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Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters Formula

GoCritical Temperature of Real Gas given Wohl Parameter a. and Other Actual and Reduced Parameters Formula

GoCritical Temperature of Real Gas using Wohl Equation given Reduced and Critical Parameters Formula

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Critical Temperature of Real Gas is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor. Check FAQs

T' c = \frac{\frac{[R]}{(P rg + (\frac{a}{V m \cdot (V m - b)}) - (\frac{c}{({V m}^{3})})) \cdot (V m - b)}}{T r}

T'_c - Critical Temperature of Real Gas?P_rg - Pressure of Gas?a - Wohl Parameter a?V_m - Molar Volume?b - Wohl Parameter b?c - Wohl Parameter c?T_r - Reduced Temperature?[R] - Universal gas constant?

Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters Example

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Here is how the Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters equation looks like with Values.

Here is how the Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters equation looks like with Units.

Here is how the Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters equation looks like.

2.5E-5 = \frac{\frac{8.3145}{(10132 + (\frac{266}{22.4 \cdot (22.4 - 0.0062)}) - (\frac{21}{({22.4}^{3})})) \cdot (22.4 - 0.0062)}}{1.46}

2.5E-5K = \frac{\frac{8.3145}{(10132Pa + (\frac{266}{22.4m³/mol \cdot (22.4m³/mol - 0.0062)}) - (\frac{21}{({22.4m³/mol}^{3})})) \cdot (22.4m³/mol - 0.0062)}}{1.46}

2.5E-5 = \frac{\frac{8.3145}{(10132 + (\frac{266}{22.4 \cdot (22.4 - 0.0062)}) - (\frac{21}{({22.4}^{3})})) \cdot (22.4 - 0.0062)}}{1.46}

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Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters Solution

Follow our step by step solution on how to calculate Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters?

FIRST Step Consider the formula

T' c = \frac{\frac{[R]}{(P rg + (\frac{a}{V m \cdot (V m - b)}) - (\frac{c}{({V m}^{3})})) \cdot (V m - b)}}{T r}

Next Step Substitute values of Variables

∴

T' c = \frac{\frac{[R]}{(10132Pa + (\frac{266}{22.4m³/mol \cdot (22.4m³/mol - 0.0062)}) - (\frac{21}{({22.4m³/mol}^{3})})) \cdot (22.4m³/mol - 0.0062)}}{1.46}

Next Step Substitute values of Constants

∴

T' c = \frac{\frac{8.3145}{(10132Pa + (\frac{266}{22.4m³/mol \cdot (22.4m³/mol - 0.0062)}) - (\frac{21}{({22.4m³/mol}^{3})})) \cdot (22.4m³/mol - 0.0062)}}{1.46}

Next Step Prepare to Evaluate

∴

T' c = \frac{\frac{8.3145}{(10132 + (\frac{266}{22.4 \cdot (22.4 - 0.0062)}) - (\frac{21}{({22.4}^{3})})) \cdot (22.4 - 0.0062)}}{1.46}

Next Step Evaluate

∴

T' c = 2.50978589081903E-05K

LAST Step Rounding Answer

∴

T' c = 2.5E-5K

Critical Temperature of Real Gas using Wohl Equation given Reduced and Actual Parameters Formula Elements

Variables

Constants

Critical Temperature of Real Gas

Critical Temperature of Real Gas is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor.

Symbol: T'_c

Measurement: TemperatureUnit: K

Note: Value should be greater than 0.

Formulas to find Critical Temperature of Real Gas

Pressure of Gas

Pressure of Gas is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: P_rg

Measurement: PressureUnit: Pa