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Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Formula

GoArea of Unicursal Hexagram Formula

GoArea of Unicursal Hexagram given Long Diagonal Formula

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The Area of Unicursal Hexagram is defined as the total quantity of the region enclosed within the Unicursal Hexagram. Check FAQs

A = ({(d' Long(Short Diagonal) + d' Short(Short Diagonal))}^{2} \cdot \sin (\frac{π}{3})) + (2 \cdot d' Short(Short Diagonal) \cdot d' Long Diagonal)

A - Area of Unicursal Hexagram?d'_{Long(Short Diagonal)} - Longest Section of SD of Unicursal Hexagram?d'_{Short(Short Diagonal)} - Shortest Section of SD of Unicursal Hexagram?d'_{Long Diagonal} - Section of Long Diagonal of Unicursal Hexagram?π - Archimedes' constant?

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Example

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Here is how the Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal equation looks like with Values.

Here is how the Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal equation looks like with Units.

Here is how the Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal equation looks like.

154.7077 = ({(9 + 3)}^{2} \cdot \sin (\frac{3.1416}{3})) + (2 \cdot 3 \cdot 5)

154.7077m² = ({(9m + 3m)}^{2} \cdot \sin (\frac{3.1416}{3})) + (2 \cdot 3m \cdot 5m)

154.7077 = ({(9 + 3)}^{2} \cdot \sin (\frac{3.1416}{3})) + (2 \cdot 3 \cdot 5)

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Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Solution

Follow our step by step solution on how to calculate Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

FIRST Step Consider the formula

A = ({(d' Long(Short Diagonal) + d' Short(Short Diagonal))}^{2} \cdot \sin (\frac{π}{3})) + (2 \cdot d' Short(Short Diagonal) \cdot d' Long Diagonal)

Next Step Substitute values of Variables

∴

A = ({(9m + 3m)}^{2} \cdot \sin (\frac{π}{3})) + (2 \cdot 3m \cdot 5m)

Next Step Substitute values of Constants

∴

A = ({(9m + 3m)}^{2} \cdot \sin (\frac{3.1416}{3})) + (2 \cdot 3m \cdot 5m)

Next Step Prepare to Evaluate

∴

A = ({(9 + 3)}^{2} \cdot \sin (\frac{3.1416}{3})) + (2 \cdot 3 \cdot 5)

Next Step Evaluate

∴

A = 154.707658144959m²

LAST Step Rounding Answer

∴

A = 154.7077m²

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Formula Elements

Variables

Constants

Functions

Area of Unicursal Hexagram

The Area of Unicursal Hexagram is defined as the total quantity of the region enclosed within the Unicursal Hexagram.

Symbol: A

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Area of Unicursal Hexagram

Longest Section of SD of Unicursal Hexagram

The Longest Section of SD of Unicursal Hexagram is the longest section of the three sections of the short diagonal of the Unicursal hexagram.

Symbol: d'_{Long(Short Diagonal)}

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Longest Section of SD of Unicursal Hexagram

Shortest Section of SD of Unicursal Hexagram

The Shortest Section of SD of Unicursal Hexagram is the shortest section of the three sections of the short diagonal of the Unicursal Hexagram.

Symbol: d'_{Short(Short Diagonal)}

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Shortest Section of SD of Unicursal Hexagram

Section of Long Diagonal of Unicursal Hexagram

A Section of Long Diagonal of Unicursal Hexagram is a particular type of section of the longest diagonal of a Unicursal Hexagram.

Symbol: d'_{Long Diagonal}

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Section of Long Diagonal of Unicursal Hexagram

Archimedes' constant

Archimedes' constant is a mathematical constant that represents the ratio of the circumference of a circle to its diameter.

Symbol: π

Value: 3.14159265358979323846264338327950288

sin

Sine is a trigonometric function that describes the ratio of the length of the opposite side of a right triangle to the length of the hypotenuse.

