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Conjugate Axis of Hyperbola Formula

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Conjugate Axis of Hyperbola is the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex. Check FAQs

2b = 2 \cdot b

2b - Conjugate Axis of Hyperbola?b - Semi Conjugate Axis of Hyperbola?

Conjugate Axis of Hyperbola Example

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Here is how the Conjugate Axis of Hyperbola equation looks like with Values.

Here is how the Conjugate Axis of Hyperbola equation looks like with Units.

Here is how the Conjugate Axis of Hyperbola equation looks like.

24 = 2 \cdot 12

24m = 2 \cdot 12m

24 = 2 \cdot 12

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Conjugate Axis of Hyperbola Solution

Follow our step by step solution on how to calculate Conjugate Axis of Hyperbola?

FIRST Step Consider the formula

2b = 2 \cdot b

Next Step Substitute values of Variables

∴

2b = 2 \cdot 12m

Next Step Prepare to Evaluate

∴

2b = 2 \cdot 12

LAST Step Evaluate

∴

2b = 24m

Conjugate Axis of Hyperbola Formula Elements

Variables

Conjugate Axis of Hyperbola

Conjugate Axis of Hyperbola is the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex.

Symbol: 2b

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Conjugate Axis of Hyperbola

Semi Conjugate Axis of Hyperbola

Semi Conjugate Axis of Hyperbola is half of the tangent from any of the vertices of the Hyperbola and chord to the circle passing through the foci and centered at the center of the Hyperbola.

Symbol: b

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Semi Conjugate Axis of Hyperbola

Other formulas in Conjugate Axis of Hyperbola category

Go Semi Conjugate Axis of Hyperbola given Eccentricity

b = a \cdot \sqrt{e^{2} - 1}

Go Semi Conjugate Axis of Hyperbola given Latus Rectum

b = \sqrt{\frac{L \cdot a}{2}}

Go Semi Transverse Axis of Hyperbola given Focal Parameter

a = \frac{b}{p} \cdot \sqrt{b^{2} - p^{2}}

Go Semi Transverse Axis of Hyperbola given Linear Eccentricity

a = \sqrt{c^{2} - b^{2}}

How to Evaluate Conjugate Axis of Hyperbola?

Conjugate Axis of Hyperbola evaluator uses Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola to evaluate the Conjugate Axis of Hyperbola, Conjugate Axis of Hyperbola formula is defined as the line through the center and perpendicular to transverse axis with length of the chord of the circle passing through the foci and touches the Hyperbola at vertex. Conjugate Axis of Hyperbola is denoted by 2b symbol.

How to evaluate Conjugate Axis of Hyperbola using this online evaluator? To use this online evaluator for Conjugate Axis of Hyperbola, enter Semi Conjugate Axis of Hyperbola (b) and hit the calculate button.

FAQs on Conjugate Axis of Hyperbola

What is the formula to find Conjugate Axis of Hyperbola?

The formula of Conjugate Axis of Hyperbola is expressed as Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola. Here is an example- 24 = 2*12.

How to calculate Conjugate Axis of Hyperbola?

With Semi Conjugate Axis of Hyperbola (b) we can find Conjugate Axis of Hyperbola using the formula - Conjugate Axis of Hyperbola = 2*Semi Conjugate Axis of Hyperbola.

Can the Conjugate Axis of Hyperbola be negative?

No, the Conjugate Axis of Hyperbola, measured in Length cannot be negative.

Which unit is used to measure Conjugate Axis of Hyperbola?

Conjugate Axis of Hyperbola is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Conjugate Axis of Hyperbola can be measured.

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