FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Cohesion of Soil for Local Shear Failure given Depth of Footing Formula

GoCohesion of Soil given Bearing Capacity for Local Shear Failure Formula

Fx Copy

LaTeX Copy

Cohesion in Soil as Kilopascal is the ability of like particles within soil to hold onto each other. It is the shear strength or force that binds together like particles in the structure of a soil. Check FAQs

C = \frac{q fc - (((γ \cdot D footing) \cdot N q) + (0.5 \cdot γ \cdot B \cdot N γ))}{(\frac{2}{3}) \cdot N c}

C - Cohesion in Soil as Kilopascal?q_fc - Ultimate Bearing Capacity in Soil?γ - Unit Weight of Soil?D_footing - Depth of Footing in Soil?N_q - Bearing Capacity Factor dependent on Surcharge?B - Width of Footing?N_γ - Bearing Capacity Factor dependent on Unit Weight?N_c - Bearing Capacity Factor dependent on Cohesion?

Cohesion of Soil for Local Shear Failure given Depth of Footing Example

With values

With units

Only example

Here is how the Cohesion of Soil for Local Shear Failure given Depth of Footing equation looks like with Values.

Here is how the Cohesion of Soil for Local Shear Failure given Depth of Footing equation looks like with Units.

Here is how the Cohesion of Soil for Local Shear Failure given Depth of Footing equation looks like.

1.1838 = \frac{127.8 - (((18 \cdot 2.54) \cdot 2.01) + (0.5 \cdot 18 \cdot 2 \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

1.1838kPa = \frac{127.8kPa - (((18kN/m³ \cdot 2.54m) \cdot 2.01) + (0.5 \cdot 18kN/m³ \cdot 2m \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

1.1838 = \frac{127.8 - (((18 \cdot 2.54) \cdot 2.01) + (0.5 \cdot 18 \cdot 2 \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Geotechnical Engineering » fx Cohesion of Soil for Local Shear Failure given Depth of Footing

Cohesion of Soil for Local Shear Failure given Depth of Footing Solution

Follow our step by step solution on how to calculate Cohesion of Soil for Local Shear Failure given Depth of Footing?

FIRST Step Consider the formula

C = \frac{q fc - (((γ \cdot D footing) \cdot N q) + (0.5 \cdot γ \cdot B \cdot N γ))}{(\frac{2}{3}) \cdot N c}

Next Step Substitute values of Variables

∴

C = \frac{127.8kPa - (((18kN/m³ \cdot 2.54m) \cdot 2.01) + (0.5 \cdot 18kN/m³ \cdot 2m \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

Next Step Convert Units

∴

C = \frac{127800Pa - (((18000N/m³ \cdot 2.54m) \cdot 2.01) + (0.5 \cdot 18000N/m³ \cdot 2m \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

Next Step Prepare to Evaluate

∴

C = \frac{127800 - (((18000 \cdot 2.54) \cdot 2.01) + (0.5 \cdot 18000 \cdot 2 \cdot 1.6))}{(\frac{2}{3}) \cdot 9}

Next Step Evaluate

∴

C = 1183.8Pa

LAST Step Convert to Output's Unit

∴

C = 1.1838kPa

Cohesion of Soil for Local Shear Failure given Depth of Footing Formula Elements

Variables

Cohesion in Soil as Kilopascal

Cohesion in Soil as Kilopascal is the ability of like particles within soil to hold onto each other. It is the shear strength or force that binds together like particles in the structure of a soil.

Symbol: C

Measurement: PressureUnit: kPa

Note: Value should be between 0 to 50.

Formulas to find Cohesion in Soil as Kilopascal

Ultimate Bearing Capacity in Soil

Ultimate Bearing Capacity in Soil is defined as the minimum gross pressure intensity at the base of the foundation at which the soil fails in shear.

Symbol: q_fc

Measurement: PressureUnit: kPa