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Eccentric Load given Minimum Bending Stress Formula

GoEccentric Load given Maximum Bending Stress Formula

GoEccentric Load for given Direct Stress for Circular Section Formula

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Eccentric Load on Column is the load that causes direct stress as well as bending stress. Check FAQs

P = (σb min \cdot (π \cdot (d^{2}))) \cdot \frac{1 - (\frac{8 \cdot e load}{d})}{4}

P - Eccentric Load on Column?σb^min - Minimum Bending Stress?d - Diameter?e_load - Eccentricity of Loading?π - Archimedes' constant?

Eccentric Load given Minimum Bending Stress Example

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Here is how the Eccentric Load given Minimum Bending Stress equation looks like with Values.

Here is how the Eccentric Load given Minimum Bending Stress equation looks like with Units.

Here is how the Eccentric Load given Minimum Bending Stress equation looks like.

6.3664 = (0.402 \cdot (3.1416 \cdot (142^{2}))) \cdot \frac{1 - (\frac{8 \cdot 0.0004}{142})}{4}

6.3664kN = (0.402MPa \cdot (3.1416 \cdot ({142mm}^{2}))) \cdot \frac{1 - (\frac{8 \cdot 0.0004mm}{142mm})}{4}

6.3664 = (0.402 \cdot (3.1416 \cdot (142^{2}))) \cdot \frac{1 - (\frac{8 \cdot 0.0004}{142})}{4}

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Eccentric Load given Minimum Bending Stress Solution

Follow our step by step solution on how to calculate Eccentric Load given Minimum Bending Stress?

FIRST Step Consider the formula

P = (σb min \cdot (π \cdot (d^{2}))) \cdot \frac{1 - (\frac{8 \cdot e load}{d})}{4}

Next Step Substitute values of Variables

∴

P = (0.402MPa \cdot (π \cdot ({142mm}^{2}))) \cdot \frac{1 - (\frac{8 \cdot 0.0004mm}{142mm})}{4}

Next Step Substitute values of Constants

∴

P = (0.402MPa \cdot (3.1416 \cdot ({142mm}^{2}))) \cdot \frac{1 - (\frac{8 \cdot 0.0004mm}{142mm})}{4}

Next Step Convert Units

∴

P = (402009Pa \cdot (3.1416 \cdot ({0.142m}^{2}))) \cdot \frac{1 - (\frac{8 \cdot 4E-7m}{0.142m})}{4}

Next Step Prepare to Evaluate

∴

P = (402009 \cdot (3.1416 \cdot ({0.142}^{2}))) \cdot \frac{1 - (\frac{8 \cdot 4E-7}{0.142})}{4}

Next Step Evaluate

∴

P = 6366.3793064423N

Next Step Convert to Output's Unit

∴

P = 6.3663793064423kN

LAST Step Rounding Answer

∴

P = 6.3664kN

Eccentric Load given Minimum Bending Stress Formula Elements

Variables

Constants

Eccentric Load on Column

Eccentric Load on Column is the load that causes direct stress as well as bending stress.

Symbol: P

Measurement: ForceUnit: kN

Note: Value should be greater than 0.

Formulas to find Eccentric Load on Column

Minimum Bending Stress

Minimum Bending Stress refers to the lowest amount of stress experienced by a material in response to an applied bending moment.

Symbol: σb^min

Measurement: PressureUnit: MPa

Note: Value should be greater than 0.

Formulas to find Minimum Bending Stress

Diameter

Diameter is a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

Symbol: d

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Diameter

Eccentricity of Loading

Eccentricity of Loading is the distance between the actual line of action of loads and the line of action that would produce a uniform stress over the cross section of the specimen.

