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Conduction through Edge of Two Adjoining Walls of Equal Thickness Formula

GoIsothermal Cylinder at Center of Square Solid Bar of Same Length Formula

GoEccentric Isothermal Cylinder in Cylinder of Same Length Formula

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Conduction shape factor is defined as the value used to determine the heat transfer rate for the configurations which are very complex and require high calculation time. Check FAQs

S = 0.54 \cdot L w

S - Conduction Shape Factor?L_w - Length of Wall?

Conduction through Edge of Two Adjoining Walls of Equal Thickness Example

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Here is how the Conduction through Edge of Two Adjoining Walls of Equal Thickness equation looks like with Values.

Here is how the Conduction through Edge of Two Adjoining Walls of Equal Thickness equation looks like with Units.

Here is how the Conduction through Edge of Two Adjoining Walls of Equal Thickness equation looks like.

28 = 0.54 \cdot 51.8518

28m = 0.54 \cdot 51.8518m

28 = 0.54 \cdot 51.8518

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Conduction through Edge of Two Adjoining Walls of Equal Thickness Solution

Follow our step by step solution on how to calculate Conduction through Edge of Two Adjoining Walls of Equal Thickness?

FIRST Step Consider the formula

S = 0.54 \cdot L w

Next Step Substitute values of Variables

∴

S = 0.54 \cdot 51.8518m

Next Step Prepare to Evaluate

∴

S = 0.54 \cdot 51.8518

Next Step Evaluate

∴

S = 27.999999m

LAST Step Rounding Answer

∴

S = 28m

Conduction through Edge of Two Adjoining Walls of Equal Thickness Formula Elements

Variables

Conduction Shape Factor

Conduction shape factor is defined as the value used to determine the heat transfer rate for the configurations which are very complex and require high calculation time.

Symbol: S

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Conduction Shape Factor

Length of Wall

Length of Wall can be described as the length of wall in distance.

Symbol: L_w

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Wall

Other Formulas to find Conduction Shape Factor

Go Isothermal Cylinder at Center of Square Solid Bar of Same Length

S = \frac{2 \cdot π \cdot L c}{\ln (\frac{1.08 \cdot w}{D})}

Go Eccentric Isothermal Cylinder in Cylinder of Same Length

S = \frac{2 \cdot π \cdot L c}{a} \cosh (\frac{{D 1}^{2} + {D 2}^{2} - 4 \cdot z^{2}}{2 \cdot D 1 \cdot D 2})

Go Large Plane Wall

S = \frac{A}{t}

Go Long Hollow Cylindrical Layer

S = \frac{2 \cdot π \cdot L c}{\ln (\frac{r 2}{r 1})}

How to Evaluate Conduction through Edge of Two Adjoining Walls of Equal Thickness?

Conduction through Edge of Two Adjoining Walls of Equal Thickness evaluator uses Conduction Shape Factor = 0.54*Length of Wall to evaluate the Conduction Shape Factor, Conduction through Edge of Two Adjoining Walls of Equal Thickness formula is defined as a measure of the heat transfer that occurs when two walls of equal thickness are in contact, allowing heat to flow from one wall to the other through the edge where they meet. Conduction Shape Factor is denoted by S symbol.

How to evaluate Conduction through Edge of Two Adjoining Walls of Equal Thickness using this online evaluator? To use this online evaluator for Conduction through Edge of Two Adjoining Walls of Equal Thickness, enter Length of Wall (L_w) and hit the calculate button.

FAQs on Conduction through Edge of Two Adjoining Walls of Equal Thickness

What is the formula to find Conduction through Edge of Two Adjoining Walls of Equal Thickness?

The formula of Conduction through Edge of Two Adjoining Walls of Equal Thickness is expressed as Conduction Shape Factor = 0.54*Length of Wall. Here is an example- 28.08 = 0.54*51.85185.

How to calculate Conduction through Edge of Two Adjoining Walls of Equal Thickness?

With Length of Wall (L_w) we can find Conduction through Edge of Two Adjoining Walls of Equal Thickness using the formula - Conduction Shape Factor = 0.54*Length of Wall.

What are the other ways to Calculate Conduction Shape Factor?

Here are the different ways to Calculate Conduction Shape Factor-

Conduction Shape Factor=(2*pi*Length of Cylinder)/ln((1.08*Width of Square Bar)/Diameter of Cylinder)
Conduction Shape Factor=(2*pi*Length of Cylinder)/acosh((Diameter of Cylinder 1^2+Diameter of Cylinder 2^2-4*Eccentric Distance Between Objects^2)/(2*Diameter of Cylinder 1*Diameter of Cylinder 2))
Conduction Shape Factor=Cross-Sectional Area/Thickness

Can the Conduction through Edge of Two Adjoining Walls of Equal Thickness be negative?

No, the Conduction through Edge of Two Adjoining Walls of Equal Thickness, measured in Length cannot be negative.

Which unit is used to measure Conduction through Edge of Two Adjoining Walls of Equal Thickness?

Conduction through Edge of Two Adjoining Walls of Equal Thickness is usually measured using the Meter[m] for Length. Millimeter[m], Kilometer[m], Decimeter[m] are the few other units in which Conduction through Edge of Two Adjoining Walls of Equal Thickness can be measured.

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