FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula

GoDepression Head in well given pumping stopped and clay soil is present Formula

GoDepression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula

Fx Copy

LaTeX Copy

Depression Head is the difference of level of waters table and the water level in the well when pumping stopped. Check FAQs

h d = h w2 \cdot 10^{\frac{K \cdot t}{A cs \cdot 2.303}}

h_d - Depression Head?h_w2 - Depression Head in Well 2?K - Constant?t - Time?A_cs - Cross Sectional Area?

Depression Head in Well given Pumping Stopped and Constant with Base 10 Example

With values

With units

Only example

Here is how the Depression Head in Well given Pumping Stopped and Constant with Base 10 equation looks like with Values.

Here is how the Depression Head in Well given Pumping Stopped and Constant with Base 10 equation looks like with Units.

Here is how the Depression Head in Well given Pumping Stopped and Constant with Base 10 equation looks like.

27.1779 = 10 \cdot 10^{\frac{5 \cdot 4}{20 \cdot 2.303}}

27.1779m = 10m \cdot 10^{\frac{5 \cdot 4h}{20m² \cdot 2.303}}

27.1779 = 10 \cdot 10^{\frac{5 \cdot 4}{20 \cdot 2.303}}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Environmental Engineering » fx Depression Head in Well given Pumping Stopped and Constant with Base 10

Depression Head in Well given Pumping Stopped and Constant with Base 10 Solution

Follow our step by step solution on how to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?

FIRST Step Consider the formula

h d = h w2 \cdot 10^{\frac{K \cdot t}{A cs \cdot 2.303}}

Next Step Substitute values of Variables

∴

h d = 10m \cdot 10^{\frac{5 \cdot 4h}{20m² \cdot 2.303}}

Next Step Prepare to Evaluate

∴

h d = 10 \cdot 10^{\frac{5 \cdot 4}{20 \cdot 2.303}}

Next Step Evaluate

∴

h d = 27.177921486562m

LAST Step Rounding Answer

∴

h d = 27.1779m

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula Elements

Variables

Depression Head

Depression Head is the difference of level of waters table and the water level in the well when pumping stopped.

Symbol: h_d

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head

Depression Head in Well 2

Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

Symbol: h_w2

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head in Well 2

Constant

Constant depending on the soil at the base of the well.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant

Time

Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.

Symbol: t

Measurement: TimeUnit: h

Note: Value should be greater than 0.

Formulas to find Time

Cross Sectional Area

Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.

Symbol: A_cs

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross Sectional Area

Other Formulas to find Depression Head

Go Depression Head in well given pumping stopped and clay soil is present

h d = h w2 \cdot \exp (0.25 \cdot Δt)

Go Depression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present

h d = h w2 \cdot 10^{\frac{0.25 \cdot Δt}{2.303}}

Go Depression Head in Well given Pumping Stopped and Fine Sand is Present

h d = h w2 \cdot \exp (0.5 \cdot Δ t)

Go Depression Head in Well given Pumping Stopped and Coarse Sand is Present

h d = h w2 \cdot \exp (1 \cdot Δ t)

How to Evaluate Depression Head in Well given Pumping Stopped and Constant with Base 10?

Depression Head in Well given Pumping Stopped and Constant with Base 10 evaluator uses Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)) to evaluate the Depression Head, The Depression Head in Well given Pumping Stopped and Constant with Base 10 formula is defined as the calculation of the value of depression head in well when we have prior information of other parameters used. Depression Head is denoted by h_d symbol.

How to evaluate Depression Head in Well given Pumping Stopped and Constant with Base 10 using this online evaluator? To use this online evaluator for Depression Head in Well given Pumping Stopped and Constant with Base 10, enter Depression Head in Well 2 (h_w2), Constant (K), Time (t) & Cross Sectional Area (A_cs) and hit the calculate button.

FAQs on Depression Head in Well given Pumping Stopped and Constant with Base 10

What is the formula to find Depression Head in Well given Pumping Stopped and Constant with Base 10?

The formula of Depression Head in Well given Pumping Stopped and Constant with Base 10 is expressed as Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)). Here is an example- 27.17792 = 10*10^((5*14400)/(20*2.303)).

How to calculate Depression Head in Well given Pumping Stopped and Constant with Base 10?

With Depression Head in Well 2 (h_w2), Constant (K), Time (t) & Cross Sectional Area (A_cs) we can find Depression Head in Well given Pumping Stopped and Constant with Base 10 using the formula - Depression Head = Depression Head in Well 2*10^((Constant*Time)/(Cross Sectional Area*2.303)).

What are the other ways to Calculate Depression Head?

Here are the different ways to Calculate Depression Head-

Depression Head=Depression Head in Well 2*exp(0.25*Total Time Interval)
Depression Head=Depression Head in Well 2*10^((0.25*Total Time Interval)/2.303)
Depression Head=Depression Head in Well 2*exp(0.5*Time Interval)

Can the Depression Head in Well given Pumping Stopped and Constant with Base 10 be negative?

No, the Depression Head in Well given Pumping Stopped and Constant with Base 10, measured in Length cannot be negative.

Which unit is used to measure Depression Head in Well given Pumping Stopped and Constant with Base 10?

Depression Head in Well given Pumping Stopped and Constant with Base 10 is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Depression Head in Well given Pumping Stopped and Constant with Base 10 can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula

​GoDepression Head in well given pumping stopped and clay soil is present Formula

​GoDepression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula

Depression Head in Well given Pumping Stopped and Constant with Base 10 Example

Depression Head in Well given Pumping Stopped and Constant with Base 10 Solution

Depression Head in Well given Pumping Stopped and Constant with Base 10 Formula Elements

Other Formulas to find Depression Head

How to Evaluate Depression Head in Well given Pumping Stopped and Constant with Base 10?

FAQs on Depression Head in Well given Pumping Stopped and Constant with Base 10

Variable Name

GoDepression Head in well given pumping stopped and clay soil is present Formula

GoDepression Head in Well given Pumping Stopped with Base 10 and Clay soil is Present Formula