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Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula

GoDepression Head in well given pumping stopped and clay soil is present Formula

GoDepression Head in Well given Pumping Stopped and Fine Sand is Present Formula

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Depression Head is the difference of level of waters table and the water level in the well when pumping stopped. Check FAQs

h d = h w2 \cdot 10^{\frac{0.25 \cdot Δt}{2.303}}

h_d - Depression Head?h_w2 - Depression Head in Well 2?Δt - Total Time Interval?

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Example

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Here is how the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present equation looks like with Values.

Here is how the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present equation looks like with Units.

Here is how the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present equation looks like.

34.8956 = 10 \cdot 10^{\frac{0.25 \cdot 5}{2.303}}

34.8956m = 10m \cdot 10^{\frac{0.25 \cdot 5s}{2.303}}

34.8956 = 10 \cdot 10^{\frac{0.25 \cdot 5}{2.303}}

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Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Solution

Follow our step by step solution on how to calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

FIRST Step Consider the formula

h d = h w2 \cdot 10^{\frac{0.25 \cdot Δt}{2.303}}

Next Step Substitute values of Variables

∴

h d = 10m \cdot 10^{\frac{0.25 \cdot 5s}{2.303}}

Next Step Prepare to Evaluate

∴

h d = 10 \cdot 10^{\frac{0.25 \cdot 5}{2.303}}

Next Step Evaluate

∴

h d = 34.895570235195m

LAST Step Rounding Answer

∴

h d = 34.8956m

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula Elements

Variables

Depression Head

Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.

Symbol: h_d

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head

Depression Head in Well 2

Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

Symbol: h_w2

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head in Well 2

Total Time Interval

Total Time Interval is the amount of time required for the total change in concentration.

Symbol: Δt

Measurement: TimeUnit: s

Note: Value can be positive or negative.

Formulas to find Total Time Interval

Other Formulas to find Depression Head

Go Depression Head in well given pumping stopped and clay soil is present

h d = h w2 \cdot \exp (0.25 \cdot Δt)

Go Depression Head in Well given Pumping Stopped and Fine Sand is Present

h d = h w2 \cdot \exp (0.5 \cdot Δ t)

Go Depression Head in Well given Pumping Stopped and Coarse Sand is Present

h d = h w2 \cdot \exp (1 \cdot Δ t)

Go Depression Head in Well given Pumping Stopped with Base 10 and Coarse Sand is Present

h d = h w2 \cdot 10^{\frac{1 \cdot Δ t}{2.303}}

How to Evaluate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present evaluator uses Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303) to evaluate the Depression Head, The Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present formula is defined as the calculation of the value of depression head when we have prior information of other parameters used. Depression Head is denoted by h_d symbol.

How to evaluate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present using this online evaluator? To use this online evaluator for Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present, enter Depression Head in Well 2 (h_w2) & Total Time Interval (Δt) and hit the calculate button.

FAQs on Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present

What is the formula to find Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

The formula of Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present is expressed as Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303). Here is an example- 34.89557 = 10*10^((0.25*5)/2.303).

How to calculate Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

With Depression Head in Well 2 (h_w2) & Total Time Interval (Δt) we can find Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present using the formula - Depression Head = Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303).

What are the other ways to Calculate Depression Head?

Here are the different ways to Calculate Depression Head-

Depression Head=Depression Head in Well 2*exp(0.25*Total Time Interval)
Depression Head=Depression Head in Well 2*exp(0.5*Time Interval)
Depression Head=Depression Head in Well 2*exp(1*Time Interval)

Can the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present be negative?

No, the Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present, measured in Length cannot be negative.

Which unit is used to measure Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present?

Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present can be measured.

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