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Area of X-Section using Line Losses (2-Phase 3-Wire US) Formula

GoArea of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Formula

GoArea using Resistance of Natural Wire (2-Phase 3-Wire US) Formula

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Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system. Check FAQs

A = (2 + \sqrt{2}) \cdot ρ \cdot L \cdot \frac{{(P)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

A - Area of Underground AC Wire?ρ - Resistivity?L - Length of Underground AC Wire?P - Power Transmitted?P_loss - Line Losses?V_m - Maximum Voltage Underground AC?Φ - Phase Difference?

Area of X-Section using Line Losses (2-Phase 3-Wire US) Example

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Here is how the Area of X-Section using Line Losses (2-Phase 3-Wire US) equation looks like with Values.

Here is how the Area of X-Section using Line Losses (2-Phase 3-Wire US) equation looks like with Units.

Here is how the Area of X-Section using Line Losses (2-Phase 3-Wire US) equation looks like.

0.0012 = (2 + \sqrt{2}) \cdot 1.7E-5 \cdot 24 \cdot \frac{{(300)}^{2}}{2.67 \cdot {(230 \cdot \cos (30))}^{2}}

0.0012m² = (2 + \sqrt{2}) \cdot 1.7E-5Ω*m \cdot 24m \cdot \frac{{(300W)}^{2}}{2.67W \cdot {(230V \cdot \cos (30°))}^{2}}

0.0012 = (2 + \sqrt{2}) \cdot 1.7E-5 \cdot 24 \cdot \frac{{(300)}^{2}}{2.67 \cdot {(230 \cdot \cos (30))}^{2}}

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Area of X-Section using Line Losses (2-Phase 3-Wire US) Solution

Follow our step by step solution on how to calculate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

FIRST Step Consider the formula

A = (2 + \sqrt{2}) \cdot ρ \cdot L \cdot \frac{{(P)}^{2}}{P loss \cdot {(V m \cdot \cos (Φ))}^{2}}

Next Step Substitute values of Variables

∴

A = (2 + \sqrt{2}) \cdot 1.7E-5Ω*m \cdot 24m \cdot \frac{{(300W)}^{2}}{2.67W \cdot {(230V \cdot \cos (30°))}^{2}}

Next Step Convert Units

∴

A = (2 + \sqrt{2}) \cdot 1.7E-5Ω*m \cdot 24m \cdot \frac{{(300W)}^{2}}{2.67W \cdot {(230V \cdot \cos (0.5236rad))}^{2}}

Next Step Prepare to Evaluate

∴

A = (2 + \sqrt{2}) \cdot 1.7E-5 \cdot 24 \cdot \frac{{(300)}^{2}}{2.67 \cdot {(230 \cdot \cos (0.5236))}^{2}}

Next Step Evaluate

∴

A = 0.00118349154304133m²

LAST Step Rounding Answer

∴

A = 0.0012m²

Area of X-Section using Line Losses (2-Phase 3-Wire US) Formula Elements

Variables

Functions

Area of Underground AC Wire

Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.

Symbol: A

Measurement: AreaUnit: m²

Note: Value can be positive or negative.

Formulas to find Area of Underground AC Wire

Resistivity

Resistivity is the measure of how strongly a material opposes the flow of current through them.

Symbol: ρ

Measurement: Electric ResistivityUnit: Ω*m

Note: Value can be positive or negative.

Formulas to find Resistivity

Length of Underground AC Wire

Length of Underground AC Wire is the total length of the wire from one end to other end.

Symbol: L

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Length of Underground AC Wire

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Line Losses

Line Losses is defined as the total losses occurring in an Underground AC line when in use.

Symbol: P_loss

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Line Losses

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Area of Underground AC Wire

Go Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

A = \frac{V}{(2 + \sqrt{2}) \cdot L}

Go Area using Resistance of Natural Wire (2-Phase 3-Wire US)

A = ρ \cdot \frac{L}{\sqrt{2} \cdot R}

Other formulas in Wire Parameters category

Go Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)

P loss = {((2 + \sqrt{2}) \cdot P)}^{2} \cdot ρ \cdot \frac{{(L)}^{2}}{{(V m \cdot \cos (Φ))}^{2} \cdot V}

Go Length using Volume of Conductor Material (2 Phase 3 Wire US)

L = \sqrt{V \cdot P loss \cdot \frac{{(\cos (Φ) \cdot V m)}^{2}}{ρ \cdot ((2 + \sqrt{2}) \cdot P^{2})}}

How to Evaluate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

Area of X-Section using Line Losses (2-Phase 3-Wire US) evaluator uses Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2) to evaluate the Area of Underground AC Wire, The Area of X-Section using Line Losses (2-Phase 3-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to evaluate Area of X-Section using Line Losses (2-Phase 3-Wire US) using this online evaluator? To use this online evaluator for Area of X-Section using Line Losses (2-Phase 3-Wire US), enter Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button.

FAQs on Area of X-Section using Line Losses (2-Phase 3-Wire US)

What is the formula to find Area of X-Section using Line Losses (2-Phase 3-Wire US)?

The formula of Area of X-Section using Line Losses (2-Phase 3-Wire US) is expressed as Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2). Here is an example- 0.001183 = (2+sqrt(2))*1.7E-05*24*(300)^2/(2.67*(230*cos(0.5235987755982))^2).

How to calculate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

With Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) we can find Area of X-Section using Line Losses (2-Phase 3-Wire US) using the formula - Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2). This formula also uses Cosine (cos), Square Root (sqrt) function(s).

What are the other ways to Calculate Area of Underground AC Wire?

Here are the different ways to Calculate Area of Underground AC Wire-

Area of Underground AC Wire=Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
Area of Underground AC Wire=Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)

Can the Area of X-Section using Line Losses (2-Phase 3-Wire US) be negative?

Yes, the Area of X-Section using Line Losses (2-Phase 3-Wire US), measured in Area can be negative.

Which unit is used to measure Area of X-Section using Line Losses (2-Phase 3-Wire US)?

Area of X-Section using Line Losses (2-Phase 3-Wire US) is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Area of X-Section using Line Losses (2-Phase 3-Wire US) can be measured.

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Area of X-Section using Line Losses (2-Phase 3-Wire US) Formula

​GoArea of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Formula

​GoArea using Resistance of Natural Wire (2-Phase 3-Wire US) Formula

Area of X-Section using Line Losses (2-Phase 3-Wire US) Example

Area of X-Section using Line Losses (2-Phase 3-Wire US) Solution

Area of X-Section using Line Losses (2-Phase 3-Wire US) Formula Elements

Other Formulas to find Area of Underground AC Wire

Other formulas in Wire Parameters category

How to Evaluate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

FAQs on Area of X-Section using Line Losses (2-Phase 3-Wire US)

Variable Name

GoArea of X Section using Volume of Conductor Material (2 Phase 3 Wire US) Formula

GoArea using Resistance of Natural Wire (2-Phase 3-Wire US) Formula