Symbol: e_load

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Eccentricity of Loading

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other Formulas to find Eccentric Load on Column

Go Eccentric Load given Maximum Bending Stress

P = \frac{M max \cdot (π \cdot (d^{3}))}{32 \cdot e load}

Go Eccentric Load for given Direct Stress for Circular Section

P = \frac{σ \cdot π \cdot (d^{2})}{4}

Other formulas in Middle Quarter Rule for Circular Section category

Go Diameter of Circular Section given Maximum Value of Eccentricity

d = 8 \cdot e load

Go Maximum value of Eccentricity for No Tensile Stress

e load = \frac{d}{8}

Go Condition for Maximum Bending Stress given Diameter

d = 2 \cdot d nl

Go Eccentricity of Load given Minimum Bending Stress

e load = ((\frac{4 \cdot P}{π \cdot (d^{2})}) - σb min) \cdot (\frac{π \cdot (d^{3})}{32 \cdot P})

How to Evaluate Eccentric Load given Minimum Bending Stress?

Eccentric Load given Minimum Bending Stress evaluator uses Eccentric Load on Column = (Minimum Bending Stress*(pi*(Diameter^2)))*(1-((8*Eccentricity of Loading)/Diameter))/4 to evaluate the Eccentric Load on Column, The Eccentric Load given Minimum Bending Stress formula is defined as a measure of the load applied at an offset from the axis of a structural member, which causes both compressive and tensile stresses, and is critical in determining the minimum bending stress that a material can withstand without deforming or failing. Eccentric Load on Column is denoted by P symbol.

How to evaluate Eccentric Load given Minimum Bending Stress using this online evaluator? To use this online evaluator for Eccentric Load given Minimum Bending Stress, enter Minimum Bending Stress (σb^min), Diameter (d) & Eccentricity of Loading (e_load) and hit the calculate button.

FAQs on Eccentric Load given Minimum Bending Stress

What is the formula to find Eccentric Load given Minimum Bending Stress?

The formula of Eccentric Load given Minimum Bending Stress is expressed as Eccentric Load on Column = (Minimum Bending Stress*(pi*(Diameter^2)))*(1-((8*Eccentricity of Loading)/Diameter))/4. Here is an example- 7.9E-5 = (402009*(pi*(0.142^2)))*(1-((8*4.02E-07)/0.142))/4.

How to calculate Eccentric Load given Minimum Bending Stress?

With Minimum Bending Stress (σb^min), Diameter (d) & Eccentricity of Loading (e_load) we can find Eccentric Load given Minimum Bending Stress using the formula - Eccentric Load on Column = (Minimum Bending Stress*(pi*(Diameter^2)))*(1-((8*Eccentricity of Loading)/Diameter))/4. This formula also uses Archimedes' constant .

What are the other ways to Calculate Eccentric Load on Column?

Here are the different ways to Calculate Eccentric Load on Column-

Eccentric Load on Column=(Maximum Bending Moment*(pi*(Diameter^3)))/(32*Eccentricity of Loading)
Eccentric Load on Column=(Direct Stress*pi*(Diameter^2))/4

Can the Eccentric Load given Minimum Bending Stress be negative?

No, the Eccentric Load given Minimum Bending Stress, measured in Force cannot be negative.

Which unit is used to measure Eccentric Load given Minimum Bending Stress?

Eccentric Load given Minimum Bending Stress is usually measured using the Kilonewton[kN] for Force. Newton[kN], Exanewton[kN], Meganewton[kN] are the few other units in which Eccentric Load given Minimum Bending Stress can be measured.

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Eccentric Load given Minimum Bending Stress Formula

​GoEccentric Load given Maximum Bending Stress Formula

​GoEccentric Load for given Direct Stress for Circular Section Formula

Eccentric Load given Minimum Bending Stress Example

Eccentric Load given Minimum Bending Stress Solution

Eccentric Load given Minimum Bending Stress Formula Elements

Other Formulas to find Eccentric Load on Column

Other formulas in Middle Quarter Rule for Circular Section category

How to Evaluate Eccentric Load given Minimum Bending Stress?

FAQs on Eccentric Load given Minimum Bending Stress

Variable Name

GoEccentric Load given Maximum Bending Stress Formula

GoEccentric Load for given Direct Stress for Circular Section Formula