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Constant Depending upon Soil at Base of Well given Clay Soil Formula

GoConstant Depending upon Soil at Base of Well given Specific Capacity Formula

GoConstant Depending upon Soil at Base of Well Formula

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Constant depending on the soil at the base of the well. Check FAQs

K = 0.25 \cdot A cs

K - Constant?A_cs - Cross Sectional Area?

Constant Depending upon Soil at Base of Well given Clay Soil Example

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Here is how the Constant Depending upon Soil at Base of Well given Clay Soil equation looks like with Values.

Here is how the Constant Depending upon Soil at Base of Well given Clay Soil equation looks like with Units.

Here is how the Constant Depending upon Soil at Base of Well given Clay Soil equation looks like.

5 = 0.25 \cdot 20

5 = 0.25 \cdot 20m²

5 = 0.25 \cdot 20

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Constant Depending upon Soil at Base of Well given Clay Soil Solution

Follow our step by step solution on how to calculate Constant Depending upon Soil at Base of Well given Clay Soil?

FIRST Step Consider the formula

K = 0.25 \cdot A cs

Next Step Substitute values of Variables

∴

K = 0.25 \cdot 20m²

Next Step Prepare to Evaluate

∴

K = 0.25 \cdot 20

LAST Step Evaluate

∴

K = 5

Constant Depending upon Soil at Base of Well given Clay Soil Formula Elements

Variables

Constant

Constant depending on the soil at the base of the well.

Symbol: K

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Constant

Cross Sectional Area

Cross Sectional Area is the area of a two-dimensional shape that is obtained when a three-dimensional shape is sliced perpendicular to some specified axis at a point.

Symbol: A_cs

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross Sectional Area

Other Formulas to find Constant

Go Constant Depending upon Soil at Base of Well given Specific Capacity

K = A sec \cdot S si

Go Constant Depending upon Soil at Base of Well

K = (\frac{A cs}{t}) \cdot \log ((\frac{h d}{h w2}), e)

Go Constant Depending upon Soil at Base of Well with Base 10

K = (\frac{A sec \cdot 2.303}{t}) \cdot \log ((\frac{h d}{h w2}), 10)

Go Constant Depending upon Soil at Base of Well given Fine Sand

K = 0.5 \cdot A csw

Other formulas in Constant Depending upon Base Soil category

Go Constant Depression Head given Discharge from Well

H' = \frac{Q}{K}

Go Constant Depression Head given Discharge and Time in Hours

H' = \frac{Q}{\frac{2.303 \cdot A csw \cdot \log ((\frac{h d}{h w2}), 10)}{t}}

How to Evaluate Constant Depending upon Soil at Base of Well given Clay Soil?

Constant Depending upon Soil at Base of Well given Clay Soil evaluator uses Constant = 0.25*Cross Sectional Area to evaluate the Constant, The Constant Depending upon Soil at Base of Well given Clay Soil formula is defined as the calculation of the value of constant depending upon soil at base of well when we have prior information of other parameters used. Constant is denoted by K symbol.

How to evaluate Constant Depending upon Soil at Base of Well given Clay Soil using this online evaluator? To use this online evaluator for Constant Depending upon Soil at Base of Well given Clay Soil, enter Cross Sectional Area (A_cs) and hit the calculate button.

FAQs on Constant Depending upon Soil at Base of Well given Clay Soil

What is the formula to find Constant Depending upon Soil at Base of Well given Clay Soil?

The formula of Constant Depending upon Soil at Base of Well given Clay Soil is expressed as Constant = 0.25*Cross Sectional Area. Here is an example- 5 = 0.25*20.

How to calculate Constant Depending upon Soil at Base of Well given Clay Soil?

With Cross Sectional Area (A_cs) we can find Constant Depending upon Soil at Base of Well given Clay Soil using the formula - Constant = 0.25*Cross Sectional Area.

What are the other ways to Calculate Constant?

Here are the different ways to Calculate Constant-

Constant=Cross-Sectional Area given Specific Capacity*Specific Capacity in SI unit
Constant=(Cross Sectional Area/Time)*log((Depression Head/Depression Head in Well 2),e)
Constant=((Cross-Sectional Area given Specific Capacity*2.303)/Time)*log((Depression Head/Depression Head in Well 2),10)

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