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Area of Frame given Inner Length, Inner Width and Vertex Diagonal Formula

GoArea of Frame given Outer Length, Inner Width and Thickness Formula

GoArea of Frame given Inner Length, Outer Width and Thickness Formula

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The Area of Frame is the total quantity of plane enclosed by the boundary of Frame. Check FAQs

A = ((l Inner + (\sqrt{2} \cdot d Vertex)) \cdot (w Inner + (\sqrt{2} \cdot d Vertex))) - (l Inner \cdot w Inner)

A - Area of Frame?l_Inner - Inner Length of Frame?d_Vertex - Vertex Diagonal of Frame?w_Inner - Inner Width of Frame?

Area of Frame given Inner Length, Inner Width and Vertex Diagonal Example

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Here is how the Area of Frame given Inner Length, Inner Width and Vertex Diagonal equation looks like with Values.

Here is how the Area of Frame given Inner Length, Inner Width and Vertex Diagonal equation looks like with Units.

Here is how the Area of Frame given Inner Length, Inner Width and Vertex Diagonal equation looks like.

116.8528 = ((9 + (\sqrt{2} \cdot 4)) \cdot (6 + (\sqrt{2} \cdot 4))) - (9 \cdot 6)

116.8528m² = ((9m + (\sqrt{2} \cdot 4m)) \cdot (6m + (\sqrt{2} \cdot 4m))) - (9m \cdot 6m)

116.8528 = ((9 + (\sqrt{2} \cdot 4)) \cdot (6 + (\sqrt{2} \cdot 4))) - (9 \cdot 6)

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Area of Frame given Inner Length, Inner Width and Vertex Diagonal Solution

Follow our step by step solution on how to calculate Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

FIRST Step Consider the formula

A = ((l Inner + (\sqrt{2} \cdot d Vertex)) \cdot (w Inner + (\sqrt{2} \cdot d Vertex))) - (l Inner \cdot w Inner)

Next Step Substitute values of Variables

∴

A = ((9m + (\sqrt{2} \cdot 4m)) \cdot (6m + (\sqrt{2} \cdot 4m))) - (9m \cdot 6m)

Next Step Prepare to Evaluate

∴

A = ((9 + (\sqrt{2} \cdot 4)) \cdot (6 + (\sqrt{2} \cdot 4))) - (9 \cdot 6)

Next Step Evaluate

∴

A = 116.852813742386m²

LAST Step Rounding Answer

∴

A = 116.8528m²

Area of Frame given Inner Length, Inner Width and Vertex Diagonal Formula Elements

Variables

Functions

Area of Frame

The Area of Frame is the total quantity of plane enclosed by the boundary of Frame.

Symbol: A

Measurement: AreaUnit: m²

Note: Value should be greater than 0.

Formulas to find Area of Frame

Inner Length of Frame

The Inner Length of Frame is the length or longest side of the inner rectangle of the Frame.

Symbol: l_Inner

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Inner Length of Frame

Vertex Diagonal of Frame

The Vertex Diagonal of Frame is the linear distance between any pair adjacent vertices of inner and outer rectangles of Frame.

Symbol: d_Vertex

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Vertex Diagonal of Frame

Inner Width of Frame

The Inner Width of Frame is the breadth or shortest side of the inner rectangle of the Frame.

Symbol: w_Inner

Measurement: LengthUnit: m

Note: Value should be greater than 0.

Formulas to find Inner Width of Frame

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Area of Frame

Go Area of Frame given Outer Length, Inner Width and Thickness

A = (l Outer \cdot (w Inner + (2 \cdot t))) - ((l Outer - (2 \cdot t)) \cdot w Inner)

Go Area of Frame given Inner Length, Outer Width and Thickness

A = ((l Inner + (2 \cdot t)) \cdot w Outer) - (l Inner \cdot (w Outer - (2 \cdot t)))

Go Area of Frame given Inner Length, Outer Width and Vertex Diagonal

A = ((l Inner + (\sqrt{2} \cdot d Vertex)) \cdot w Outer) - (l Inner \cdot (w Outer - (\sqrt{2} \cdot d Vertex)))

Go Area of Frame given Outer Length, Outer Width and Vertex Diagonal

A = (l Outer \cdot w Outer) - ((l Outer - (\sqrt{2} \cdot d Vertex)) \cdot (w Outer - (\sqrt{2} \cdot d Vertex)))

