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Angle using Load Current (2 Phase 4 Wire US) Formula

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Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit. Check FAQs

Φ = a \cos (\sqrt{2} \cdot \frac{P}{V m \cdot I})

Φ - Phase Difference?P - Power Transmitted?V_m - Maximum Voltage Underground AC?I - Current Underground AC?

Angle using Load Current (2 Phase 4 Wire US) Example

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Here is how the Angle using Load Current (2 Phase 4 Wire US) equation looks like with Values.

Here is how the Angle using Load Current (2 Phase 4 Wire US) equation looks like with Units.

Here is how the Angle using Load Current (2 Phase 4 Wire US) equation looks like.

78.1729 = a \cos (\sqrt{2} \cdot \frac{300}{230 \cdot 9})

78.1729° = a \cos (\sqrt{2} \cdot \frac{300W}{230V \cdot 9A})

78.1729 = a \cos (\sqrt{2} \cdot \frac{300}{230 \cdot 9})

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Angle using Load Current (2 Phase 4 Wire US) Solution

Follow our step by step solution on how to calculate Angle using Load Current (2 Phase 4 Wire US)?

FIRST Step Consider the formula

Φ = a \cos (\sqrt{2} \cdot \frac{P}{V m \cdot I})

Next Step Substitute values of Variables

∴

Φ = a \cos (\sqrt{2} \cdot \frac{300W}{230V \cdot 9A})

Next Step Prepare to Evaluate

∴

Φ = a \cos (\sqrt{2} \cdot \frac{300}{230 \cdot 9})

Next Step Evaluate

∴

Φ = 1.36437503282367rad

Next Step Convert to Output's Unit

∴

Φ = 78.1729310538342°

LAST Step Rounding Answer

∴

Φ = 78.1729°

Angle using Load Current (2 Phase 4 Wire US) Formula Elements

Variables

Functions

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

acos

The inverse cosine function, is the inverse function of the cosine function. It is the function that takes a ratio as an input and returns the angle whose cosine is equal to that ratio.

Syntax: acos(Number)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other formulas in Power and Power Factor category

Go Power Factor using Area of X-Section (2 Phase 4 Wire US)

PF = ((2) \cdot \frac{P}{V m}) \cdot \sqrt{ρ \cdot \frac{L}{P loss \cdot A}}

Go Power Transmitted using Area of X-Section (2 Phase 4 Wire US)

P = V m \cdot \cos (Φ) \cdot \sqrt{A \cdot \frac{P loss}{4 \cdot ρ \cdot L}}

Go Power Transmitted using Line Losses (2 Phase 4 Wire US)

P = V m \cdot \cos (Φ) \cdot \sqrt{\frac{P loss}{4 \cdot R}}

Go Power Factor using Line Losses (2 Phase 4 Wire US)

PF = \sqrt{4 \cdot (P^{2}) \cdot \frac{R}{P loss \cdot ({V m}^{2})}}

How to Evaluate Angle using Load Current (2 Phase 4 Wire US)?

Angle using Load Current (2 Phase 4 Wire US) evaluator uses Phase Difference = acos(sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*Current Underground AC)) to evaluate the Phase Difference, The Angle using Load Current (2 phase 4 wire US) formula is defined as the phase angle between reactive and active power. Phase Difference is denoted by Φ symbol.

How to evaluate Angle using Load Current (2 Phase 4 Wire US) using this online evaluator? To use this online evaluator for Angle using Load Current (2 Phase 4 Wire US), enter Power Transmitted (P), Maximum Voltage Underground AC (V_m) & Current Underground AC (I) and hit the calculate button.

FAQs on Angle using Load Current (2 Phase 4 Wire US)

What is the formula to find Angle using Load Current (2 Phase 4 Wire US)?

The formula of Angle using Load Current (2 Phase 4 Wire US) is expressed as Phase Difference = acos(sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*Current Underground AC)). Here is an example- 4478.979 = acos(sqrt(2)*300/(230*9)).

How to calculate Angle using Load Current (2 Phase 4 Wire US)?

With Power Transmitted (P), Maximum Voltage Underground AC (V_m) & Current Underground AC (I) we can find Angle using Load Current (2 Phase 4 Wire US) using the formula - Phase Difference = acos(sqrt(2)*Power Transmitted/(Maximum Voltage Underground AC*Current Underground AC)). This formula also uses Cosine (cos)Inverse Cosine (acos), Square Root (sqrt) function(s).

Can the Angle using Load Current (2 Phase 4 Wire US) be negative?

No, the Angle using Load Current (2 Phase 4 Wire US), measured in Angle cannot be negative.

Which unit is used to measure Angle using Load Current (2 Phase 4 Wire US)?

Angle using Load Current (2 Phase 4 Wire US) is usually measured using the Degree[°] for Angle. Radian[°], Minute[°], Second[°] are the few other units in which Angle using Load Current (2 Phase 4 Wire US) can be measured.

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Angle using Load Current (2 Phase 4 Wire US) Formula

Angle using Load Current (2 Phase 4 Wire US) Example

Angle using Load Current (2 Phase 4 Wire US) Solution

Angle using Load Current (2 Phase 4 Wire US) Formula Elements

Other formulas in Power and Power Factor category

How to Evaluate Angle using Load Current (2 Phase 4 Wire US)?

FAQs on Angle using Load Current (2 Phase 4 Wire US)

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