Cos (B/2) given Sides A and C and Sin (B/2) Formula

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Cos (B/2) is the value of the trigonometric cosine function of half of the given angle B of the triangle. Check FAQs
cos(B/2)=ASaScsin(B/2)
cos(B/2) - Cos (B/2)?A - Area of Triangle?Sa - Side A of Triangle?Sc - Side C of Triangle?sin(B/2) - Sin (B/2)?

Cos (B/2) given Sides A and C and Sin (B/2) Example

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Here is how the Cos (B/2) given Sides A and C and Sin (B/2) equation looks like with Values.

Here is how the Cos (B/2) given Sides A and C and Sin (B/2) equation looks like with Units.

Here is how the Cos (B/2) given Sides A and C and Sin (B/2) equation looks like.

0.9503Edit=65Edit10Edit20Edit0.342Edit
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Cos (B/2) given Sides A and C and Sin (B/2) Solution

Follow our step by step solution on how to calculate Cos (B/2) given Sides A and C and Sin (B/2)?

FIRST Step Consider the formula
cos(B/2)=ASaScsin(B/2)
Next Step Substitute values of Variables
cos(B/2)=6510m20m0.342
Next Step Prepare to Evaluate
cos(B/2)=6510200.342
Next Step Evaluate
cos(B/2)=0.950292397660819
LAST Step Rounding Answer
cos(B/2)=0.9503

Cos (B/2) given Sides A and C and Sin (B/2) Formula Elements

Variables
Cos (B/2)
Cos (B/2) is the value of the trigonometric cosine function of half of the given angle B of the triangle.
Symbol: cos(B/2)
Measurement: NAUnit: Unitless
Note: Value should be between -1.01 to 1.01.
Area of Triangle
The Area of Triangle is the amount of region or space occupied by the Triangle.
Symbol: A
Measurement: AreaUnit:
Note: Value should be greater than 0.
Side A of Triangle
The Side A of Triangle is the length of the side A, of the three sides of the triangle. In other words, the side A of the Triangle is the side opposite to the angle A.
Symbol: Sa
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Side C of Triangle
The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C.
Symbol: Sc
Measurement: LengthUnit: m
Note: Value should be greater than 0.
Sin (B/2)
Sin (B/2) is the value of the trigonometric sine function of half of the given angle A of the triangle.
Symbol: sin(B/2)
Measurement: NAUnit: Unitless
Note: Value should be between -1.01 to 1.01.

Other formulas in Trigonometric Ratios of Half Angles using Area of the Triangle category

​Go Sin (A/2) given Sides B and C and Cos (A/2)
sin(A/2)=ASbSccos(A/2)
​Go Sin (B/2) given Sides A and C and Cos (B/2)
sin(B/2)=ASaSccos(B/2)
​Go Sin (C/2) given Sides A and B and Cos (C/2)
sin(C/2)=ASaSbcos(C/2)
​Go Cos (A/2) given Sides B and C and Sin (A/2)
cos(A/2)=ASbScsin(A/2)

How to Evaluate Cos (B/2) given Sides A and C and Sin (B/2)?

Cos (B/2) given Sides A and C and Sin (B/2) evaluator uses Cos (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Sin (B/2)) to evaluate the Cos (B/2), The Cos (B/2) given Sides A and C and Sin (B/2) formula is defined as value of cos B/2 using area of the triangle, the sides A & C and the trigonometric half ratio Sin B/2. Cos (B/2) is denoted by cos(B/2) symbol.

How to evaluate Cos (B/2) given Sides A and C and Sin (B/2) using this online evaluator? To use this online evaluator for Cos (B/2) given Sides A and C and Sin (B/2), enter Area of Triangle (A), Side A of Triangle (Sa), Side C of Triangle (Sc) & Sin (B/2) (sin(B/2)) and hit the calculate button.

FAQs on Cos (B/2) given Sides A and C and Sin (B/2)

What is the formula to find Cos (B/2) given Sides A and C and Sin (B/2)?
The formula of Cos (B/2) given Sides A and C and Sin (B/2) is expressed as Cos (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Sin (B/2)). Here is an example- 0.950292 = 65/(10*20*0.342).
How to calculate Cos (B/2) given Sides A and C and Sin (B/2)?
With Area of Triangle (A), Side A of Triangle (Sa), Side C of Triangle (Sc) & Sin (B/2) (sin(B/2)) we can find Cos (B/2) given Sides A and C and Sin (B/2) using the formula - Cos (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Sin (B/2)).
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