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Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula

GoEffectiveness NTU method Formula

GoEffectiveness in double pipe parallel flow heat exchanger Formula

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The effectiveness of heat exchanger is defined as the ratio of the actual heat transfer to the maximum possible heat transfer. Check FAQs

ϵ = \frac{1}{2 \cdot (1 + C + ({(1 + (C^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- NTU \cdot ({(1 + (C^{2}))}^{0.5}))}{1 - \exp (- NTU \cdot ({(1 + (C^{2}))}^{0.5}))})))}

ϵ - Effectiveness of Heat Exchanger?C - Heat capacity ratio?NTU - Number of Transfer Units?

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Example

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Here is how the Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like with Values.

Here is how the Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like with Units.

Here is how the Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass equation looks like.

0.191 = \frac{1}{2 \cdot (1 + 0.5 + ({(1 + ({0.5}^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))}{1 - \exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))})))}

0.191 = \frac{1}{2 \cdot (1 + 0.5 + ({(1 + ({0.5}^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))}{1 - \exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))})))}

0.191 = \frac{1}{2 \cdot (1 + 0.5 + ({(1 + ({0.5}^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))}{1 - \exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))})))}

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Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Solution

Follow our step by step solution on how to calculate Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass?

FIRST Step Consider the formula

ϵ = \frac{1}{2 \cdot (1 + C + ({(1 + (C^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- NTU \cdot ({(1 + (C^{2}))}^{0.5}))}{1 - \exp (- NTU \cdot ({(1 + (C^{2}))}^{0.5}))})))}

Next Step Substitute values of Variables

∴

ϵ = \frac{1}{2 \cdot (1 + 0.5 + ({(1 + ({0.5}^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))}{1 - \exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))})))}

Next Step Prepare to Evaluate

∴

ϵ = \frac{1}{2 \cdot (1 + 0.5 + ({(1 + ({0.5}^{2}))}^{0.5}) \cdot ((1 + \frac{\exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))}{1 - \exp (- 12 \cdot ({(1 + ({0.5}^{2}))}^{0.5}))})))}

Next Step Evaluate

∴

ϵ = 0.19098288406163

LAST Step Rounding Answer

∴

ϵ = 0.191

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula Elements

Variables

Functions

Effectiveness of Heat Exchanger

The effectiveness of heat exchanger is defined as the ratio of the actual heat transfer to the maximum possible heat transfer.

Symbol: ϵ

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Effectiveness of Heat Exchanger

Heat capacity ratio

Heat capacity ratio is the ratio of cmin and cmax.

Symbol: C

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Heat capacity ratio

Number of Transfer Units

The number of transfer units is defined as ratio of overall thermal conductance to smaller heat capacity rate. NTU designates non-dimensional heat transfer size or thermal size of the exchanger.

Symbol: NTU

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Number of Transfer Units

exp

n an exponential function, the value of the function changes by a constant factor for every unit change in the independent variable.

Syntax: exp(Number)

Other Formulas to find Effectiveness of Heat Exchanger

Go Effectiveness NTU method

ϵ = \frac{Q}{C min \cdot (T1 - t1)}

Go Effectiveness in double pipe parallel flow heat exchanger

ϵ = \frac{1 - \exp (- 1 \cdot NTU \cdot (1 + C))}{1 + C}

Go Effectiveness of double pipe counter flow heat exchanger

ϵ = \frac{1 - \exp (- 1 \cdot NTU \cdot (1 - C))}{1 - C \cdot \exp (- 1 \cdot NTU \cdot (1 - C))}

Go Effectiveness of double pipe counter flow heat exchanger given C equal to 1

ϵ = \frac{NTU}{1 + NTU}

How to Evaluate Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass?

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass evaluator uses Effectiveness of Heat Exchanger = 1/(2*(1+Heat capacity ratio+((1+(Heat capacity ratio^2))^0.5)*((1+exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))/(1-exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))))))) to evaluate the Effectiveness of Heat Exchanger, The Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass formula is defined as the ratio of the actual heat transfer to the maximum possible heat transfer. Effectiveness of Heat Exchanger is denoted by ϵ symbol.

How to evaluate Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass using this online evaluator? To use this online evaluator for Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass, enter Heat capacity ratio (C) & Number of Transfer Units (NTU) and hit the calculate button.

FAQs on Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass

What is the formula to find Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass?

The formula of Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass is expressed as Effectiveness of Heat Exchanger = 1/(2*(1+Heat capacity ratio+((1+(Heat capacity ratio^2))^0.5)*((1+exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))/(1-exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))))))). Here is an example- 0.190983 = 1/(2*(1+0.5+((1+(0.5^2))^0.5)*((1+exp(-12*((1+(0.5^2))^0.5))/(1-exp(-12*((1+(0.5^2))^0.5))))))).

How to calculate Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass?

With Heat capacity ratio (C) & Number of Transfer Units (NTU) we can find Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass using the formula - Effectiveness of Heat Exchanger = 1/(2*(1+Heat capacity ratio+((1+(Heat capacity ratio^2))^0.5)*((1+exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))/(1-exp(-Number of Transfer Units*((1+(Heat capacity ratio^2))^0.5))))))). This formula also uses Exponential Growth (exp) function(s).

What are the other ways to Calculate Effectiveness of Heat Exchanger?

Here are the different ways to Calculate Effectiveness of Heat Exchanger-

Effectiveness of Heat Exchanger=Heat exchanged/(Smaller Value*(Entry Temperature of Hot Fluid-Entry Temperature of Cold Fluid))
Effectiveness of Heat Exchanger=(1-exp(-1*Number of Transfer Units*(1+Heat capacity ratio)))/(1+Heat capacity ratio)
Effectiveness of Heat Exchanger=(1-exp(-1*Number of Transfer Units*(1-Heat capacity ratio)))/(1-Heat capacity ratio*exp(-1*Number of Transfer Units*(1-Heat capacity ratio)))

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Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula

​GoEffectiveness NTU method Formula

​GoEffectiveness in double pipe parallel flow heat exchanger Formula

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Example

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Solution

Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass Formula Elements

Other Formulas to find Effectiveness of Heat Exchanger

How to Evaluate Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass?

FAQs on Effectiveness of heat exchanger with one shell pass and 2, 4, 6 tube pass

Variable Name

GoEffectiveness NTU method Formula

GoEffectiveness in double pipe parallel flow heat exchanger Formula