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Diameter of shaft given polar moment of inertia of shaft Formula

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The Diameter of Shaft is the diameter of the external surface of a shaft which is a rotating element in the transmitting system for transmitting power. Check FAQs

d s = {(\frac{32 \cdot J shaft}{π})}^{\frac{1}{4}}

d_s - Diameter of Shaft?J_shaft - Polar Moment of Inertia of shaft?π - Archimedes' constant?

Diameter of shaft given polar moment of inertia of shaft Example

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Here is how the Diameter of shaft given polar moment of inertia of shaft equation looks like with Values.

Here is how the Diameter of shaft given polar moment of inertia of shaft equation looks like with Units.

Here is how the Diameter of shaft given polar moment of inertia of shaft equation looks like.

3176.8743 = {(\frac{32 \cdot 10}{3.1416})}^{\frac{1}{4}}

3176.8743mm = {(\frac{32 \cdot 10m⁴}{3.1416})}^{\frac{1}{4}}

3176.8743 = {(\frac{32 \cdot 10}{3.1416})}^{\frac{1}{4}}

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Diameter of shaft given polar moment of inertia of shaft Solution

Follow our step by step solution on how to calculate Diameter of shaft given polar moment of inertia of shaft?

FIRST Step Consider the formula

d s = {(\frac{32 \cdot J shaft}{π})}^{\frac{1}{4}}

Next Step Substitute values of Variables

∴

d s = {(\frac{32 \cdot 10m⁴}{π})}^{\frac{1}{4}}

Next Step Substitute values of Constants

∴

d s = {(\frac{32 \cdot 10m⁴}{3.1416})}^{\frac{1}{4}}

Next Step Prepare to Evaluate

∴

d s = {(\frac{32 \cdot 10}{3.1416})}^{\frac{1}{4}}

Next Step Evaluate

∴

d s = 3.17687426381351m

Next Step Convert to Output's Unit

∴

d s = 3176.87426381351mm

LAST Step Rounding Answer

∴

d s = 3176.8743mm

Diameter of shaft given polar moment of inertia of shaft Formula Elements

Variables

Constants

Diameter of Shaft

The Diameter of Shaft is the diameter of the external surface of a shaft which is a rotating element in the transmitting system for transmitting power.

Symbol: d_s

Measurement: LengthUnit: mm

Note: Value should be greater than 0.

Formulas to find Diameter of Shaft

Polar Moment of Inertia of shaft

Polar Moment of Inertia of shaft is the measure of object resistance to torsion.

Symbol: J_shaft

Measurement: Second Moment of AreaUnit: m⁴

Note: Value can be positive or negative.

Formulas to find Polar Moment of Inertia of shaft

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

Other formulas in Expression for Torque in terms of Polar Moment of Inertia category

Go Modulus of Rigidity of Shaft given Torque Transmitted and Polar Moment of Inertia

C = \frac{τ \cdot L}{θ \cdot J shaft}

Go Polar Moment of Inertia of Shaft given Torque Transmitted and Modulus of Rigidity

J shaft = \frac{τ \cdot L}{C \cdot θ}

Go Length of Shaft given Polar Moment of Inertia and Modulus of Rigidity

L = \frac{C \cdot θ \cdot J shaft}{τ}

Go Angle of Twist for Shaft given Polar Moment of Inertia and Modulus of Rigidity

θ = \frac{τ \cdot L}{C \cdot J shaft}

How to Evaluate Diameter of shaft given polar moment of inertia of shaft?

Diameter of shaft given polar moment of inertia of shaft evaluator uses Diameter of Shaft = ((32*Polar Moment of Inertia of shaft)/pi)^(1/4) to evaluate the Diameter of Shaft, Diameter of shaft given polar moment of inertia of shaft is defined as a chord that runs through the center point of the circle. Diameter of Shaft is denoted by d_s symbol.

How to evaluate Diameter of shaft given polar moment of inertia of shaft using this online evaluator? To use this online evaluator for Diameter of shaft given polar moment of inertia of shaft, enter Polar Moment of Inertia of shaft (J_shaft) and hit the calculate button.

FAQs on Diameter of shaft given polar moment of inertia of shaft

What is the formula to find Diameter of shaft given polar moment of inertia of shaft?

The formula of Diameter of shaft given polar moment of inertia of shaft is expressed as Diameter of Shaft = ((32*Polar Moment of Inertia of shaft)/pi)^(1/4). Here is an example- 3.2E+6 = ((32*10)/pi)^(1/4).

How to calculate Diameter of shaft given polar moment of inertia of shaft?

With Polar Moment of Inertia of shaft (J_shaft) we can find Diameter of shaft given polar moment of inertia of shaft using the formula - Diameter of Shaft = ((32*Polar Moment of Inertia of shaft)/pi)^(1/4). This formula also uses Archimedes' constant .

Can the Diameter of shaft given polar moment of inertia of shaft be negative?

No, the Diameter of shaft given polar moment of inertia of shaft, measured in Length cannot be negative.

Which unit is used to measure Diameter of shaft given polar moment of inertia of shaft?

Diameter of shaft given polar moment of inertia of shaft is usually measured using the Millimeter[mm] for Length. Meter[mm], Kilometer[mm], Decimeter[mm] are the few other units in which Diameter of shaft given polar moment of inertia of shaft can be measured.

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