FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Formula

Fx Copy

LaTeX Copy

Cross-Sectional Area given Specific Capacity is the cross-sectional area of the wellbore through which water flows. Check FAQs

A sec = \frac{K b}{(\frac{2.303}{t}) \cdot \log ((\frac{h1'}{h w2}), 10)}

A_sec - Cross-Sectional Area given Specific Capacity?K_b - Constant Dependent on Base Soil?t - Time?h1' - Depression Head in Well?h_w2 - Depression Head in Well 2?

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Example

With values

With units

Only example

Here is how the Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 equation looks like with Values.

Here is how the Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 equation looks like with Units.

Here is how the Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 equation looks like.

2.609 = \frac{4.99}{(\frac{2.303}{4}) \cdot \log ((\frac{20}{10}), 10)}

2.609m² = \frac{4.99m³/hr}{(\frac{2.303}{4h}) \cdot \log ((\frac{20m}{10m}), 10)}

2.609 = \frac{4.99}{(\frac{2.303}{4}) \cdot \log ((\frac{20}{10}), 10)}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Environmental Engineering » fx Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Solution

Follow our step by step solution on how to calculate Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

FIRST Step Consider the formula

A sec = \frac{K b}{(\frac{2.303}{t}) \cdot \log ((\frac{h1'}{h w2}), 10)}

Next Step Substitute values of Variables

∴

A sec = \frac{4.99m³/hr}{(\frac{2.303}{4h}) \cdot \log ((\frac{20m}{10m}), 10)}

Next Step Convert Units

∴

A sec = \frac{0.0014m³/s}{(\frac{2.303}{14400s}) \cdot \log ((\frac{20m}{10m}), 10)}

Next Step Prepare to Evaluate

∴

A sec = \frac{0.0014}{(\frac{2.303}{14400}) \cdot \log ((\frac{20}{10}), 10)}

Next Step Evaluate

∴

A sec = 2.60901377049634m²

LAST Step Rounding Answer

∴

A sec = 2.609m²

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Formula Elements

Variables

Functions

Cross-Sectional Area given Specific Capacity

Cross-Sectional Area given Specific Capacity is the cross-sectional area of the wellbore through which water flows.

Symbol: A_sec

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area given Specific Capacity

Constant Dependent on Base Soil

Constant Dependent on Base Soil is the constant depending on the soil at the base of the well.

Symbol: K_b

Measurement: Volumetric Flow RateUnit: m³/hr

Note: Value should be greater than 0.

Formulas to find Constant Dependent on Base Soil

Time

Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.

Symbol: t

Measurement: TimeUnit: h

Note: Value should be greater than 0.

Formulas to find Time

Depression Head in Well

Depression Head in Well is the depression head in the well when pumping stopped.

Symbol: h1'

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head in Well

Depression Head in Well 2

Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.

Symbol: h_w2

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Depression Head in Well 2

log

Logarithmic function is an inverse function to exponentiation.

Syntax: log(Base, Number)

Other formulas in Cross Sectional Area of Well category

Go Cross-sectional Area of Well given Constant Depending upon Soil at Base

A csw = \frac{K b}{(\frac{1}{t}) \cdot \log ((\frac{h1'}{h w2}), e)}

Go Cross-sectional Area of Well given Discharge from Well

A csw = \frac{Q}{S si \cdot H'}

How to Evaluate Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 evaluator uses Cross-Sectional Area given Specific Capacity = Constant Dependent on Base Soil/((2.303/Time)*log((Depression Head in Well/Depression Head in Well 2),10)) to evaluate the Cross-Sectional Area given Specific Capacity, The Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 formula is defined as the calculation of value of cross-sectional area of well when we have prior information of other parameters used. Cross-Sectional Area given Specific Capacity is denoted by A_sec symbol.

How to evaluate Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 using this online evaluator? To use this online evaluator for Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10, enter Constant Dependent on Base Soil (K_b), Time (t), Depression Head in Well (h1') & Depression Head in Well 2 (h_w2) and hit the calculate button.

FAQs on Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10

What is the formula to find Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

The formula of Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 is expressed as Cross-Sectional Area given Specific Capacity = Constant Dependent on Base Soil/((2.303/Time)*log((Depression Head in Well/Depression Head in Well 2),10)). Here is an example- 2.609014 = 0.00138611111111111/((2.303/14400)*log((20/10),10)).

How to calculate Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

With Constant Dependent on Base Soil (K_b), Time (t), Depression Head in Well (h1') & Depression Head in Well 2 (h_w2) we can find Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 using the formula - Cross-Sectional Area given Specific Capacity = Constant Dependent on Base Soil/((2.303/Time)*log((Depression Head in Well/Depression Head in Well 2),10)). This formula also uses Logarithmic Inverse (log) function(s).

Can the Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 be negative?

No, the Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10, measured in Area cannot be negative.

Which unit is used to measure Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Formula

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Example

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Solution

Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10 Formula Elements

Other formulas in Cross Sectional Area of Well category

How to Evaluate Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10?

FAQs on Cross-sectional Area of Well given Constant Depending upon Soil at Base with Base 10

Variable Name