FormulaDen.com

Physics Chemistry Math Chemical Engineering Civil Electrical Electronics Electronics and Instrumentation Materials Science Mechanical Production Engineering Financial Health

Apparent Magnetic Force at length l Formula

Fx Copy

LaTeX Copy

Full Length Apparent Magnetic Force is the product of Current in the coil when the length is maximum and Number of Turns of a coil. Check FAQs

H 1 = I L \cdot n

H₁ - Full Length Apparent Magnetic Force?I_L - Full Length Coil Current?n - Number of Turns per Unit Coil Length?

Apparent Magnetic Force at length l Example

With values

With units

Only example

Here is how the Apparent Magnetic Force at length l equation looks like with Values.

Here is how the Apparent Magnetic Force at length l equation looks like with Units.

Here is how the Apparent Magnetic Force at length l equation looks like.

36 = 9 \cdot 4

36A/m = 9A \cdot 4

36 = 9 \cdot 4

Tip: Use pencil ( Pencil

) icon above to edit Input Values and Units.

Calculate

Recalculate

Solution

Copy

Reset

You are here -

Home » Category

Engineering » Category

Electronics and Instrumentation » Category

Measurement of Magnetic Parameters » fx Apparent Magnetic Force at length l

Apparent Magnetic Force at length l Solution

Follow our step by step solution on how to calculate Apparent Magnetic Force at length l?

FIRST Step Consider the formula

H 1 = I L \cdot n

Next Step Substitute values of Variables

∴

H 1 = 9A \cdot 4

Next Step Prepare to Evaluate

∴

H 1 = 9 \cdot 4

LAST Step Evaluate

∴

H 1 = 36A/m

Apparent Magnetic Force at length l Formula Elements

Variables

Full Length Apparent Magnetic Force

Full Length Apparent Magnetic Force is the product of Current in the coil when the length is maximum and Number of Turns of a coil.

Symbol: H₁

Measurement: Magnetic Field StrengthUnit: A/m

Note: Value should be greater than 0.

Formulas to find Full Length Apparent Magnetic Force

Full Length Coil Current

Full Length Coil Current is the electric current flowing through a wire coil, generating a magnetic field around it. It is fundamental in electromagnets, transformers, and inductors.

Symbol: I_L

Measurement: Electric CurrentUnit: A

Note: Value should be greater than 0.

Formulas to find Full Length Coil Current

Number of Turns per Unit Coil Length

Number of Turns per Unit Coil Length refers to the ratio of the total coil turns to its length, determining the coil's magnetic field strength per unit distance.

Symbol: n

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Number of Turns per Unit Coil Length

Other formulas in Magnetic Instruments category

Go Number of Turns in Solenoid

N = \frac{H s \cdot L}{I \cdot [Permeability-vacuum]}

Go Magnetic Field of Solenoid

H s = \frac{[Permeability-vacuum] \cdot N \cdot I}{L}

Go Magneto Motive Force(MMF)

mmf = Φ \cdot R

Go Reluctance of Magnetic Circuit

R = \frac{mmf}{Φ}

How to Evaluate Apparent Magnetic Force at length l?

Apparent Magnetic Force at length l evaluator uses Full Length Apparent Magnetic Force = Full Length Coil Current*Number of Turns per Unit Coil Length to evaluate the Full Length Apparent Magnetic Force, The Apparent Magnetic Force at length l formula is defined as Magnetic force, attraction, or repulsion that arises between electrically charged particles because of their motion at length l. Full Length Apparent Magnetic Force is denoted by H₁ symbol.

How to evaluate Apparent Magnetic Force at length l using this online evaluator? To use this online evaluator for Apparent Magnetic Force at length l, enter Full Length Coil Current (I_L) & Number of Turns per Unit Coil Length (n) and hit the calculate button.

FAQs on Apparent Magnetic Force at length l

What is the formula to find Apparent Magnetic Force at length l?

The formula of Apparent Magnetic Force at length l is expressed as Full Length Apparent Magnetic Force = Full Length Coil Current*Number of Turns per Unit Coil Length. Here is an example- 207 = 9*4.

How to calculate Apparent Magnetic Force at length l?

With Full Length Coil Current (I_L) & Number of Turns per Unit Coil Length (n) we can find Apparent Magnetic Force at length l using the formula - Full Length Apparent Magnetic Force = Full Length Coil Current*Number of Turns per Unit Coil Length.

Can the Apparent Magnetic Force at length l be negative?

No, the Apparent Magnetic Force at length l, measured in Magnetic Field Strength cannot be negative.

Which unit is used to measure Apparent Magnetic Force at length l?

Apparent Magnetic Force at length l is usually measured using the Ampere per Meter[A/m] for Magnetic Field Strength. Ampere-Turn per Meter[A/m], Kiloampere per Meter[A/m], Oersted[A/m] are the few other units in which Apparent Magnetic Force at length l can be measured.

Let Others Know

✖

Facebook

Twitter

Copied!

Apparent Magnetic Force at length l Formula

Apparent Magnetic Force at length l Example

Apparent Magnetic Force at length l Solution

Apparent Magnetic Force at length l Formula Elements

Other formulas in Magnetic Instruments category

How to Evaluate Apparent Magnetic Force at length l?

FAQs on Apparent Magnetic Force at length l

Variable Name