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Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 Formula

GoConcentration of Intermediate B in First Order Consecutive Reaction Formula

GoMaximum Concentration of Intermediate B in First Order Consecutive Reaction Formula

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Concentration of B at Time t is defined as the amount of substance B present after reacting for a given interval of time t. Check FAQs

[B] = A \cdot (\frac{k 1}{k 2 - k 1})

[B] - Concentration of B at Time t?A - Concentration of A at Time t?k₁ - Reaction Rate Constant 1?k₂ - Rate Constant of Reaction 2?

Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 Example

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Here is how the Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 equation looks like with Values.

Here is how the Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 equation looks like with Units.

Here is how the Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 equation looks like.

0.0644 = 101 \cdot (\frac{5.7E-6}{0.0089 - 5.7E-6})

0.0644mol/L = 101mol/L \cdot (\frac{5.7E-6s⁻¹}{0.0089s⁻¹ - 5.7E-6s⁻¹})

0.0644 = 101 \cdot (\frac{5.7E-6}{0.0089 - 5.7E-6})

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Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 Solution

Follow our step by step solution on how to calculate Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1?

FIRST Step Consider the formula

[B] = A \cdot (\frac{k 1}{k 2 - k 1})

Next Step Substitute values of Variables

∴

[B] = 101mol/L \cdot (\frac{5.7E-6s⁻¹}{0.0089s⁻¹ - 5.7E-6s⁻¹})

Next Step Convert Units

∴

[B] = 101000mol/m³ \cdot (\frac{5.7E-6s⁻¹}{0.0089s⁻¹ - 5.7E-6s⁻¹})

Next Step Prepare to Evaluate

∴

[B] = 101000 \cdot (\frac{5.7E-6}{0.0089 - 5.7E-6})

Next Step Evaluate

∴

[B] = 64.3859627425562mol/m³

Next Step Convert to Output's Unit

∴

[B] = 0.0643859627425562mol/L

LAST Step Rounding Answer

∴

[B] = 0.0644mol/L

Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 Formula Elements

Variables

Concentration of B at Time t

Concentration of B at Time t is defined as the amount of substance B present after reacting for a given interval of time t.

Symbol: [B]

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Concentration of B at Time t

Concentration of A at Time t

Concentration of A at Time t is defined as the amount of substance A present after reacting for a given interval of time t.

Symbol: A

Measurement: Molar ConcentrationUnit: mol/L

Note: Value can be positive or negative.

Formulas to find Concentration of A at Time t

Reaction Rate Constant 1

Reaction Rate Constant 1 is defined as proportionality constant relating to the rate of the chemical reaction to the conc. of reactant or product in reaction 1.

Symbol: k₁

Measurement: First Order Reaction Rate ConstantUnit: s⁻¹

Note: Value should be greater than -1.

Formulas to find Reaction Rate Constant 1

Rate Constant of Reaction 2

Rate Constant of Reaction 2 is the proportionality constant relating to the rate of the chemical reaction to the conc. of the reactant or product in chemical reaction 2.

Symbol: k₂

Measurement: First Order Reaction Rate ConstantUnit: s⁻¹

Note: Value should be greater than 0.

Formulas to find Rate Constant of Reaction 2

Other Formulas to find Concentration of B at Time t

Go Concentration of Intermediate B in First Order Consecutive Reaction

[B] = A 0 \cdot (\frac{k 1}{k 2 - k 1}) \cdot (\exp (- k 1 \cdot t) - \exp (- k 2 \cdot t))

Go Maximum Concentration of Intermediate B in First Order Consecutive Reaction

[B] = A 0 \cdot {(\frac{k 2}{k 1})}^{\frac{k 2}{k 1 - k 2}}

Other formulas in Consecutive Reactions category

Go Concentration of Reactant A in First Order Consecutive Reaction

A = A 0 \cdot \exp (- k 1 \cdot t)

Go Concentration of Product C in First Order Consecutive Reaction

[C] = A 0 \cdot (1 - (\frac{1}{k 2 - k 1} \cdot (k 2 \cdot (\exp (- k 1 \cdot t) - k 1 \cdot \exp (- k 2 \cdot t)))))

Go Transient Eqm- Ratio of B by A when k2 much greater than k1 for 1st Order Consecutive Rxn

R B:A = \frac{k 1}{k 2 - k 1}

Go Secular Eqm- Ratio of Conc. of A to B given of half-lives provided k2 much greater than k1

R A:B = \frac{t 1/2,B}{t 1/2,A}

How to Evaluate Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1?

Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 evaluator uses Concentration of B at Time t = Concentration of A at Time t*(Reaction Rate Constant 1/(Rate Constant of Reaction 2-Reaction Rate Constant 1)) to evaluate the Concentration of B at Time t, The Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 formula is defined as amount of intermediate B that is formed in time interval t when rate constant k2>>k1. Concentration of B at Time t is denoted by [B] symbol.

How to evaluate Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 using this online evaluator? To use this online evaluator for Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1, enter Concentration of A at Time t (A), Reaction Rate Constant 1 (k₁) & Rate Constant of Reaction 2 (k₂) and hit the calculate button.

FAQs on Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1

What is the formula to find Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1?

The formula of Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 is expressed as Concentration of B at Time t = Concentration of A at Time t*(Reaction Rate Constant 1/(Rate Constant of Reaction 2-Reaction Rate Constant 1)). Here is an example- 6.4E-5 = 101000*(5.67E-06/(0.0089-5.67E-06)).

How to calculate Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1?

With Concentration of A at Time t (A), Reaction Rate Constant 1 (k₁) & Rate Constant of Reaction 2 (k₂) we can find Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 using the formula - Concentration of B at Time t = Concentration of A at Time t*(Reaction Rate Constant 1/(Rate Constant of Reaction 2-Reaction Rate Constant 1)).

What are the other ways to Calculate Concentration of B at Time t?

Here are the different ways to Calculate Concentration of B at Time t-

Concentration of B at Time t=Initial Concentration of Reactant A*(Reaction Rate Constant 1/(Rate Constant of Reaction 2-Reaction Rate Constant 1))*(exp(-Reaction Rate Constant 1*Time)-exp(-Rate Constant of Reaction 2*Time))
Concentration of B at Time t=Initial Concentration of Reactant A*(Rate Constant of Reaction 2/Reaction Rate Constant 1)^(Rate Constant of Reaction 2/(Reaction Rate Constant 1-Rate Constant of Reaction 2))

Can the Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 be negative?

Yes, the Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1, measured in Molar Concentration can be negative.

Which unit is used to measure Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1?

Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 is usually measured using the Mole per Liter[mol/L] for Molar Concentration. Mole per Cubic Meter[mol/L], Mole per Cubic Millimeter[mol/L], Kilomole per Cubic Meter[mol/L] are the few other units in which Conc. of Intermediate B provided Reactant A Conc. at time t given k2 much greater than k1 can be measured.

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