FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Average Unit Weight of Sediment Deposit during Period of T Years Formula

Fx Copy

LaTeX Copy

Average Unit Weight of Deposit refers to the weight per unit volume of sediment material deposited in a reservoir during a specific period. Check FAQs

W av = W T1 + (0.4343 \cdot B w) \cdot (((\frac{T}{T - 1}) \cdot \ln (T)) - 1)

W_av - Average Unit Weight of Deposit?W_T1 - Initial Unit Weight?B_w - Weighted Value of B?T - Age of Sediment?

Average Unit Weight of Sediment Deposit during Period of T Years Example

With values

With units

Only example

Here is how the Average Unit Weight of Sediment Deposit during Period of T Years equation looks like with Values.

Here is how the Average Unit Weight of Sediment Deposit during Period of T Years equation looks like with Units.

Here is how the Average Unit Weight of Sediment Deposit during Period of T Years equation looks like.

15.0592 = 15 + (0.4343 \cdot 7) \cdot (((\frac{25}{25 - 1}) \cdot \ln (25)) - 1)

15.0592kN/m³ = 15kN/m³ + (0.4343 \cdot 7) \cdot (((\frac{25Year}{25Year - 1}) \cdot \ln (25Year)) - 1)

15.0592 = 15 + (0.4343 \cdot 7) \cdot (((\frac{25}{25 - 1}) \cdot \ln (25)) - 1)

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Civil » Category

Engineering Hydrology » fx Average Unit Weight of Sediment Deposit during Period of T Years

Average Unit Weight of Sediment Deposit during Period of T Years Solution

Follow our step by step solution on how to calculate Average Unit Weight of Sediment Deposit during Period of T Years?

FIRST Step Consider the formula

W av = W T1 + (0.4343 \cdot B w) \cdot (((\frac{T}{T - 1}) \cdot \ln (T)) - 1)

Next Step Substitute values of Variables

∴

W av = 15kN/m³ + (0.4343 \cdot 7) \cdot (((\frac{25Year}{25Year - 1}) \cdot \ln (25Year)) - 1)

Next Step Convert Units

∴

W av = 15000N/m³ + (0.4343 \cdot 7) \cdot (((\frac{7.9E+8s}{7.9E+8s - 1}) \cdot \ln (7.9E+8s)) - 1)

Next Step Prepare to Evaluate

∴

W av = 15000 + (0.4343 \cdot 7) \cdot (((\frac{7.9E+8}{7.9E+8 - 1}) \cdot \ln (7.9E+8)) - 1)

Next Step Evaluate

∴

W av = 15059.2399367974N/m³

Next Step Convert to Output's Unit

∴

W av = 15.0592399367974kN/m³

LAST Step Rounding Answer

∴

W av = 15.0592kN/m³

Average Unit Weight of Sediment Deposit during Period of T Years Formula Elements

Variables

Functions

Average Unit Weight of Deposit

Average Unit Weight of Deposit refers to the weight per unit volume of sediment material deposited in a reservoir during a specific period.

Symbol: W_av

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Average Unit Weight of Deposit

Initial Unit Weight

Initial Unit Weight represents the weight (mass multiplied by gravity) per unit volume of sediment deposition at the initial phase.

Symbol: W_T1

Measurement: Specific WeightUnit: kN/m³

Note: Value should be greater than 0.

Formulas to find Initial Unit Weight

Weighted Value of B

Weighted Value of B in decimal, is the weightages of sand, silt and clay samples present in fraction form.

Symbol: B_w

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Weighted Value of B

Age of Sediment

Age of Sediment is the time elapsed since the material was deposited in years.

Symbol: T

Measurement: TimeUnit: Year

Note: Value should be greater than 0.

Formulas to find Age of Sediment

The natural logarithm, also known as the logarithm to the base e, is the inverse function of the natural exponential function.

