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Classical Analysis of Fluorescence Anisotropy Formula

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Classical Analysis of Fluorescence Anisotropy occurs when each optical field (pump or probe) interacts selectively with one transition only. Check FAQs

r a = \frac{3 \cdot ({\cos (γ a)}^{2}) - 1}{5}

r_a - Classical Analysis of Fluorescence Anisotropy?γ_a - Angle Between Transition Dipole Moments?

Classical Analysis of Fluorescence Anisotropy Example

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Here is how the Classical Analysis of Fluorescence Anisotropy equation looks like with Values.

Here is how the Classical Analysis of Fluorescence Anisotropy equation looks like with Units.

Here is how the Classical Analysis of Fluorescence Anisotropy equation looks like.

0.1 = \frac{3 \cdot ({\cos (45)}^{2}) - 1}{5}

0.1 = \frac{3 \cdot ({\cos (45°)}^{2}) - 1}{5}

0.1 = \frac{3 \cdot ({\cos (45)}^{2}) - 1}{5}

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Classical Analysis of Fluorescence Anisotropy Solution

Follow our step by step solution on how to calculate Classical Analysis of Fluorescence Anisotropy?

FIRST Step Consider the formula

r a = \frac{3 \cdot ({\cos (γ a)}^{2}) - 1}{5}

Next Step Substitute values of Variables

∴

r a = \frac{3 \cdot ({\cos (45°)}^{2}) - 1}{5}

Next Step Convert Units

∴

r a = \frac{3 \cdot ({\cos (0.7854rad)}^{2}) - 1}{5}

Next Step Prepare to Evaluate

∴

r a = \frac{3 \cdot ({\cos (0.7854)}^{2}) - 1}{5}

Next Step Evaluate

∴

r a = 0.100000000000088

LAST Step Rounding Answer

∴

r a = 0.1

Classical Analysis of Fluorescence Anisotropy Formula Elements

Variables

Functions

Classical Analysis of Fluorescence Anisotropy

Classical Analysis of Fluorescence Anisotropy occurs when each optical field (pump or probe) interacts selectively with one transition only.

Symbol: r_a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Classical Analysis of Fluorescence Anisotropy

Angle Between Transition Dipole Moments

Angle Between Transition Dipole Moments is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.

Symbol: γ_a

Measurement: AngleUnit: °

Note: Value can be positive or negative.

Formulas to find Angle Between Transition Dipole Moments

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

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Go Recoil Energy for Bond Breaking

E = (\frac{1}{2}) \cdot μ \cdot (v^{2})

Go Observed Lifetime Given Reduced Mass

τ obs = \frac{\sqrt{\frac{μ \cdot [BoltZ] \cdot T}{8 \cdot π}}}{P \cdot σ}

How to Evaluate Classical Analysis of Fluorescence Anisotropy?

Classical Analysis of Fluorescence Anisotropy evaluator uses Classical Analysis of Fluorescence Anisotropy = (3*(cos(Angle Between Transition Dipole Moments)^2)-1)/5 to evaluate the Classical Analysis of Fluorescence Anisotropy, The Classical Analysis of Fluorescence Anisotropy formula is defined as anisotropy where the characteristic of each term is that each optical field (pump or probe) interacts selectively with one transition only. Classical Analysis of Fluorescence Anisotropy is denoted by r_a symbol.

How to evaluate Classical Analysis of Fluorescence Anisotropy using this online evaluator? To use this online evaluator for Classical Analysis of Fluorescence Anisotropy, enter Angle Between Transition Dipole Moments (γ_a) and hit the calculate button.

FAQs on Classical Analysis of Fluorescence Anisotropy

What is the formula to find Classical Analysis of Fluorescence Anisotropy?

The formula of Classical Analysis of Fluorescence Anisotropy is expressed as Classical Analysis of Fluorescence Anisotropy = (3*(cos(Angle Between Transition Dipole Moments)^2)-1)/5. Here is an example- 0.1 = (3*(cos(0.785398163397301)^2)-1)/5.

How to calculate Classical Analysis of Fluorescence Anisotropy?

With Angle Between Transition Dipole Moments (γ_a) we can find Classical Analysis of Fluorescence Anisotropy using the formula - Classical Analysis of Fluorescence Anisotropy = (3*(cos(Angle Between Transition Dipole Moments)^2)-1)/5. This formula also uses Cosine (cos) function(s).

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