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Dielectric Loss due to Heating in Cables Formula

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Dielectric Loss is loss of energy that goes into heating a dielectric material in a varying electric field. Check FAQs

D f = ω \cdot C \cdot V^{2} \cdot \tan (∠δ)

D_f - Dielectric Loss?ω - Angular Frequency?C - Capacitance?V - Voltage?∠δ - Loss Angle?

Dielectric Loss due to Heating in Cables Example

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Here is how the Dielectric Loss due to Heating in Cables equation looks like with Values.

Here is how the Dielectric Loss due to Heating in Cables equation looks like with Units.

Here is how the Dielectric Loss due to Heating in Cables equation looks like.

232.7876 = 10 \cdot 2.8 \cdot 120^{2} \cdot \tan (30)

232.7876W = 10rad/s \cdot 2.8mF \cdot {120V}^{2} \cdot \tan (30°)

232.7876 = 10 \cdot 2.8 \cdot 120^{2} \cdot \tan (30)

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Dielectric Loss due to Heating in Cables Solution

Follow our step by step solution on how to calculate Dielectric Loss due to Heating in Cables?

FIRST Step Consider the formula

D f = ω \cdot C \cdot V^{2} \cdot \tan (∠δ)

Next Step Substitute values of Variables

∴

D f = 10rad/s \cdot 2.8mF \cdot {120V}^{2} \cdot \tan (30°)

Next Step Convert Units

∴

D f = 10rad/s \cdot 0.0028F \cdot {120V}^{2} \cdot \tan (0.5236rad)

Next Step Prepare to Evaluate

∴

D f = 10 \cdot 0.0028 \cdot 120^{2} \cdot \tan (0.5236)

Next Step Evaluate

∴

D f = 232.787628537257W

LAST Step Rounding Answer

∴

D f = 232.7876W

Dielectric Loss due to Heating in Cables Formula Elements

Variables

Functions

Dielectric Loss

Dielectric Loss is loss of energy that goes into heating a dielectric material in a varying electric field.

Symbol: D_f

Measurement: PowerUnit: W

Note: Value should be greater than 0.

Formulas to find Dielectric Loss

Angular Frequency

Angular Frequency of a steadily recurring phenomenon expressed in radians per second.

Symbol: ω

Measurement: Angular FrequencyUnit: rad/s

Note: Value should be greater than 0.

Formulas to find Angular Frequency

Capacitance

Capacitance is defined as the ratio of the amount of electric charge stored on a conductor to a difference in electric potential.

Symbol: C

Measurement: CapacitanceUnit: mF

Note: Value should be greater than 0.

Formulas to find Capacitance

Voltage

Voltage, electric potential difference, electric pressure, is the difference in electric potential between two points.

Symbol: V

Measurement: Electric PotentialUnit: V

Note: Value should be greater than 0.

Formulas to find Voltage

Loss Angle

Loss Angle is defined as measure of the power loss is equal to the amount by which the angle between the phasors denoting voltage and current across the inductor or capacitor differs.

Symbol: ∠δ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Loss Angle

tan

The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle.

Syntax: tan(Angle)

Other formulas in Line Performance Characteristics category

Go Complex Power given Current

S = I^{2} \cdot Z

Go Skin Depth in Conductor

δ = \sqrt{\frac{R s}{f \cdot μ r \cdot 4 \cdot π \cdot 10^{- 7}}}

Go Base Impedance given Base Current

Z base = \frac{V base}{I pu(b)}

Go Base Power

P b = V base \cdot I b

How to Evaluate Dielectric Loss due to Heating in Cables?

Dielectric Loss due to Heating in Cables evaluator uses Dielectric Loss = Angular Frequency*Capacitance*Voltage^2*tan(Loss Angle) to evaluate the Dielectric Loss, Dielectric Loss due to heating in cables formula is defined as the product of angular frequency, capacitance, square of voltage with tangent angle. Dielectric Loss is denoted by D_f symbol.

How to evaluate Dielectric Loss due to Heating in Cables using this online evaluator? To use this online evaluator for Dielectric Loss due to Heating in Cables, enter Angular Frequency (ω), Capacitance (C), Voltage (V) & Loss Angle (∠δ) and hit the calculate button.

FAQs on Dielectric Loss due to Heating in Cables

What is the formula to find Dielectric Loss due to Heating in Cables?

The formula of Dielectric Loss due to Heating in Cables is expressed as Dielectric Loss = Angular Frequency*Capacitance*Voltage^2*tan(Loss Angle). Here is an example- 232.7876 = 10*0.0028*120^2*tan(0.5235987755982).

How to calculate Dielectric Loss due to Heating in Cables?

With Angular Frequency (ω), Capacitance (C), Voltage (V) & Loss Angle (∠δ) we can find Dielectric Loss due to Heating in Cables using the formula - Dielectric Loss = Angular Frequency*Capacitance*Voltage^2*tan(Loss Angle). This formula also uses Tangent (tan) function(s).

Can the Dielectric Loss due to Heating in Cables be negative?

No, the Dielectric Loss due to Heating in Cables, measured in Power cannot be negative.

Which unit is used to measure Dielectric Loss due to Heating in Cables?

Dielectric Loss due to Heating in Cables is usually measured using the Watt[W] for Power. Kilowatt[W], Milliwatt[W], Microwatt[W] are the few other units in which Dielectric Loss due to Heating in Cables can be measured.

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Dielectric Loss due to Heating in Cables Formula

Dielectric Loss due to Heating in Cables Example

Dielectric Loss due to Heating in Cables Solution

Dielectric Loss due to Heating in Cables Formula Elements

Other formulas in Line Performance Characteristics category

How to Evaluate Dielectric Loss due to Heating in Cables?

FAQs on Dielectric Loss due to Heating in Cables

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