FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Discharge given Time at 1st and 2nd Instance Formula

GoDischarge given Drawdown Formula

GoDischarge given Formation Constant T Formula

Fx Copy

LaTeX Copy

Discharge is the rate of flow of a fluid in unsteady flow. Check FAQs

Q = \frac{Δd}{\frac{2.303 \cdot \log ((\frac{t 2sec}{t1}), 10)}{4 \cdot π \cdot t hr}}

Q - Discharge?Δd - Change in Drawdown?t_2sec - Time of Drawdown (t2) in Wells?t1 - Time of Drawdown (t1) in Wells?t_hr - Time in Hours for Well Discharge?π - Archimedes' constant?

Discharge given Time at 1st and 2nd Instance Example

With values

With units

Only example

Here is how the Discharge given Time at 1st and 2nd Instance equation looks like with Values.

Here is how the Discharge given Time at 1st and 2nd Instance equation looks like with Units.

Here is how the Discharge given Time at 1st and 2nd Instance equation looks like.

1.0732 = \frac{0.23}{\frac{2.303 \cdot \log ((\frac{62}{58.7}), 10)}{4 \cdot 3.1416 \cdot 0.01}}

1.0732m³/s = \frac{0.23m}{\frac{2.303 \cdot \log ((\frac{62s}{58.7s}), 10)}{4 \cdot 3.1416 \cdot 0.01h}}

1.0732 = \frac{0.23}{\frac{2.303 \cdot \log ((\frac{62}{58.7}), 10)}{4 \cdot 3.1416 \cdot 0.01}}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Environmental Engineering » fx Discharge given Time at 1st and 2nd Instance

Discharge given Time at 1st and 2nd Instance Solution

Follow our step by step solution on how to calculate Discharge given Time at 1st and 2nd Instance?

FIRST Step Consider the formula

Q = \frac{Δd}{\frac{2.303 \cdot \log ((\frac{t 2sec}{t1}), 10)}{4 \cdot π \cdot t hr}}

Next Step Substitute values of Variables

∴

Q = \frac{0.23m}{\frac{2.303 \cdot \log ((\frac{62s}{58.7s}), 10)}{4 \cdot π \cdot 0.01h}}

Next Step Substitute values of Constants

∴

Q = \frac{0.23m}{\frac{2.303 \cdot \log ((\frac{62s}{58.7s}), 10)}{4 \cdot 3.1416 \cdot 0.01h}}

Next Step Convert Units

∴

Q = \frac{0.23m}{\frac{2.303 \cdot \log ((\frac{62s}{58.7s}), 10)}{4 \cdot 3.1416 \cdot 36s}}

Next Step Prepare to Evaluate

∴

Q = \frac{0.23}{\frac{2.303 \cdot \log ((\frac{62}{58.7}), 10)}{4 \cdot 3.1416 \cdot 36}}

Next Step Evaluate

∴

Q = 1.07318720676219m³/s

LAST Step Rounding Answer

∴

Q = 1.0732m³/s

Discharge given Time at 1st and 2nd Instance Formula Elements

Variables

Constants

Functions

Discharge

Discharge is the rate of flow of a fluid in unsteady flow.

Symbol: Q

Measurement: Volumetric Flow RateUnit: m³/s

Note: Value can be positive or negative.

Formulas to find Discharge

Change in Drawdown

Change in Drawdown is defined as the difference at the two wells.

Symbol: Δd

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Change in Drawdown

Time of Drawdown (t2) in Wells

Time of Drawdown (t2) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level for wells.

Symbol: t_2sec

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time of Drawdown (t2) in Wells

Time of Drawdown (t1) in Wells

Time of Drawdown (t1) in Wells is the total period for the difference between the pumping water level and the static (non-pumping) water level for wells.

Symbol: t1

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time of Drawdown (t1) in Wells

Time in Hours for Well Discharge

Time in Hours for Well Discharge is the time measured in hours for the discharge in wells.

