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Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Formula

GoCross Sectional Area given Time required to Lower Liquid Surface Formula

GoCross Sectional Area given Time required to Lower Liquid for Triangular Notch Formula

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Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point. Check FAQs

A R = \frac{Δt \cdot m \cdot \sqrt{2 \cdot g}}{(\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}}) \cdot 2}

A_R - Cross-Sectional Area of Reservoir?Δt - Time Interval?m - Bazins Coefficient?g - Acceleration due to Gravity?h₂ - Head on Downstream of Weir?H_Upstream - Head on Upstream of Weir?

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Example

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Here is how the Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula equation looks like with Values.

Here is how the Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula equation looks like with Units.

Here is how the Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula equation looks like.

8.7879 = \frac{1.25 \cdot 0.407 \cdot \sqrt{2 \cdot 9.8}}{(\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}}) \cdot 2}

8.7879m² = \frac{1.25s \cdot 0.407 \cdot \sqrt{2 \cdot 9.8m/s²}}{(\frac{1}{\sqrt{5.1m}} - \frac{1}{\sqrt{10.1m}}) \cdot 2}

8.7879 = \frac{1.25 \cdot 0.407 \cdot \sqrt{2 \cdot 9.8}}{(\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}}) \cdot 2}

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Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Solution

Follow our step by step solution on how to calculate Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

FIRST Step Consider the formula

A R = \frac{Δt \cdot m \cdot \sqrt{2 \cdot g}}{(\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}}) \cdot 2}

Next Step Substitute values of Variables

∴

A R = \frac{1.25s \cdot 0.407 \cdot \sqrt{2 \cdot 9.8m/s²}}{(\frac{1}{\sqrt{5.1m}} - \frac{1}{\sqrt{10.1m}}) \cdot 2}

Next Step Prepare to Evaluate

∴

A R = \frac{1.25 \cdot 0.407 \cdot \sqrt{2 \cdot 9.8}}{(\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}}) \cdot 2}

Next Step Evaluate

∴

A R = 8.78793941689505m²

LAST Step Rounding Answer

∴

A R = 8.7879m²

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Formula Elements

Variables

Functions

Cross-Sectional Area of Reservoir

Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.

Symbol: A_R

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area of Reservoir

Time Interval

Time interval is the time duration between two events/entities of interest.

Symbol: Δt

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time Interval

Bazins Coefficient

Bazins Coefficient is the constant value obtained by Head.

Symbol: m

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Bazins Coefficient

Acceleration due to Gravity

The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration due to Gravity

Head on Downstream of Weir

Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: h₂

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Downstream of Weir

Head on Upstream of Weir

Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: H_Upstream

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Upstream of Weir

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Cross-Sectional Area of Reservoir

Go Cross Sectional Area given Time required to Lower Liquid Surface

A R = \frac{Δt \cdot (\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}{2 \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})}

Go Cross Sectional Area given Time required to Lower Liquid for Triangular Notch

A R = \frac{Δt \cdot (\frac{8}{15}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot \tan (\frac{θ}{2})}{(\frac{2}{3}) \cdot ((\frac{1}{{h 2}^{\frac{3}{2}}}) - (\frac{1}{{H Upstream}^{\frac{3}{2}}}))}

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

Go Time Required to Lower Liquid Surface

Δt = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Coefficient of Discharge for Time Required to Lower Liquid Surface

C d = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot Δt \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Length of Crest for time required to Lower Liquid Surface

L w = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot Δt}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Head2 given Time Required to Lower Liquid Surface

h 2 = {(\frac{1}{\frac{Δt \cdot (\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}{2 \cdot A R} + (\frac{1}{\sqrt{H Upstream}})})}^{2}

How to Evaluate Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula evaluator uses Cross-Sectional Area of Reservoir = (Time Interval*Bazins Coefficient*sqrt(2*Acceleration due to Gravity))/((1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))*2) to evaluate the Cross-Sectional Area of Reservoir, The Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula is area of a two-dimensional shape that is obtained when a three-dimensional object - such as a cylinder. Cross-Sectional Area of Reservoir is denoted by A_R symbol.

How to evaluate Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula using this online evaluator? To use this online evaluator for Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula, enter Time Interval (Δt), Bazins Coefficient (m), Acceleration due to Gravity (g), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) and hit the calculate button.

FAQs on Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula

What is the formula to find Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

The formula of Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula is expressed as Cross-Sectional Area of Reservoir = (Time Interval*Bazins Coefficient*sqrt(2*Acceleration due to Gravity))/((1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))*2). Here is an example- 8.787939 = (1.25*0.407*sqrt(2*9.8))/((1/sqrt(5.1)-1/sqrt(10.1))*2).

How to calculate Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

With Time Interval (Δt), Bazins Coefficient (m), Acceleration due to Gravity (g), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) we can find Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula using the formula - Cross-Sectional Area of Reservoir = (Time Interval*Bazins Coefficient*sqrt(2*Acceleration due to Gravity))/((1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))*2). This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Cross-Sectional Area of Reservoir?

Here are the different ways to Calculate Cross-Sectional Area of Reservoir-

Cross-Sectional Area of Reservoir=(Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))
Cross-Sectional Area of Reservoir=(Time Interval*(8/15)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*tan(Theta/2))/((2/3)*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))))

Can the Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula be negative?

No, the Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula, measured in Area cannot be negative.

Which unit is used to measure Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula can be measured.

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Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Formula

​GoCross Sectional Area given Time required to Lower Liquid Surface Formula

​GoCross Sectional Area given Time required to Lower Liquid for Triangular Notch Formula

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Example

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Solution

Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula Formula Elements

Other Formulas to find Cross-Sectional Area of Reservoir

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

How to Evaluate Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula?

FAQs on Cross Sectional Area given time required to Lower Liquid Surface using Bazins Formula

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GoCross Sectional Area given Time required to Lower Liquid Surface Formula

GoCross Sectional Area given Time required to Lower Liquid for Triangular Notch Formula