FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Constant using Line Losses (1-Phase 2-Wire US) Formula

GoConstant (1-Phase 2-Wire US) Formula

GoConstant using Area of X-Section (1-Phase 2-Wire US) Formula

Fx Copy

LaTeX Copy

Constant Underground AC is defined as the constant of line of a Overhead supply system. Check FAQs

K = \frac{4 \cdot ρ \cdot {(P \cdot V ac)}^{2}}{P loss \cdot {(V m)}^{2}}

K - Constant Underground AC?ρ - Resistivity?P - Power Transmitted?V_ac - Voltage Underground AC?P_loss - Line Losses?V_m - Maximum Voltage Underground AC?

Constant using Line Losses (1-Phase 2-Wire US) Example

With values

With units

Only example

Here is how the Constant using Line Losses (1-Phase 2-Wire US) equation looks like with Values.

Here is how the Constant using Line Losses (1-Phase 2-Wire US) equation looks like with Units.

Here is how the Constant using Line Losses (1-Phase 2-Wire US) equation looks like.

0.6239 = \frac{4 \cdot 1.7E-5 \cdot {(300 \cdot 120)}^{2}}{2.67 \cdot {(230)}^{2}}

0.6239 = \frac{4 \cdot 1.7E-5Ω*m \cdot {(300W \cdot 120V)}^{2}}{2.67W \cdot {(230V)}^{2}}

0.6239 = \frac{4 \cdot 1.7E-5 \cdot {(300 \cdot 120)}^{2}}{2.67 \cdot {(230)}^{2}}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Electrical » Category

Power System » fx Constant using Line Losses (1-Phase 2-Wire US)

Constant using Line Losses (1-Phase 2-Wire US) Solution

Follow our step by step solution on how to calculate Constant using Line Losses (1-Phase 2-Wire US)?

FIRST Step Consider the formula

K = \frac{4 \cdot ρ \cdot {(P \cdot V ac)}^{2}}{P loss \cdot {(V m)}^{2}}

Next Step Substitute values of Variables

∴

K = \frac{4 \cdot 1.7E-5Ω*m \cdot {(300W \cdot 120V)}^{2}}{2.67W \cdot {(230V)}^{2}}

Next Step Prepare to Evaluate

∴

K = \frac{4 \cdot 1.7E-5 \cdot {(300 \cdot 120)}^{2}}{2.67 \cdot {(230)}^{2}}

Next Step Evaluate

∴

K = 0.623945965463775

LAST Step Rounding Answer

∴

K = 0.6239

Constant using Line Losses (1-Phase 2-Wire US) Formula Elements

Variables

Constant Underground AC

Constant Underground AC is defined as the constant of line of a Overhead supply system.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Constant Underground AC

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Voltage Underground AC

Voltage Underground AC is defined as the amount of work or force required to start the conduction of current within a line.

Symbol: V_ac

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Voltage Underground AC

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Other Formulas to find Constant Underground AC

Go Constant (1-Phase 2-Wire US)

K = 4 \cdot ρ \cdot \frac{{(P \cdot L)}^{2}}{P loss \cdot {(V m)}^{2}}

Go Constant using Area of X-Section (1-Phase 2-Wire US)

K = A \cdot L \cdot {(\cos (Φ))}^{2}

Go Constant using Volume of Conductor Material (1-Phase 2-Wire US)

K = V \cdot \frac{{(\cos (Φ))}^{2}}{2}

Go Constant using Load Current (1-Phase 2-Wire US)

K = 2 \cdot (I^{2}) \cdot ({\cos (Φ)}^{2}) \cdot ρ \cdot \frac{L^{2}}{P loss}

Other formulas in Wire Parameters category

Go Area of X-Section (1-Phase 2-Wire US)

A = (4) \cdot ρ \cdot L \cdot \frac{{(P)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Go Voltage of Conductor Material (1-Phase 2-Wire US)

V = 2 \cdot \frac{K}{{(\cos (Φ))}^{2}}

Go Area of X-Section using Volume of Conductor Material (1-Phase 2-Wire US)

A = \frac{V}{2 \cdot L}

Go Length using Area of X-Section (1-Phase 2-Wire US)

L = A \cdot P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot (P^{2}) \cdot ρ}

How to Evaluate Constant using Line Losses (1-Phase 2-Wire US)?

Constant using Line Losses (1-Phase 2-Wire US) evaluator uses Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2) to evaluate the Constant Underground AC, The Constant using Line Losses (1-Phase 2-Wire US) formula is defined as the total constant of a single-phase two-wire overhead system. it is represented by K. Constant Underground AC is denoted by K symbol.

How to evaluate Constant using Line Losses (1-Phase 2-Wire US) using this online evaluator? To use this online evaluator for Constant using Line Losses (1-Phase 2-Wire US), enter Resistivity (ρ), Power Transmitted (P), Voltage Underground AC (V_ac), Line Losses (P_loss) & Maximum Voltage Underground AC (V_m) and hit the calculate button.

FAQs on Constant using Line Losses (1-Phase 2-Wire US)

What is the formula to find Constant using Line Losses (1-Phase 2-Wire US)?

The formula of Constant using Line Losses (1-Phase 2-Wire US) is expressed as Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2). Here is an example- 0.623946 = (4*1.7E-05*(300*120)^2)/(2.67*(230)^2).

How to calculate Constant using Line Losses (1-Phase 2-Wire US)?

With Resistivity (ρ), Power Transmitted (P), Voltage Underground AC (V_ac), Line Losses (P_loss) & Maximum Voltage Underground AC (V_m) we can find Constant using Line Losses (1-Phase 2-Wire US) using the formula - Constant Underground AC = (4*Resistivity*(Power Transmitted*Voltage Underground AC)^2)/(Line Losses*(Maximum Voltage Underground AC)^2).

What are the other ways to Calculate Constant Underground AC?

Here are the different ways to Calculate Constant Underground AC-

Constant Underground AC=4*Resistivity*(Power Transmitted*Length of Underground AC Wire)^2/(Line Losses*(Maximum Voltage Underground AC)^2)
Constant Underground AC=Area of Underground AC Wire*Length of Underground AC Wire*(cos(Phase Difference))^2
Constant Underground AC=Volume Of Conductor*(cos(Phase Difference))^2/2

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Constant using Line Losses (1-Phase 2-Wire US) Formula

​GoConstant (1-Phase 2-Wire US) Formula

​GoConstant using Area of X-Section (1-Phase 2-Wire US) Formula

Constant using Line Losses (1-Phase 2-Wire US) Example

Constant using Line Losses (1-Phase 2-Wire US) Solution

Constant using Line Losses (1-Phase 2-Wire US) Formula Elements

Other Formulas to find Constant Underground AC

Other formulas in Wire Parameters category

How to Evaluate Constant using Line Losses (1-Phase 2-Wire US)?

FAQs on Constant using Line Losses (1-Phase 2-Wire US)

Variable Name

GoConstant (1-Phase 2-Wire US) Formula

GoConstant using Area of X-Section (1-Phase 2-Wire US) Formula