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Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing Formula

GoCohesion of Soil for Rectangular Footing given Shape Factor Formula

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Cohesion in Soil as Kilopascal is the ability of like particles within soil to hold onto each other. It is the shear strength or force that binds together like particles in the structure of a soil. Check FAQs

C = \frac{q fc - ((σ s \cdot N q) + (0.4 \cdot γ \cdot B \cdot N γ))}{(N c) \cdot (1 + 0.3 \cdot (\frac{B}{L}))}

C - Cohesion in Soil as Kilopascal?q_fc - Ultimate Bearing Capacity in Soil?σ_s - Effective Surcharge in KiloPascal?N_q - Bearing Capacity Factor dependent on Surcharge?γ - Unit Weight of Soil?B - Width of Footing?N_γ - Bearing Capacity Factor dependent on Unit Weight?N_c - Bearing Capacity Factor dependent on Cohesion?L - Length of Footing?

Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing Example

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Here is how the Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing equation looks like with Values.

Here is how the Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing equation looks like with Units.

Here is how the Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing equation looks like.

1.2078 = \frac{127.8 - ((45.9 \cdot 2.01) + (0.4 \cdot 18 \cdot 2 \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2}{4}))}

1.2078kPa = \frac{127.8kPa - ((45.9kN/m² \cdot 2.01) + (0.4 \cdot 18kN/m³ \cdot 2m \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2m}{4m}))}

1.2078 = \frac{127.8 - ((45.9 \cdot 2.01) + (0.4 \cdot 18 \cdot 2 \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2}{4}))}

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Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing Solution

Follow our step by step solution on how to calculate Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing?

FIRST Step Consider the formula

C = \frac{q fc - ((σ s \cdot N q) + (0.4 \cdot γ \cdot B \cdot N γ))}{(N c) \cdot (1 + 0.3 \cdot (\frac{B}{L}))}

Next Step Substitute values of Variables

∴

C = \frac{127.8kPa - ((45.9kN/m² \cdot 2.01) + (0.4 \cdot 18kN/m³ \cdot 2m \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2m}{4m}))}

Next Step Convert Units

∴

C = \frac{127800Pa - ((45900Pa \cdot 2.01) + (0.4 \cdot 18000N/m³ \cdot 2m \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2m}{4m}))}

Next Step Prepare to Evaluate

∴

C = \frac{127800 - ((45900 \cdot 2.01) + (0.4 \cdot 18000 \cdot 2 \cdot 1.6))}{(9) \cdot (1 + 0.3 \cdot (\frac{2}{4}))}

Next Step Evaluate

∴

C = 1207.82608695652Pa

Next Step Convert to Output's Unit

∴

C = 1.20782608695652kPa

LAST Step Rounding Answer

∴

C = 1.2078kPa

Cohesion of Soil given Ultimate Bearing Capacity for Rectangular Footing Formula Elements

Variables

Cohesion in Soil as Kilopascal

Cohesion in Soil as Kilopascal is the ability of like particles within soil to hold onto each other. It is the shear strength or force that binds together like particles in the structure of a soil.

Symbol: C

Measurement: PressureUnit: kPa

Note: Value should be between 0 to 50.

Formulas to find Cohesion in Soil as Kilopascal

Ultimate Bearing Capacity in Soil

Ultimate Bearing Capacity in Soil is defined as the minimum gross pressure intensity at the base of the foundation at which the soil fails in shear.

Symbol: q_fc

Measurement: PressureUnit: kPa