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Attenuation is defined as the loss of information from a signal. Check FAQs
dB=10(log10(P2P1))
dB - Attenuation?P2 - Power 2?P1 - Power 1?

Attenuation given Power of 2 Signals Example

With values
With units
Only example

Here is how the Attenuation given Power of 2 Signals equation looks like with Values.

Here is how the Attenuation given Power of 2 Signals equation looks like with Units.

Here is how the Attenuation given Power of 2 Signals equation looks like.

-10.8884Edit=10(log10(14.67Edit180Edit))
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Attenuation given Power of 2 Signals Solution

Follow our step by step solution on how to calculate Attenuation given Power of 2 Signals?

FIRST Step Consider the formula
dB=10(log10(P2P1))
Next Step Substitute values of Variables
dB=10(log10(14.67W180W))
Next Step Prepare to Evaluate
dB=10(log10(14.67180))
Next Step Evaluate
dB=-10.8884239126002dB
LAST Step Rounding Answer
dB=-10.8884dB

Attenuation given Power of 2 Signals Formula Elements

Variables
Functions
Attenuation
Attenuation is defined as the loss of information from a signal.
Symbol: dB
Measurement: SoundUnit: dB
Note: Value can be positive or negative.
Power 2
Power 2 is the amount of energy transferred or converted per unit of time from a second source of power.
Symbol: P2
Measurement: PowerUnit: W
Note: Value can be positive or negative.
Power 1
Power 1 is the amount of energy transferred or converted per unit time from the first source.
Symbol: P1
Measurement: PowerUnit: W
Note: Value can be positive or negative.
log10
The common logarithm, also known as the base-10 logarithm or the decimal logarithm, is a mathematical function that is the inverse of the exponential function.
Syntax: log10(Number)

Other Formulas to find Attenuation

​Go Attenuation given Voltage of 2 Signals
dB=20(log10(V2V1))

Other formulas in Modulation Parameters category

​Go Bit Rate
R=fsBitDepth
​Go Bit Rate using Bit Duration
R=1Tb
​Go Bit Rate of Raised Cosine Filter using Rolloff Factor
Rs=2fb1+α
​Go Bit Rate of Raised Cosine Filter given Time Period
Rs=1T

How to Evaluate Attenuation given Power of 2 Signals?

Attenuation given Power of 2 Signals evaluator uses Attenuation = 10*(log10(Power 2/Power 1)) to evaluate the Attenuation, Attenuation given Power of 2 Signals is the loss of energy due to conduction loss or multipath fading. Attenuation is denoted by dB symbol.

How to evaluate Attenuation given Power of 2 Signals using this online evaluator? To use this online evaluator for Attenuation given Power of 2 Signals, enter Power 2 (P2) & Power 1 (P1) and hit the calculate button.

FAQs on Attenuation given Power of 2 Signals

What is the formula to find Attenuation given Power of 2 Signals?
The formula of Attenuation given Power of 2 Signals is expressed as Attenuation = 10*(log10(Power 2/Power 1)). Here is an example- -10.888424 = 10*(log10(14.67/180)).
How to calculate Attenuation given Power of 2 Signals?
With Power 2 (P2) & Power 1 (P1) we can find Attenuation given Power of 2 Signals using the formula - Attenuation = 10*(log10(Power 2/Power 1)). This formula also uses Common Logarithm (log10) function(s).
What are the other ways to Calculate Attenuation?
Here are the different ways to Calculate Attenuation-
  • Attenuation=20*(log10(Voltage 2/Voltage 1))OpenImg
Can the Attenuation given Power of 2 Signals be negative?
Yes, the Attenuation given Power of 2 Signals, measured in Sound can be negative.
Which unit is used to measure Attenuation given Power of 2 Signals?
Attenuation given Power of 2 Signals is usually measured using the Decibel[dB] for Sound. Bel[dB], Neper[dB] are the few other units in which Attenuation given Power of 2 Signals can be measured.
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