FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Formula

GoCoefficient of Discharge for Time Required to Lower Liquid Surface Formula

Fx Copy

LaTeX Copy

The Coefficient of Discharge is ratio of actual discharge to theoretical discharge. Check FAQs

C d = (\frac{(\frac{2}{3}) \cdot A R}{(\frac{8}{15}) \cdot Δt \cdot \sqrt{2 \cdot g} \cdot \tan (\frac{θ}{2})}) \cdot ((\frac{1}{{h 2}^{\frac{3}{2}}}) - (\frac{1}{{H Upstream}^{\frac{3}{2}}}))

C_d - Coefficient of Discharge?A_R - Cross-Sectional Area of Reservoir?Δt - Time Interval?g - Acceleration due to Gravity?θ - Theta?h₂ - Head on Downstream of Weir?H_Upstream - Head on Upstream of Weir?

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Example

With values

With units

Only example

Here is how the Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch equation looks like with Values.

Here is how the Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch equation looks like with Units.

Here is how the Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch equation looks like.

0.6101 = (\frac{(\frac{2}{3}) \cdot 13}{(\frac{8}{15}) \cdot 1.25 \cdot \sqrt{2 \cdot 9.8} \cdot \tan (\frac{30}{2})}) \cdot ((\frac{1}{{5.1}^{\frac{3}{2}}}) - (\frac{1}{{10.1}^{\frac{3}{2}}}))

0.6101 = (\frac{(\frac{2}{3}) \cdot 13m²}{(\frac{8}{15}) \cdot 1.25s \cdot \sqrt{2 \cdot 9.8m/s²} \cdot \tan (\frac{30°}{2})}) \cdot ((\frac{1}{{5.1m}^{\frac{3}{2}}}) - (\frac{1}{{10.1m}^{\frac{3}{2}}}))

0.6101 = (\frac{(\frac{2}{3}) \cdot 13}{(\frac{8}{15}) \cdot 1.25 \cdot \sqrt{2 \cdot 9.8} \cdot \tan (\frac{30}{2})}) \cdot ((\frac{1}{{5.1}^{\frac{3}{2}}}) - (\frac{1}{{10.1}^{\frac{3}{2}}}))

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Hydraulics and Waterworks » fx Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Solution

Follow our step by step solution on how to calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

FIRST Step Consider the formula

C d = (\frac{(\frac{2}{3}) \cdot A R}{(\frac{8}{15}) \cdot Δt \cdot \sqrt{2 \cdot g} \cdot \tan (\frac{θ}{2})}) \cdot ((\frac{1}{{h 2}^{\frac{3}{2}}}) - (\frac{1}{{H Upstream}^{\frac{3}{2}}}))

Next Step Substitute values of Variables

∴

C d = (\frac{(\frac{2}{3}) \cdot 13m²}{(\frac{8}{15}) \cdot 1.25s \cdot \sqrt{2 \cdot 9.8m/s²} \cdot \tan (\frac{30°}{2})}) \cdot ((\frac{1}{{5.1m}^{\frac{3}{2}}}) - (\frac{1}{{10.1m}^{\frac{3}{2}}}))

Next Step Convert Units

∴

C d = (\frac{(\frac{2}{3}) \cdot 13m²}{(\frac{8}{15}) \cdot 1.25s \cdot \sqrt{2 \cdot 9.8m/s²} \cdot \tan (\frac{0.5236rad}{2})}) \cdot ((\frac{1}{{5.1m}^{\frac{3}{2}}}) - (\frac{1}{{10.1m}^{\frac{3}{2}}}))

Next Step Prepare to Evaluate

∴

C d = (\frac{(\frac{2}{3}) \cdot 13}{(\frac{8}{15}) \cdot 1.25 \cdot \sqrt{2 \cdot 9.8} \cdot \tan (\frac{0.5236}{2})}) \cdot ((\frac{1}{{5.1}^{\frac{3}{2}}}) - (\frac{1}{{10.1}^{\frac{3}{2}}}))

Next Step Evaluate

∴

C d = 0.610083797710571

LAST Step Rounding Answer

∴

C d = 0.6101

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Formula Elements

Variables

Functions

Coefficient of Discharge

The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.

Symbol: C_d

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.2.

Formulas to find Coefficient of Discharge

Cross-Sectional Area of Reservoir

Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.

Symbol: A_R

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area of Reservoir

Time Interval

Time interval is the time duration between two events/entities of interest.

Symbol: Δt

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time Interval

Acceleration due to Gravity

The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration due to Gravity

Theta

Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.

Symbol: θ

Measurement: AngleUnit: °

Note: Value can be positive or negative.

Formulas to find Theta

Head on Downstream of Weir

Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: h₂

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Downstream of Weir

Head on Upstream of Weir

Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: H_Upstream

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Upstream of Weir

tan

The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle.

Syntax: tan(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Coefficient of Discharge

Go Coefficient of Discharge for Time Required to Lower Liquid Surface

C d = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot Δt \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

Go Time Required to Lower Liquid Surface

Δt = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Length of Crest for time required to Lower Liquid Surface

L w = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot Δt}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

How to Evaluate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch evaluator uses Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))) to evaluate the Coefficient of Discharge, The Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch is ratio of actual discharge to theoretical discharge, i.e., ratio of mass flow rate at discharge end. Coefficient of Discharge is denoted by C_d symbol.

How to evaluate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch using this online evaluator? To use this online evaluator for Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch, enter Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) and hit the calculate button.

FAQs on Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch

What is the formula to find Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

The formula of Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch is expressed as Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))). Here is an example- 0.610084 = (((2/3)*13)/((8/15)*1.25*sqrt(2*9.8)*tan(0.5235987755982/2)))*((1/5.1^(3/2))-(1/10.1^(3/2))).

How to calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

With Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) we can find Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch using the formula - Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))). This formula also uses Tangent (tan), Square Root (sqrt) function(s).

What are the other ways to Calculate Coefficient of Discharge?

Here are the different ways to Calculate Coefficient of Discharge-

Coefficient of Discharge=((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Formula

​GoCoefficient of Discharge for Time Required to Lower Liquid Surface Formula

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Example

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Solution

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Formula Elements

Other Formulas to find Coefficient of Discharge

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

How to Evaluate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

FAQs on Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch

Variable Name

GoCoefficient of Discharge for Time Required to Lower Liquid Surface Formula