How to Evaluate Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

Area of Frame given Inner Length, Inner Width and Vertex Diagonal evaluator uses Area of Frame = ((Inner Length of Frame+(sqrt(2)*Vertex Diagonal of Frame))*(Inner Width of Frame+(sqrt(2)*Vertex Diagonal of Frame)))-(Inner Length of Frame*Inner Width of Frame) to evaluate the Area of Frame, The Area of Frame given Inner Length, Inner Width and Vertex Diagonal formula is defined as the total quantity of plane enclosed by the boundary of Frame and calculated using the inner length, inner width, and vertex diagonal of the Frame. Area of Frame is denoted by A symbol.

How to evaluate Area of Frame given Inner Length, Inner Width and Vertex Diagonal using this online evaluator? To use this online evaluator for Area of Frame given Inner Length, Inner Width and Vertex Diagonal, enter Inner Length of Frame (l_Inner), Vertex Diagonal of Frame (d_Vertex) & Inner Width of Frame (w_Inner) and hit the calculate button.

FAQs on Area of Frame given Inner Length, Inner Width and Vertex Diagonal

What is the formula to find Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

The formula of Area of Frame given Inner Length, Inner Width and Vertex Diagonal is expressed as Area of Frame = ((Inner Length of Frame+(sqrt(2)*Vertex Diagonal of Frame))*(Inner Width of Frame+(sqrt(2)*Vertex Diagonal of Frame)))-(Inner Length of Frame*Inner Width of Frame). Here is an example- 116.8528 = ((9+(sqrt(2)*4))*(6+(sqrt(2)*4)))-(9*6).

How to calculate Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

With Inner Length of Frame (l_Inner), Vertex Diagonal of Frame (d_Vertex) & Inner Width of Frame (w_Inner) we can find Area of Frame given Inner Length, Inner Width and Vertex Diagonal using the formula - Area of Frame = ((Inner Length of Frame+(sqrt(2)*Vertex Diagonal of Frame))*(Inner Width of Frame+(sqrt(2)*Vertex Diagonal of Frame)))-(Inner Length of Frame*Inner Width of Frame). This formula also uses Square Root (sqrt) function(s).

What are the other ways to Calculate Area of Frame?

Here are the different ways to Calculate Area of Frame-

Area of Frame=(Outer Length of Frame*(Inner Width of Frame+(2*Thickness of Frame)))-((Outer Length of Frame-(2*Thickness of Frame))*Inner Width of Frame)
Area of Frame=((Inner Length of Frame+(2*Thickness of Frame))*Outer Width of Frame)-(Inner Length of Frame*(Outer Width of Frame-(2*Thickness of Frame)))
Area of Frame=((Inner Length of Frame+(sqrt(2)*Vertex Diagonal of Frame))*Outer Width of Frame)-(Inner Length of Frame*(Outer Width of Frame-(sqrt(2)*Vertex Diagonal of Frame)))

Can the Area of Frame given Inner Length, Inner Width and Vertex Diagonal be negative?

No, the Area of Frame given Inner Length, Inner Width and Vertex Diagonal, measured in Area cannot be negative.

Which unit is used to measure Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

Area of Frame given Inner Length, Inner Width and Vertex Diagonal is usually measured using the Square Meter[m²] for Area. Square Kilometer[m²], Square Centimeter[m²], Square Millimeter[m²] are the few other units in which Area of Frame given Inner Length, Inner Width and Vertex Diagonal can be measured.

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Area of Frame given Inner Length, Inner Width and Vertex Diagonal Formula

​GoArea of Frame given Outer Length, Inner Width and Thickness Formula

​GoArea of Frame given Inner Length, Outer Width and Thickness Formula

Area of Frame given Inner Length, Inner Width and Vertex Diagonal Example

Area of Frame given Inner Length, Inner Width and Vertex Diagonal Solution

Area of Frame given Inner Length, Inner Width and Vertex Diagonal Formula Elements

Other Formulas to find Area of Frame

How to Evaluate Area of Frame given Inner Length, Inner Width and Vertex Diagonal?

FAQs on Area of Frame given Inner Length, Inner Width and Vertex Diagonal

Variable Name

GoArea of Frame given Outer Length, Inner Width and Thickness Formula

GoArea of Frame given Inner Length, Outer Width and Thickness Formula