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Electric Field due to Hall Voltage Formula

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Hall Electric Field phenomenon that occurs in a conductor when a current flows through it in the presence of a perpendicular magnetic field. Check FAQs

E H = \frac{V h}{d}

E_H - Hall Electric Field?V_h - Hall Voltage?d - Conductor Width?

Electric Field due to Hall Voltage Example

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Here is how the Electric Field due to Hall Voltage equation looks like with Values.

Here is how the Electric Field due to Hall Voltage equation looks like with Units.

Here is how the Electric Field due to Hall Voltage equation looks like.

1.8889 = \frac{0.85}{0.45}

1.8889V/m = \frac{0.85V}{0.45m}

1.8889 = \frac{0.85}{0.45}

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Electric Field due to Hall Voltage Solution

Follow our step by step solution on how to calculate Electric Field due to Hall Voltage?

FIRST Step Consider the formula

E H = \frac{V h}{d}

Next Step Substitute values of Variables

∴

E H = \frac{0.85V}{0.45m}

Next Step Prepare to Evaluate

∴

E H = \frac{0.85}{0.45}

Next Step Evaluate

∴

E H = 1.88888888888889V/m

LAST Step Rounding Answer

∴

E H = 1.8889V/m

Electric Field due to Hall Voltage Formula Elements

Variables

Hall Electric Field

Hall Electric Field phenomenon that occurs in a conductor when a current flows through it in the presence of a perpendicular magnetic field.

Symbol: E_H

Measurement: Electric Field StrengthUnit: V/m

Note: Value can be positive or negative.

Formulas to find Hall Electric Field

Hall Voltage

Hall voltage states that if a metal or a semiconductor carrying a current I which is placed in transverse magnetic field B, an electric field is induced in a direction perpendicular to both I and B.

Symbol: V_h

Measurement: Electric PotentialUnit: V

Note: Value should be between -10000 to 10000.

Formulas to find Hall Voltage

Conductor Width

Conductor Width is defined as the width of the conductor perpendicular to both the current direction and the magnetic field direction.

Symbol: d

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Conductor Width

Other formulas in Semiconductor Characteristics category

Go Fermi Level of Intrinsic Semiconductors

E Fi = \frac{E c + E v}{2}

Go Mobility of Charge Carriers

μ = \frac{V d}{E I}

Go Electron Diffusion Length

L n = \sqrt{D n \cdot τ n}

Go Conductivity in Semiconductors

σ = (ρ e \cdot [Charge-e] \cdot μ n) + (ρ h \cdot [Charge-e] \cdot μ p)

How to Evaluate Electric Field due to Hall Voltage?

Electric Field due to Hall Voltage evaluator uses Hall Electric Field = Hall Voltage/Conductor Width to evaluate the Hall Electric Field, Electric Field due to Hall Voltage is a phenomenon that occurs in a conductor when a current flows through it in the presence of a perpendicular magnetic field. This phenomenon is known as the Hall effect. Hall Electric Field is denoted by E_H symbol.

How to evaluate Electric Field due to Hall Voltage using this online evaluator? To use this online evaluator for Electric Field due to Hall Voltage, enter Hall Voltage (V_h) & Conductor Width (d) and hit the calculate button.

FAQs on Electric Field due to Hall Voltage

What is the formula to find Electric Field due to Hall Voltage?

The formula of Electric Field due to Hall Voltage is expressed as Hall Electric Field = Hall Voltage/Conductor Width. Here is an example- 1.888889 = 0.85/0.45.

How to calculate Electric Field due to Hall Voltage?

With Hall Voltage (V_h) & Conductor Width (d) we can find Electric Field due to Hall Voltage using the formula - Hall Electric Field = Hall Voltage/Conductor Width.

Can the Electric Field due to Hall Voltage be negative?

Yes, the Electric Field due to Hall Voltage, measured in Electric Field Strength can be negative.

Which unit is used to measure Electric Field due to Hall Voltage?

Electric Field due to Hall Voltage is usually measured using the Volt per Meter[V/m] for Electric Field Strength. Kilovolt per Meter[V/m], Millivolt per Meter[V/m], Microvolt per Meter[V/m] are the few other units in which Electric Field due to Hall Voltage can be measured.

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