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Constant Depending upon Soil at Base of Well given Fine Sand Formula

GoConstant Depending upon Soil at Base of Well given Specific Capacity Formula

GoConstant Depending upon Soil at Base of Well Formula

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Constant depending on the soil at the base of the well. Check FAQs

K = 0.5 \cdot A csw

K - Constant?A_csw - Cross-Sectional Area of Well?

Constant Depending upon Soil at Base of Well given Fine Sand Example

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Here is how the Constant Depending upon Soil at Base of Well given Fine Sand equation looks like with Values.

Here is how the Constant Depending upon Soil at Base of Well given Fine Sand equation looks like with Units.

Here is how the Constant Depending upon Soil at Base of Well given Fine Sand equation looks like.

6.5 = 0.5 \cdot 13

6.5 = 0.5 \cdot 13m²

6.5 = 0.5 \cdot 13

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Constant Depending upon Soil at Base of Well given Fine Sand Solution

Follow our step by step solution on how to calculate Constant Depending upon Soil at Base of Well given Fine Sand?

FIRST Step Consider the formula

K = 0.5 \cdot A csw

Next Step Substitute values of Variables

∴

K = 0.5 \cdot 13m²

Next Step Prepare to Evaluate

∴

K = 0.5 \cdot 13

LAST Step Evaluate

∴

K = 6.5

Constant Depending upon Soil at Base of Well given Fine Sand Formula Elements

Variables

Constant

Constant depending on the soil at the base of the well.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant

Cross-Sectional Area of Well

Cross-Sectional Area of Well is the the surface area of the interior opening of the well.

Symbol: A_csw

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area of Well

Other Formulas to find Constant

Go Constant Depending upon Soil at Base of Well given Specific Capacity

K = A sec \cdot S si

Go Constant Depending upon Soil at Base of Well

K = (\frac{A cs}{t}) \cdot \log ((\frac{h d}{h w2}), e)

Go Constant Depending upon Soil at Base of Well with Base 10

K = (\frac{A sec \cdot 2.303}{t}) \cdot \log ((\frac{h d}{h w2}), 10)

Go Constant Depending upon Soil at Base of Well given Clay Soil

K = 0.25 \cdot A cs

Other formulas in Constant Depending upon Base Soil category

Go Constant Depression Head given Discharge from Well

H' = \frac{Q}{K}

Go Constant Depression Head given Discharge and Time in Hours

H' = \frac{Q}{\frac{2.303 \cdot A csw \cdot \log ((\frac{h d}{h w2}), 10)}{t}}

How to Evaluate Constant Depending upon Soil at Base of Well given Fine Sand?

Constant Depending upon Soil at Base of Well given Fine Sand evaluator uses Constant = 0.5*Cross-Sectional Area of Well to evaluate the Constant, The Constant Depending upon Soil at Base of Well given Fine Sand formula is defined as the calculation of the value of constant depending upon soil at base of well when we have prior information of other parameters used. Constant is denoted by K symbol.

How to evaluate Constant Depending upon Soil at Base of Well given Fine Sand using this online evaluator? To use this online evaluator for Constant Depending upon Soil at Base of Well given Fine Sand, enter Cross-Sectional Area of Well (A_csw) and hit the calculate button.

FAQs on Constant Depending upon Soil at Base of Well given Fine Sand

What is the formula to find Constant Depending upon Soil at Base of Well given Fine Sand?

The formula of Constant Depending upon Soil at Base of Well given Fine Sand is expressed as Constant = 0.5*Cross-Sectional Area of Well. Here is an example- 6.5 = 0.5*13.

How to calculate Constant Depending upon Soil at Base of Well given Fine Sand?

With Cross-Sectional Area of Well (A_csw) we can find Constant Depending upon Soil at Base of Well given Fine Sand using the formula - Constant = 0.5*Cross-Sectional Area of Well.

What are the other ways to Calculate Constant?

Here are the different ways to Calculate Constant-

Constant=Cross-Sectional Area given Specific Capacity*Specific Capacity in SI unit
Constant=(Cross Sectional Area/Time)*log((Depression Head/Depression Head in Well 2),e)
Constant=((Cross-Sectional Area given Specific Capacity*2.303)/Time)*log((Depression Head/Depression Head in Well 2),10)

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