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Clausius Parameter given Reduced and Actual Parameters Formula

GoClausius Parameter given Critical Parameters Formula

GoClausius Parameter given Pressure, Temperature and Molar Volume of Real Gas Formula

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Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas. Check FAQs

a = \frac{27 \cdot ({[R]}^{2}) \cdot ({(\frac{T rg}{T r})}^{3})}{64 \cdot (\frac{p}{P r})}

a - Clausius Parameter a?T_rg - Temperature of Real Gas?T_r - Reduced Temperature?p - Pressure?P_r - Reduced Pressure?[R] - Universal gas constant?

Clausius Parameter given Reduced and Actual Parameters Example

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Here is how the Clausius Parameter given Reduced and Actual Parameters equation looks like with Values.

Here is how the Clausius Parameter given Reduced and Actual Parameters equation looks like with Units.

Here is how the Clausius Parameter given Reduced and Actual Parameters equation looks like.

787.4372 = \frac{27 \cdot ({8.3145}^{2}) \cdot ({(\frac{300}{10})}^{3})}{64 \cdot (\frac{800}{0.8})}

787.4372 = \frac{27 \cdot ({8.3145}^{2}) \cdot ({(\frac{300K}{10})}^{3})}{64 \cdot (\frac{800Pa}{0.8})}

787.4372 = \frac{27 \cdot ({8.3145}^{2}) \cdot ({(\frac{300}{10})}^{3})}{64 \cdot (\frac{800}{0.8})}

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Clausius Parameter given Reduced and Actual Parameters Solution

Follow our step by step solution on how to calculate Clausius Parameter given Reduced and Actual Parameters?

FIRST Step Consider the formula

a = \frac{27 \cdot ({[R]}^{2}) \cdot ({(\frac{T rg}{T r})}^{3})}{64 \cdot (\frac{p}{P r})}

Next Step Substitute values of Variables

∴

a = \frac{27 \cdot ({[R]}^{2}) \cdot ({(\frac{300K}{10})}^{3})}{64 \cdot (\frac{800Pa}{0.8})}

Next Step Substitute values of Constants

∴

a = \frac{27 \cdot ({8.3145}^{2}) \cdot ({(\frac{300K}{10})}^{3})}{64 \cdot (\frac{800Pa}{0.8})}

Next Step Prepare to Evaluate

∴

a = \frac{27 \cdot ({8.3145}^{2}) \cdot ({(\frac{300}{10})}^{3})}{64 \cdot (\frac{800}{0.8})}

Next Step Evaluate

∴

a = 787.437193910917

LAST Step Rounding Answer

∴

a = 787.4372

Clausius Parameter given Reduced and Actual Parameters Formula Elements

Variables

Constants

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Temperature of Real Gas

Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

Symbol: T_rg

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Real Gas

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Pressure

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Symbol: p

Measurement: PressureUnit: Pa

Note: Value can be positive or negative.

Formulas to find Pressure

Reduced Pressure

Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.

Symbol: P_r

Measurement: NAUnit: Unitless

Note: Value should be between 0 to 1.

Formulas to find Reduced Pressure

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Clausius Parameter a

Go Clausius Parameter given Critical Parameters

a = \frac{27 \cdot ({[R]}^{2}) \cdot ({T c}^{3})}{64 \cdot P c}

Go Clausius Parameter given Pressure, Temperature and Molar Volume of Real Gas

a = ((\frac{[R] \cdot T rg}{V m - b}) - p) \cdot (T rg \cdot ({(V m + c)}^{2}))

Go Clausius Parametera given Reduced and Critical Parameters using Clausius Equation

a = ((\frac{[R] \cdot (V m,r \cdot T c)}{(V m,r \cdot V m,c) - b}) - (P r \cdot P c)) \cdot ((T r \cdot T c) \cdot ({((V m,r \cdot V m,c) + c)}^{2}))

Other formulas in Clausius Parameter category

Go Clausius Parameter b given Critical Parameters

b = V c - (\frac{[R] \cdot T c}{4 \cdot P' c})

Go Clausius Parameter b given Pressure, Temperature and Molar Volume of Real Gas

b = V m - (\frac{[R] \cdot T rg}{p + (\frac{a}{T rg \cdot ({(V m + c)}^{2})})})

Go Clausius Parameter b given Reduced and Actual Parameters

b RP = (\frac{V real}{V r}) - (\frac{[R] \cdot (\frac{T rg}{T r})}{4 \cdot (\frac{p}{P r})})

Go Clausius Parameter b given Reduced and Critical Parameters using Clausius Equation

b = (V m,r \cdot V m,c) - (\frac{[R] \cdot (T r \cdot T c)}{(P r \cdot P c) + (\frac{a}{(T r \cdot T c) \cdot ({((V m,r \cdot V m,c) + c)}^{2})})})

How to Evaluate Clausius Parameter given Reduced and Actual Parameters?

Clausius Parameter given Reduced and Actual Parameters evaluator uses Clausius Parameter a = (27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*(Pressure/Reduced Pressure)) to evaluate the Clausius Parameter a, Clausius parameter given reduced and actual parameters formula is defined as empirical parameter characteristic to equation obtained from Clausius model of real gas. Clausius Parameter a is denoted by a symbol.

How to evaluate Clausius Parameter given Reduced and Actual Parameters using this online evaluator? To use this online evaluator for Clausius Parameter given Reduced and Actual Parameters, enter Temperature of Real Gas (T_rg), Reduced Temperature (T_r), Pressure (p) & Reduced Pressure (P_r) and hit the calculate button.

FAQs on Clausius Parameter given Reduced and Actual Parameters

What is the formula to find Clausius Parameter given Reduced and Actual Parameters?

The formula of Clausius Parameter given Reduced and Actual Parameters is expressed as Clausius Parameter a = (27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*(Pressure/Reduced Pressure)). Here is an example- 17.91055 = (27*([R]^2)*((300/10)^3))/(64*(800/0.8)).

How to calculate Clausius Parameter given Reduced and Actual Parameters?

With Temperature of Real Gas (T_rg), Reduced Temperature (T_r), Pressure (p) & Reduced Pressure (P_r) we can find Clausius Parameter given Reduced and Actual Parameters using the formula - Clausius Parameter a = (27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*(Pressure/Reduced Pressure)). This formula also uses Universal gas constant .

What are the other ways to Calculate Clausius Parameter a?

Here are the different ways to Calculate Clausius Parameter a-

Clausius Parameter a=(27*([R]^2)*(Critical Temperature^3))/(64*Critical Pressure)
Clausius Parameter a=((([R]*Temperature of Real Gas)/(Molar Volume-Clausius Parameter b))-Pressure)*(Temperature of Real Gas*((Molar Volume+Clausius Parameter c)^2))
Clausius Parameter a=((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2))

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Clausius Parameter given Reduced and Actual Parameters Formula

​GoClausius Parameter given Critical Parameters Formula

​GoClausius Parameter given Pressure, Temperature and Molar Volume of Real Gas Formula

Clausius Parameter given Reduced and Actual Parameters Example

Clausius Parameter given Reduced and Actual Parameters Solution

Clausius Parameter given Reduced and Actual Parameters Formula Elements

Other Formulas to find Clausius Parameter a

Other formulas in Clausius Parameter category

How to Evaluate Clausius Parameter given Reduced and Actual Parameters?

FAQs on Clausius Parameter given Reduced and Actual Parameters

Variable Name

GoClausius Parameter given Critical Parameters Formula

GoClausius Parameter given Pressure, Temperature and Molar Volume of Real Gas Formula