Syntax: ln(Number)

Other formulas in Density of Sediment Deposits category

Go Rough Estimation for Unit Weight of Deposit by Koelzer and Lara Formula

W T = ((\frac{p sa}{100}) \cdot (W 1 + B 1 \cdot \log 10 (T))) + ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T))) + ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))

Go Percentage of Sand given Unit Weight of Deposit

p sa = \frac{(W av) - ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T))) - ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))}{\frac{W 1 + B 1 \cdot \log 10 (T)}{100}}

Go Percentage of Silt for Unit Weight of Deposits

p si = \frac{(W av) - ((\frac{p sa}{100}) \cdot (W 1 + B 1 \cdot \log 10 (T))) - ((\frac{p cl}{100}) \cdot (W 3 + B 3 \cdot \log 10 (T)))}{\frac{W 2 + B 2 \cdot \log 10 (T)}{100}}

Go Percentage of Clay given Unit Weight of Deposit

p cl = \frac{(W av) - ((\frac{p sa}{100}) \cdot (W 1 + B 1 \cdot \log 10 (T))) - ((\frac{p si}{100}) \cdot (W 2 + B 2 \cdot \log 10 (T)))}{\frac{W 3 + B 3 \cdot \log 10 (T)}{100}}

How to Evaluate Average Unit Weight of Sediment Deposit during Period of T Years?

Average Unit Weight of Sediment Deposit during Period of T Years evaluator uses Average Unit Weight of Deposit = Initial Unit Weight+(0.4343*Weighted Value of B)*(((Age of Sediment/(Age of Sediment-1))*ln(Age of Sediment))-1) to evaluate the Average Unit Weight of Deposit, The Average Unit Weight of Sediment Deposit during Period of T Years formula is defined as the average unit weight of sediment deposit which varies over a wide range depending upon the composition, reservoir operation and consolidation undergone by the deposit over the period of T years. Average Unit Weight of Deposit is denoted by W_av symbol.

How to evaluate Average Unit Weight of Sediment Deposit during Period of T Years using this online evaluator? To use this online evaluator for Average Unit Weight of Sediment Deposit during Period of T Years, enter Initial Unit Weight (W_T1), Weighted Value of B (B_w) & Age of Sediment (T) and hit the calculate button.

FAQs on Average Unit Weight of Sediment Deposit during Period of T Years

What is the formula to find Average Unit Weight of Sediment Deposit during Period of T Years?

The formula of Average Unit Weight of Sediment Deposit during Period of T Years is expressed as Average Unit Weight of Deposit = Initial Unit Weight+(0.4343*Weighted Value of B)*(((Age of Sediment/(Age of Sediment-1))*ln(Age of Sediment))-1). Here is an example- 0.015059 = 15000+(0.4343*7)*(((788923800/(788923800-1))*ln(788923800))-1).

How to calculate Average Unit Weight of Sediment Deposit during Period of T Years?

With Initial Unit Weight (W_T1), Weighted Value of B (B_w) & Age of Sediment (T) we can find Average Unit Weight of Sediment Deposit during Period of T Years using the formula - Average Unit Weight of Deposit = Initial Unit Weight+(0.4343*Weighted Value of B)*(((Age of Sediment/(Age of Sediment-1))*ln(Age of Sediment))-1). This formula also uses Natural Logarithm (ln) function(s).

Can the Average Unit Weight of Sediment Deposit during Period of T Years be negative?

No, the Average Unit Weight of Sediment Deposit during Period of T Years, measured in Specific Weight cannot be negative.

Which unit is used to measure Average Unit Weight of Sediment Deposit during Period of T Years?

Average Unit Weight of Sediment Deposit during Period of T Years is usually measured using the Kilonewton per Cubic Meter[kN/m³] for Specific Weight. Newton per Cubic Meter[kN/m³], Newton per Cubic Centimeter[kN/m³], Newton per Cubic Millimeter[kN/m³] are the few other units in which Average Unit Weight of Sediment Deposit during Period of T Years can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

Average Unit Weight of Sediment Deposit during Period of T Years Formula

Average Unit Weight of Sediment Deposit during Period of T Years Example

Average Unit Weight of Sediment Deposit during Period of T Years Solution

Average Unit Weight of Sediment Deposit during Period of T Years Formula Elements

Other formulas in Density of Sediment Deposits category

How to Evaluate Average Unit Weight of Sediment Deposit during Period of T Years?

FAQs on Average Unit Weight of Sediment Deposit during Period of T Years

Variable Name