Symbol: t_hr

Measurement: TimeUnit: h

Note: Value should be greater than 0.

Formulas to find Time in Hours for Well Discharge

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

log

Logarithmic function is an inverse function to exponentiation.

Syntax: log(Base, Number)

Other Formulas to find Discharge

Go Discharge given Drawdown

Q = \frac{4 \cdot π \cdot F c \cdot s t}{W u}

Go Discharge given Formation Constant T

Q = \frac{F c}{\frac{2.303}{4 \cdot π \cdot Δd}}

How to Evaluate Discharge given Time at 1st and 2nd Instance?

Discharge given Time at 1st and 2nd Instance evaluator uses Discharge = Change in Drawdown/((2.303*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Time in Hours for Well Discharge)) to evaluate the Discharge, Discharge given Time at 1st and 2nd Instance formula is defined as a measure of the rate of fluid flow in an unsteady flow context, where the flow rate varies with time, and is used to quantify the amount of fluid that passes through a given surface per unit time. Discharge is denoted by Q symbol.

How to evaluate Discharge given Time at 1st and 2nd Instance using this online evaluator? To use this online evaluator for Discharge given Time at 1st and 2nd Instance, enter Change in Drawdown (Δd), Time of Drawdown (t2) in Wells (t_2sec), Time of Drawdown (t1) in Wells (t1) & Time in Hours for Well Discharge (t_hr) and hit the calculate button.

FAQs on Discharge given Time at 1st and 2nd Instance

What is the formula to find Discharge given Time at 1st and 2nd Instance?

The formula of Discharge given Time at 1st and 2nd Instance is expressed as Discharge = Change in Drawdown/((2.303*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Time in Hours for Well Discharge)). Here is an example- 1.073187 = 0.23/((2.303*log((62/58.7),10))/(4*pi*36)).

How to calculate Discharge given Time at 1st and 2nd Instance?

With Change in Drawdown (Δd), Time of Drawdown (t2) in Wells (t_2sec), Time of Drawdown (t1) in Wells (t1) & Time in Hours for Well Discharge (t_hr) we can find Discharge given Time at 1st and 2nd Instance using the formula - Discharge = Change in Drawdown/((2.303*log((Time of Drawdown (t2) in Wells/Time of Drawdown (t1) in Wells),10))/(4*pi*Time in Hours for Well Discharge)). This formula also uses Archimedes' constant and Logarithmic Inverse (log) function(s).

What are the other ways to Calculate Discharge?

Here are the different ways to Calculate Discharge-

Discharge=(4*pi*Formation Constant for Unsteady Flow*Total Drawdown in Well)/Well Function of u
Discharge=Formation Constant for Unsteady Flow/((2.303)/(4*pi*Change in Drawdown))

Can the Discharge given Time at 1st and 2nd Instance be negative?

Yes, the Discharge given Time at 1st and 2nd Instance, measured in Volumetric Flow Rate can be negative.

Which unit is used to measure Discharge given Time at 1st and 2nd Instance?

Discharge given Time at 1st and 2nd Instance is usually measured using the Cubic Meter per Second[m³/s] for Volumetric Flow Rate. Cubic Meter per Day[m³/s], Cubic Meter per Hour[m³/s], Cubic Meter per Minute[m³/s] are the few other units in which Discharge given Time at 1st and 2nd Instance can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Discharge given Time at 1st and 2nd Instance Formula

​GoDischarge given Drawdown Formula

​GoDischarge given Formation Constant T Formula

Discharge given Time at 1st and 2nd Instance Example

Discharge given Time at 1st and 2nd Instance Solution

Discharge given Time at 1st and 2nd Instance Formula Elements

Other Formulas to find Discharge

How to Evaluate Discharge given Time at 1st and 2nd Instance?

FAQs on Discharge given Time at 1st and 2nd Instance

Variable Name

GoDischarge given Drawdown Formula

GoDischarge given Formation Constant T Formula