Syntax: sin(Angle)

Other Formulas to find Area of Unicursal Hexagram

Go Area of Unicursal Hexagram

A = \frac{5}{6} \cdot \sqrt{3} \cdot {l e}^{2}

Go Area of Unicursal Hexagram given Long Diagonal

A = \frac{5}{6} \cdot \sqrt{3} \cdot {(\frac{d Long}{2})}^{2}

Go Area of Unicursal Hexagram given Short Diagonal

A = \frac{5}{6} \cdot \sqrt{3} \cdot {(\frac{d Short}{\sqrt{3}})}^{2}

Go Area of Unicursal Hexagram given Perimeter

A = \frac{5}{6} \cdot \sqrt{3} \cdot {(\frac{P}{2 + \frac{10}{\sqrt{3}}})}^{2}

How to Evaluate Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal evaluator uses Area of Unicursal Hexagram = ((Longest Section of SD of Unicursal Hexagram+Shortest Section of SD of Unicursal Hexagram)^2*sin(pi/3))+(2*Shortest Section of SD of Unicursal Hexagram*Section of Long Diagonal of Unicursal Hexagram) to evaluate the Area of Unicursal Hexagram, The Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal formula is defined as the total quantity of the region enclosed within the Unicursal Hexagram, calculated using sections of long diagonal and short diagonal. Area of Unicursal Hexagram is denoted by A symbol.

How to evaluate Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal using this online evaluator? To use this online evaluator for Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal, enter Longest Section of SD of Unicursal Hexagram (d'_{Long(Short Diagonal)}), Shortest Section of SD of Unicursal Hexagram (d'_{Short(Short Diagonal)}) & Section of Long Diagonal of Unicursal Hexagram (d'_{Long Diagonal}) and hit the calculate button.

FAQs on Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal

What is the formula to find Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

The formula of Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal is expressed as Area of Unicursal Hexagram = ((Longest Section of SD of Unicursal Hexagram+Shortest Section of SD of Unicursal Hexagram)^2*sin(pi/3))+(2*Shortest Section of SD of Unicursal Hexagram*Section of Long Diagonal of Unicursal Hexagram). Here is an example- 154.7077 = ((9+3)^2*sin(pi/3))+(2*3*5).

How to calculate Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

With Longest Section of SD of Unicursal Hexagram (d'_{Long(Short Diagonal)}), Shortest Section of SD of Unicursal Hexagram (d'_{Short(Short Diagonal)}) & Section of Long Diagonal of Unicursal Hexagram (d'_{Long Diagonal}) we can find Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal using the formula - Area of Unicursal Hexagram = ((Longest Section of SD of Unicursal Hexagram+Shortest Section of SD of Unicursal Hexagram)^2*sin(pi/3))+(2*Shortest Section of SD of Unicursal Hexagram*Section of Long Diagonal of Unicursal Hexagram). This formula also uses Archimedes' constant and Sine (sin) function(s).

What are the other ways to Calculate Area of Unicursal Hexagram?

Here are the different ways to Calculate Area of Unicursal Hexagram-

Area of Unicursal Hexagram=5/6*sqrt(3)*Edge Length of Unicursal Hexagram^2
Area of Unicursal Hexagram=5/6*sqrt(3)*(Long Diagonal of Unicursal Hexagram/2)^2
Area of Unicursal Hexagram=5/6*sqrt(3)*(Short Diagonal of Unicursal Hexagram/sqrt(3))^2

Can the Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal be negative?

No, the Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal, measured in Area cannot be negative.

Which unit is used to measure Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal can be measured.

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Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Formula

​GoArea of Unicursal Hexagram Formula

​GoArea of Unicursal Hexagram given Long Diagonal Formula

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Example

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Solution

Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal Formula Elements

Other Formulas to find Area of Unicursal Hexagram

How to Evaluate Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal?

FAQs on Area of Unicursal Hexagram given Sections of Long Diagonal and Short Diagonal

Variable Name

GoArea of Unicursal Hexagram Formula

GoArea of Unicursal Hexagram given Long Diagonal Formula