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Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

GoAngle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

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Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit. Check FAQs

Φ = a \cos (\sqrt{2} \cdot \frac{P}{I \cdot V m})

Φ - Phase Difference?P - Power Transmitted?I - Current Underground AC?V_m - Maximum Voltage Underground AC?

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Example

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Here is how the Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Values.

Here is how the Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) equation looks like with Units.

Here is how the Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) equation looks like.

78.1729 = a \cos (\sqrt{2} \cdot \frac{300}{9 \cdot 230})

78.1729° = a \cos (\sqrt{2} \cdot \frac{300W}{9A \cdot 230V})

78.1729 = a \cos (\sqrt{2} \cdot \frac{300}{9 \cdot 230})

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Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Solution

Follow our step by step solution on how to calculate Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

FIRST Step Consider the formula

Φ = a \cos (\sqrt{2} \cdot \frac{P}{I \cdot V m})

Next Step Substitute values of Variables

∴

Φ = a \cos (\sqrt{2} \cdot \frac{300W}{9A \cdot 230V})

Next Step Prepare to Evaluate

∴

Φ = a \cos (\sqrt{2} \cdot \frac{300}{9 \cdot 230})

Next Step Evaluate

∴

Φ = 1.36437503282367rad

Next Step Convert to Output's Unit

∴

Φ = 78.1729310538342°

LAST Step Rounding Answer

∴

Φ = 78.1729°

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Variables

Functions

Phase Difference

Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

Symbol: Φ

Measurement: AngleUnit: °

Note: Value should be greater than 0.

Formulas to find Phase Difference

Power Transmitted

Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.

Symbol: P

Measurement: PowerUnit: W

Note: Value can be positive or negative.

Formulas to find Power Transmitted

Current Underground AC

Current Underground AC is defined as the current flowing through the overhead ac supply wire.

Symbol: I

Measurement: Electric CurrentUnit: A

Note: Value can be positive or negative.

Formulas to find Current Underground AC

Maximum Voltage Underground AC

Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.

Symbol: V_m

Measurement: Electric PotentialUnit: V

Note: Value can be positive or negative.

Formulas to find Maximum Voltage Underground AC

cos

Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle.

Syntax: cos(Angle)

acos

The inverse cosine function, is the inverse function of the cosine function. It is the function that takes a ratio as an input and returns the angle whose cosine is equal to that ratio.

Syntax: acos(Number)

sqrt

A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number.

Syntax: sqrt(Number)

Other Formulas to find Phase Difference

Go Angle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

Φ = a \cos (\sqrt{4 \cdot (P^{2}) \cdot ρ \cdot \frac{L}{A \cdot P loss \cdot ({V m}^{2})}})

Other formulas in Wire Parameters category

Go Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

A = 4 \cdot ρ \cdot L \cdot \frac{P^{2}}{P loss \cdot ({(V m \cdot \cos (Φ))}^{2})}

Go Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

L = P loss \cdot \frac{A}{2 \cdot ρ \cdot (I^{2})}

Go Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

L = A \cdot P loss \cdot \frac{{(V m \cdot \cos (Φ))}^{2}}{4 \cdot (P^{2}) \cdot ρ}

Go Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

A = 2 \cdot ρ \cdot \frac{L}{P loss \cdot (I^{2})}

How to Evaluate Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) evaluator uses Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC)) to evaluate the Phase Difference, The Angle using Load Current (1-phase 2-wire Mid-point Earthed) formula is defined as the phase angle between reactive and active power. Phase Difference is denoted by Φ symbol.

How to evaluate Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) using this online evaluator? To use this online evaluator for Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed), enter Power Transmitted (P), Current Underground AC (I) & Maximum Voltage Underground AC (V_m) and hit the calculate button.

FAQs on Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)

What is the formula to find Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

The formula of Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) is expressed as Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC)). Here is an example- 4478.979 = acos(sqrt(2)*300/(9*230)).

How to calculate Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

With Power Transmitted (P), Current Underground AC (I) & Maximum Voltage Underground AC (V_m) we can find Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) using the formula - Phase Difference = acos(sqrt(2)*Power Transmitted/(Current Underground AC*Maximum Voltage Underground AC)). This formula also uses Cosine (cos)Inverse Cosine (acos), Square Root (sqrt) function(s).

What are the other ways to Calculate Phase Difference?

Here are the different ways to Calculate Phase Difference-

Phase Difference=acos(sqrt(4*(Power Transmitted^2)*Resistivity*Length of Underground AC Wire/(Area of Underground AC Wire*Line Losses*(Maximum Voltage Underground AC^2))))

Can the Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) be negative?

No, the Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed), measured in Angle cannot be negative.

Which unit is used to measure Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) is usually measured using the Degree[°] for Angle. Radian[°], Minute[°], Second[°] are the few other units in which Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) can be measured.

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Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula

​GoAngle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Example

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Solution

Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed) Formula Elements

Other Formulas to find Phase Difference

Other formulas in Wire Parameters category

How to Evaluate Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)?

FAQs on Angle using Load Current (1-Phase 2-Wire Mid-Point Earthed)

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GoAngle using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed) Formula