FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Bazins Constant given Time Required to Lower Liquid Surface Formula

Fx Copy

LaTeX Copy

Bazins Coefficient is the constant value obtained by Head. Check FAQs

m = (\frac{2 \cdot A R}{Δt \cdot \sqrt{2 \cdot g}}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

m - Bazins Coefficient?A_R - Cross-Sectional Area of Reservoir?Δt - Time Interval?g - Acceleration due to Gravity?h₂ - Head on Downstream of Weir?H_Upstream - Head on Upstream of Weir?

Bazins Constant given Time Required to Lower Liquid Surface Example

With values

With units

Only example

Here is how the Bazins Constant given Time Required to Lower Liquid Surface equation looks like with Values.

Here is how the Bazins Constant given Time Required to Lower Liquid Surface equation looks like with Units.

Here is how the Bazins Constant given Time Required to Lower Liquid Surface equation looks like.

0.6021 = (\frac{2 \cdot 13}{1.25 \cdot \sqrt{2 \cdot 9.8}}) \cdot (\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}})

0.6021 = (\frac{2 \cdot 13m²}{1.25s \cdot \sqrt{2 \cdot 9.8m/s²}}) \cdot (\frac{1}{\sqrt{5.1m}} - \frac{1}{\sqrt{10.1m}})

0.6021 = (\frac{2 \cdot 13}{1.25 \cdot \sqrt{2 \cdot 9.8}}) \cdot (\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}})

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Hydraulics and Waterworks » fx Bazins Constant given Time Required to Lower Liquid Surface

Bazins Constant given Time Required to Lower Liquid Surface Solution

Follow our step by step solution on how to calculate Bazins Constant given Time Required to Lower Liquid Surface?

FIRST Step Consider the formula

m = (\frac{2 \cdot A R}{Δt \cdot \sqrt{2 \cdot g}}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Next Step Substitute values of Variables

∴

m = (\frac{2 \cdot 13m²}{1.25s \cdot \sqrt{2 \cdot 9.8m/s²}}) \cdot (\frac{1}{\sqrt{5.1m}} - \frac{1}{\sqrt{10.1m}})

Next Step Prepare to Evaluate

∴

m = (\frac{2 \cdot 13}{1.25 \cdot \sqrt{2 \cdot 9.8}}) \cdot (\frac{1}{\sqrt{5.1}} - \frac{1}{\sqrt{10.1}})

Next Step Evaluate

∴

m = 0.602075156529631

LAST Step Rounding Answer

∴

m = 0.6021

Bazins Constant given Time Required to Lower Liquid Surface Formula Elements

Variables

Functions

Bazins Coefficient

Bazins Coefficient is the constant value obtained by Head.

Symbol: m

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Bazins Coefficient

Cross-Sectional Area of Reservoir

Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.

Symbol: A_R

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Cross-Sectional Area of Reservoir

Time Interval

Time interval is the time duration between two events/entities of interest.

Symbol: Δt

Measurement: TimeUnit: s

Note: Value should be greater than 0.

Formulas to find Time Interval

Acceleration due to Gravity

The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.

Symbol: g

Measurement: AccelerationUnit: m/s²

Note: Value should be greater than 0.

Formulas to find Acceleration due to Gravity

Head on Downstream of Weir

Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: h₂

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Downstream of Weir

Head on Upstream of Weir

Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

Symbol: H_Upstream

Measurement: LengthUnit: m

Note: Value can be positive or negative.

Formulas to find Head on Upstream of Weir

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

Go Time Required to Lower Liquid Surface

Δt = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Coefficient of Discharge for Time Required to Lower Liquid Surface

C d = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot Δt \cdot \sqrt{2 \cdot g} \cdot L w}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Length of Crest for time required to Lower Liquid Surface

L w = (\frac{2 \cdot A R}{(\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot Δt}) \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})

Go Cross Sectional Area given Time required to Lower Liquid Surface

A R = \frac{Δt \cdot (\frac{2}{3}) \cdot C d \cdot \sqrt{2 \cdot g} \cdot L w}{2 \cdot (\frac{1}{\sqrt{h 2}} - \frac{1}{\sqrt{H Upstream}})}

How to Evaluate Bazins Constant given Time Required to Lower Liquid Surface?

Bazins Constant given Time Required to Lower Liquid Surface evaluator uses Bazins Coefficient = ((2*Cross-Sectional Area of Reservoir)/(Time Interval*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)) to evaluate the Bazins Coefficient, The Bazins constant given time required to lower liquid surface can be denoted as dependent on roughness of channel surface. More roughness of surface, higher is value of Bazin's Constant. Bazins Coefficient is denoted by m symbol.

How to evaluate Bazins Constant given Time Required to Lower Liquid Surface using this online evaluator? To use this online evaluator for Bazins Constant given Time Required to Lower Liquid Surface, enter Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) and hit the calculate button.

FAQs on Bazins Constant given Time Required to Lower Liquid Surface

What is the formula to find Bazins Constant given Time Required to Lower Liquid Surface?

The formula of Bazins Constant given Time Required to Lower Liquid Surface is expressed as Bazins Coefficient = ((2*Cross-Sectional Area of Reservoir)/(Time Interval*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)). Here is an example- 0.602075 = ((2*13)/(1.25*sqrt(2*9.8)))*(1/sqrt(5.1)-1/sqrt(10.1)).

How to calculate Bazins Constant given Time Required to Lower Liquid Surface?

With Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) we can find Bazins Constant given Time Required to Lower Liquid Surface using the formula - Bazins Coefficient = ((2*Cross-Sectional Area of Reservoir)/(Time Interval*sqrt(2*Acceleration due to Gravity)))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)). This formula also uses Square Root (sqrt) function(s).

Let Others Know

✖

Facebook

Twitter

Copied!

: Value
: Unit

Bazins Constant given Time Required to Lower Liquid Surface Formula

Bazins Constant given Time Required to Lower Liquid Surface Example

Bazins Constant given Time Required to Lower Liquid Surface Solution

Bazins Constant given Time Required to Lower Liquid Surface Formula Elements

Other formulas in Time Required to Empty a Reservoir with Rectangular Weir category

How to Evaluate Bazins Constant given Time Required to Lower Liquid Surface?

FAQs on Bazins Constant given Time Required to Lower Liquid Surface

Variable Name