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Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters Formula

GoActual Temperature of Real Gas given Clausius Parameter a, Actual and Critical Parameters Formula

GoActual Temperature of Real Gas given Clausius Parameter b, Actual and Critical Parameters Formula

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Temperature of Real Gas is the degree or intensity of heat present in a substance or object. Check FAQs

T rg = ({(\frac{a \cdot 64 \cdot P' c}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot T r

T_rg - Temperature of Real Gas?a - Clausius Parameter a?P'_c - Critical Pressure of Real Gas?T_r - Reduced Temperature?[R] - Universal gas constant?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters Example

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Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters equation looks like with Values.

Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters equation looks like with Units.

Here is how the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters equation looks like.

250.7852 = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

250.7852K = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

250.7852 = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

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Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters Solution

Follow our step by step solution on how to calculate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters?

FIRST Step Consider the formula

T rg = ({(\frac{a \cdot 64 \cdot P' c}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot T r

Next Step Substitute values of Variables

∴

T rg = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Substitute values of Constants

∴

T rg = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6Pa}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Prepare to Evaluate

∴

T rg = ({(\frac{0.1 \cdot 64 \cdot 4.6E+6}{27 \cdot ({8.3145}^{2})})}^{\frac{1}{3}}) \cdot 10

Next Step Evaluate

∴

T rg = 250.785192655052K

LAST Step Rounding Answer

∴

T rg = 250.7852K

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters Formula Elements

Variables

Constants

Temperature of Real Gas

Temperature of Real Gas is the degree or intensity of heat present in a substance or object.

Symbol: T_rg

Measurement: TemperatureUnit: K

Note: Value can be positive or negative.

Formulas to find Temperature of Real Gas

Clausius Parameter a

Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

Symbol: a

Measurement: NAUnit: Unitless

Note: Value can be positive or negative.

Formulas to find Clausius Parameter a

Critical Pressure of Real Gas

Critical Pressure of Real Gas is the minimum pressure required to liquify a substance at the critical temperature.

Symbol: P'_c

Measurement: PressureUnit: Pa

Note: Value should be greater than 0.

Formulas to find Critical Pressure of Real Gas

Reduced Temperature

Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.

Symbol: T_r

Measurement: NAUnit: Unitless

Note: Value should be greater than 0.

Formulas to find Reduced Temperature

Universal gas constant

Universal gas constant is a fundamental physical constant that appears in the ideal gas law, relating the pressure, volume, and temperature of an ideal gas.

Symbol: [R]

Value: 8.31446261815324

Other Formulas to find Temperature of Real Gas

Go Actual Temperature of Real Gas given Clausius Parameter a, Actual and Critical Parameters

T rg = \frac{{(\frac{a \cdot 64 \cdot P' c}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}}{T' c}

Go Actual Temperature of Real Gas given Clausius Parameter b, Actual and Critical Parameters

T rg = \frac{(V c - b') \cdot (\frac{4 \cdot P' c}{[R]})}{T' c}

Go Actual Temperature of Real Gas given Clausius Parameter b, Reduced and Actual Parameters

T rg = (((\frac{V real}{V r}) - b') \cdot (\frac{4 \cdot (\frac{p}{P r})}{[R]})) \cdot T r

Go Actual Temperature of Real Gas given Clausius Parameter b, Reduced and Critical Parameters

T rg = ((V c - b') \cdot (\frac{4 \cdot P' c}{[R]})) \cdot T r

Other formulas in Actual Temperature of Real Gas category

Go Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Actual Parameters

T RP = ({(\frac{a \cdot 64 \cdot (\frac{p}{P r})}{27 \cdot ({[R]}^{2})})}^{\frac{1}{3}}) \cdot T r

Go Actual Temperature of Real Gas using Critical and Reduced Temperature

T RT = T r \cdot T' c

How to Evaluate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters evaluator uses Temperature of Real Gas = (((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))*Reduced Temperature to evaluate the Temperature of Real Gas, The Actual Temperature of real gas given Clausius parameter a, reduced and critical parameters formula is defined as the degree or intensity of heat present in the volume of real gas. Temperature of Real Gas is denoted by T_rg symbol.

How to evaluate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters using this online evaluator? To use this online evaluator for Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters, enter Clausius Parameter a (a), Critical Pressure of Real Gas (P'_c) & Reduced Temperature (T_r) and hit the calculate button.

FAQs on Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters

What is the formula to find Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters?

The formula of Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters is expressed as Temperature of Real Gas = (((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))*Reduced Temperature. Here is an example- 250.7852 = (((0.1*64*4600000)/(27*([R]^2)))^(1/3))*10.

How to calculate Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters?

With Clausius Parameter a (a), Critical Pressure of Real Gas (P'_c) & Reduced Temperature (T_r) we can find Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters using the formula - Temperature of Real Gas = (((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))*Reduced Temperature. This formula also uses Universal gas constant .

What are the other ways to Calculate Temperature of Real Gas?

Here are the different ways to Calculate Temperature of Real Gas-

Temperature of Real Gas=(((Clausius Parameter a*64*Critical Pressure of Real Gas)/(27*([R]^2)))^(1/3))/Critical Temperature For Clausius Model
Temperature of Real Gas=((Critical Volume-Clausius Parameter b for Real Gas)*((4*Critical Pressure of Real Gas)/[R]))/Critical Temperature For Clausius Model
Temperature of Real Gas=(((Volume of Real Gas/Reduced Volume)-Clausius Parameter b for Real Gas)*((4*(Pressure/Reduced Pressure))/[R]))*Reduced Temperature

Can the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters be negative?

Yes, the Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters, measured in Temperature can be negative.

Which unit is used to measure Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters?

Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters is usually measured using the Kelvin[K] for Temperature. Celsius[K], Fahrenheit[K], Rankine[K] are the few other units in which Actual Temperature of Real Gas given Clausius Parameter a, Reduced and Critical Parameters can be measured.

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