the number line. It's always a positive value, as it represents the magnitude of a number without considering its direction.

Syntax: abs(Number)

Other formulas in Optical Activity category

Go Specific Rotation of Optically Active Compound

[α] D = \frac{α}{l \cdot c}

Go Optical Purity

OP = (\frac{[α] obs}{[α] max}) \cdot 100

Go Percent Enantiomeric Excess

%ee = | F R - F S | \cdot 100

Go Fraction of Major Isomer

F R = 50 + (\frac{%ee}{2})

How to Evaluate Enantiomeric Excess?

Enantiomeric Excess evaluator uses Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S) to evaluate the Enantiomeric Excess, The Enantiomeric Excess formula is defined as the absolute difference between the mole fraction of each enantiomer. Enantiomeric Excess is denoted by ee symbol.

How to evaluate Enantiomeric Excess using this online evaluator? To use this online evaluator for Enantiomeric Excess, enter Mole Fraction of R (F_R) & Mole Fraction of S (F_S) and hit the calculate button.

FAQs on Enantiomeric Excess

What is the formula to find Enantiomeric Excess?

The formula of Enantiomeric Excess is expressed as Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). Here is an example- 0.4 = abs(0.7-0.3).

How to calculate Enantiomeric Excess?

With Mole Fraction of R (F_R) & Mole Fraction of S (F_S) we can find Enantiomeric Excess using the formula - Enantiomeric Excess = abs(Mole Fraction of R-Mole Fraction of S). This formula also uses Absolute (abs) function(s).

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Enantiomeric Excess Formula

Enantiomeric Excess Example

Enantiomeric Excess Solution

Enantiomeric Excess Formula Elements

Other formulas in Optical Activity category

How to Evaluate Enantiomeric Excess?

FAQs on Enantiomeric Excess

Variable Name