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Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another. Check FAQs
COPactual=T6-T5'Tt'-T2'
COPactual - Actual Coefficient of Performance?T6 - Inside Temperature of Cabin?T5' - Actual Temperature at end of Isentropic Expansion?Tt' - Actual End Temp of Isentropic Compression?T2' - Actual Temperature of Rammed Air?

C.O.P. of simple air cycle Example

With values
With units
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Here is how the C.O.P. of simple air cycle equation looks like with Values.

Here is how the C.O.P. of simple air cycle equation looks like with Units.

Here is how the C.O.P. of simple air cycle equation looks like.

0.2078Edit=281Edit-265Edit350Edit-273Edit
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C.O.P. of simple air cycle Solution

Follow our step by step solution on how to calculate C.O.P. of simple air cycle?

FIRST Step Consider the formula
COPactual=T6-T5'Tt'-T2'
Next Step Substitute values of Variables
COPactual=281K-265K350K-273K
Next Step Prepare to Evaluate
COPactual=281-265350-273
Next Step Evaluate
COPactual=0.207792207792208
LAST Step Rounding Answer
COPactual=0.2078

C.O.P. of simple air cycle Formula Elements

Variables
Actual Coefficient of Performance
Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another.
Symbol: COPactual
Measurement: NAUnit: Unitless
Note: Value can be positive or negative.
Inside Temperature of Cabin
Inside temperature of cabin is the temperature of the air inside the cabin of an air refrigeration system, which affects the overall cooling performance.
Symbol: T6
Measurement: TemperatureUnit: K
Note: Value can be positive or negative.
Actual Temperature at end of Isentropic Expansion
Actual temperature at end of isentropic expansion is the final temperature of air at the end of an isentropic expansion process in air refrigeration systems.
Symbol: T5'
Measurement: TemperatureUnit: K
Note: Value should be greater than 0.
Actual End Temp of Isentropic Compression
Actual End Temp of Isentropic Compression is the final temperature of air at the end of an isentropic compression process in air refrigeration systems.
Symbol: Tt'
Measurement: TemperatureUnit: K
Note: Value can be positive or negative.
Actual Temperature of Rammed Air
Actual temperature of Rammed Air is the temperature of air after it has been compressed and cooled in an air refrigeration system.
Symbol: T2'
Measurement: TemperatureUnit: K
Note: Value can be positive or negative.

Other Formulas to find Actual Coefficient of Performance

​Go COP of Air Cycle for given Input Power and Tonnage of Refrigeration
COPactual=210QPin60
​Go C.O.P. of simple air evaporative cycle
COPactual=210QmaCp(Tt'-T2')

Other formulas in Air Refrigeration category

​Go Energy Performance Ratio of Heat Pump
COPtheoretical=QdeliveredWper min
​Go Relative Coefficient of Performance
COPrelative=COPactualCOPtheoretical
​Go Theoretical Coefficient of Performance of Refrigerator
COPtheoretical=Qrefw
​Go Compression or Expansion Ratio
rp=P2P1

How to Evaluate C.O.P. of simple air cycle?

C.O.P. of simple air cycle evaluator uses Actual Coefficient of Performance = (Inside Temperature of Cabin-Actual Temperature at end of Isentropic Expansion)/(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air) to evaluate the Actual Coefficient of Performance, C.O.P. of simple air cycle formula is defined as the coefficient of performance of a simple air refrigeration cycle, which represents the ratio of the desired output to the required input, and is a measure of the efficiency of the refrigeration system. Actual Coefficient of Performance is denoted by COPactual symbol.

How to evaluate C.O.P. of simple air cycle using this online evaluator? To use this online evaluator for C.O.P. of simple air cycle, enter Inside Temperature of Cabin (T6), Actual Temperature at end of Isentropic Expansion (T5'), Actual End Temp of Isentropic Compression (Tt') & Actual Temperature of Rammed Air (T2') and hit the calculate button.

FAQs on C.O.P. of simple air cycle

What is the formula to find C.O.P. of simple air cycle?
The formula of C.O.P. of simple air cycle is expressed as Actual Coefficient of Performance = (Inside Temperature of Cabin-Actual Temperature at end of Isentropic Expansion)/(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air). Here is an example- 5.333333 = (281-265)/(350-273).
How to calculate C.O.P. of simple air cycle?
With Inside Temperature of Cabin (T6), Actual Temperature at end of Isentropic Expansion (T5'), Actual End Temp of Isentropic Compression (Tt') & Actual Temperature of Rammed Air (T2') we can find C.O.P. of simple air cycle using the formula - Actual Coefficient of Performance = (Inside Temperature of Cabin-Actual Temperature at end of Isentropic Expansion)/(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air).
What are the other ways to Calculate Actual Coefficient of Performance?
Here are the different ways to Calculate Actual Coefficient of Performance-
  • Actual Coefficient of Performance=(210*Tonnage of Refrigeration in TR)/(Input Power*60)OpenImg
  • Actual Coefficient of Performance=(210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air))OpenImg
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