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Diagonal of Hendecagon across Five Sides given Area Formula

GoDiagonal of Hendecagon across Five Sides Formula

GoDiagonal of Hendecagon across Five Sides given Height Formula

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Diagonal across Five Sides of Hendecagon is a straight line joining two non-adjacent sides across five sides of the Hendecagon. Check FAQs

d 5 = \sqrt{\frac{4 \cdot A \cdot \tan (\frac{π}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

d₅ - Diagonal across Five Sides of Hendecagon?A - Area of Hendecagon?π - Archimedes' constant?

Diagonal of Hendecagon across Five Sides given Area Example

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Here is how the Diagonal of Hendecagon across Five Sides given Area equation looks like with Values.

Here is how the Diagonal of Hendecagon across Five Sides given Area equation looks like with Units.

Here is how the Diagonal of Hendecagon across Five Sides given Area equation looks like.

17.5989 = \sqrt{\frac{4 \cdot 235 \cdot \tan (\frac{3.1416}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot 3.1416}{11})}{\sin (\frac{3.1416}{11})}

17.5989m = \sqrt{\frac{4 \cdot 235m² \cdot \tan (\frac{3.1416}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot 3.1416}{11})}{\sin (\frac{3.1416}{11})}

17.5989 = \sqrt{\frac{4 \cdot 235 \cdot \tan (\frac{3.1416}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot 3.1416}{11})}{\sin (\frac{3.1416}{11})}

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Diagonal of Hendecagon across Five Sides given Area Solution

Follow our step by step solution on how to calculate Diagonal of Hendecagon across Five Sides given Area?

FIRST Step Consider the formula

d 5 = \sqrt{\frac{4 \cdot A \cdot \tan (\frac{π}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

Next Step Substitute values of Variables

∴

d 5 = \sqrt{\frac{4 \cdot 235m² \cdot \tan (\frac{π}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

Next Step Substitute values of Constants

∴

d 5 = \sqrt{\frac{4 \cdot 235m² \cdot \tan (\frac{3.1416}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot 3.1416}{11})}{\sin (\frac{3.1416}{11})}

Next Step Prepare to Evaluate

∴

d 5 = \sqrt{\frac{4 \cdot 235 \cdot \tan (\frac{3.1416}{11})}{11}} \cdot \frac{\sin (\frac{5 \cdot 3.1416}{11})}{\sin (\frac{3.1416}{11})}

Next Step Evaluate

∴

d 5 = 17.5988797536418m

LAST Step Rounding Answer

∴

d 5 = 17.5989m

Diagonal of Hendecagon across Five Sides given Area Formula Elements

Variables

Constants

Functions

Diagonal across Five Sides of Hendecagon

Diagonal across Five Sides of Hendecagon is a straight line joining two non-adjacent sides across five sides of the Hendecagon.

Symbol: d₅

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Diagonal across Five Sides of Hendecagon

Area of Hendecagon

Area of Hendecagon is the amount of 2-dimensional space occupied by the Hendecagon.

Symbol: A

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Area of Hendecagon

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

tan

The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle.

Syntax: tan(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Diagonal across Five Sides of Hendecagon

Go Diagonal of Hendecagon across Five Sides

d 5 = \frac{S \cdot \sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

Go Diagonal of Hendecagon across Five Sides given Height

d 5 = 2 \cdot \tan (\frac{π}{22}) \cdot h \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

Go Diagonal of Hendecagon across Five Sides given Perimeter

d 5 = \frac{P}{11} \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

Go Diagonal of Hendecagon across Five Sides given Inradius

d 5 = 2 \cdot \tan (\frac{π}{11}) \cdot r i \cdot \frac{\sin (\frac{5 \cdot π}{11})}{\sin (\frac{π}{11})}

How to Evaluate Diagonal of Hendecagon across Five Sides given Area?

Diagonal of Hendecagon across Five Sides given Area evaluator uses Diagonal across Five Sides of Hendecagon = sqrt((4*Area of Hendecagon*tan(pi/11))/11)*sin((5*pi)/11)/sin(pi/11) to evaluate the Diagonal across Five Sides of Hendecagon, The Diagonal of Hendecagon across Five Sides given Area formula is defined as the straight line connecting two non-adjacent vertices across five sides of Hendecagon, calculated using area. Diagonal across Five Sides of Hendecagon is denoted by d₅ symbol.

How to evaluate Diagonal of Hendecagon across Five Sides given Area using this online evaluator? To use this online evaluator for Diagonal of Hendecagon across Five Sides given Area, enter Area of Hendecagon (A) and hit the calculate button.

FAQs on Diagonal of Hendecagon across Five Sides given Area

What is the formula to find Diagonal of Hendecagon across Five Sides given Area?

The formula of Diagonal of Hendecagon across Five Sides given Area is expressed as Diagonal across Five Sides of Hendecagon = sqrt((4*Area of Hendecagon*tan(pi/11))/11)*sin((5*pi)/11)/sin(pi/11). Here is an example- 17.59888 = sqrt((4*235*tan(pi/11))/11)*sin((5*pi)/11)/sin(pi/11).

How to calculate Diagonal of Hendecagon across Five Sides given Area?

With Area of Hendecagon (A) we can find Diagonal of Hendecagon across Five Sides given Area using the formula - Diagonal across Five Sides of Hendecagon = sqrt((4*Area of Hendecagon*tan(pi/11))/11)*sin((5*pi)/11)/sin(pi/11). This formula also uses Archimedes' constant and , Sine (sin), Tangent (tan), Square Root (sqrt) function(s).

What are the other ways to Calculate Diagonal across Five Sides of Hendecagon?

Here are the different ways to Calculate Diagonal across Five Sides of Hendecagon-

Diagonal across Five Sides of Hendecagon=(Side of Hendecagon*sin((5*pi)/11))/sin(pi/11)
Diagonal across Five Sides of Hendecagon=2*tan(pi/22)*Height of Hendecagon*sin((5*pi)/11)/sin(pi/11)
Diagonal across Five Sides of Hendecagon=Perimeter of Hendecagon/11*sin((5*pi)/11)/sin(pi/11)

Can the Diagonal of Hendecagon across Five Sides given Area be negative?

No, the Diagonal of Hendecagon across Five Sides given Area, measured in Length cannot be negative.

Which unit is used to measure Diagonal of Hendecagon across Five Sides given Area?

Diagonal of Hendecagon across Five Sides given Area is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Diagonal of Hendecagon across Five Sides given Area can be measured.

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